LTE Downlink Power Calculation

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ความคิดเห็น • 8

  • @hyiderali2124
    @hyiderali2124 2 ปีที่แล้ว +1

    Great Explain, Could you pls start series on CA

  • @priyadarshini1130
    @priyadarshini1130 9 หลายเดือนก่อน

    Hi, Thankyou very nicely explaned. Could you please give the spec ref for Prs=Psingle_port - 10*Log(12*Nrb) + Log(1+Pb).

  • @crystalmild
    @crystalmild 8 หลายเดือนก่อน

    At time 9:17, the example of Rho_B/Rho_A = 1.25 --> The Power of PDSCH_B in this cause should be = -2.03 dB + 18.22 right? (in TH-cam is -2.03+15.22). By the way, thank you very much for the great explanation.

  • @galziv5814
    @galziv5814 ปีที่แล้ว

    Thank you!
    Can you explain please why you add 10*log10(1+Pb) to Reference Power formula? is it just P_RS = P_singlePort -10*log10(12*Nrb)?

  • @001HouseMusic
    @001HouseMusic ปีที่แล้ว +1

    Please explain, why Ppdsch_B= 20.88mW? In the scenario when Pb=0, Pa=-3. If Pa = -3, as in first example (Pb= 1, Pa= -3) RS Power is 18.2 (66.67mWatt) not 15.2. it means Ppdsch_B should be 0.6264*66.67=41.47 mW. Right?

    • @SmartTelecomEducation
      @SmartTelecomEducation  ปีที่แล้ว

      Hi,
      The RS power formula include the value of Pb:
      Prs=Psingle_port - 10*Log(12*Nrb) + Log(1+Pb).
      in the second example Pb=0 not 1, so the value of the RS power is 15.2 for Pb=0 and 18.2 for Pb=1.
      Kind Regards,
      Smart Telecom Education

  • @mohsinashraf1098
    @mohsinashraf1098 2 ปีที่แล้ว +1

    can you please share link of that slides?