In step 4, why doesn't the sign change to a plus when subtracting the minimum NDVI value? Does the term "NDVI_min" in the formula refer to an absolute value?
Thanks for this wonderful video. Please my LST value is showing some negative values. what are the condition for obtaining a negative value considering am in the tropical zone.
I'm creating a 2023 synthetic drought map and I want to use Landsat images. So should I use Landsat 9 level 1 or level 2 images? Because as far as I know, Landsat level 2 has been processed based on level 1. Can you share more information with me? Thank you very much
Hi, I want to know whether the formula in step 6 is wrong. I mean the formula should be: LST = (BT / (1+（10.895*BT / 1.4388）* ln(E))). Also, should 𝑂𝑖 ( the correction for Band 10: 0.29) be considered in the formula in the first step? Thanks for your time!
if you use 10.895 then you should use 14388 I think it's a matter of units. As for the value 10.895 I think that's for landsat 8, it seems to be 11.5 for landsat 9 however I'm not sure about that I'll have to do some more research. EDIT: I looked it up and it says between 10.6 and 11.19 µm which means the average is 10.895 so maybe it's a mistake.
Does anyone know what units he is using at the end? I got a result of 4.05 to -36.63 despite selecting a map from July in a place with relatively hot summers.
Dear owner of this video /guys please help me, in the step 2 (convert TOA to BT), this formula BT = (K2/ (In (K1/L)+1))-273.15, how we type "In" in the raster calculator? is this same with Ln? because I use Ln and my BT result getting -25 to -48. Please for the help guys, thanks
BT = (K2/ In ((K1/L)+1))-273.15, this the right formula. see here books.google.co.in/books?id=hBZuEAAAQBAJ&pg=PA105&lpg=PA105&dq=BT+%3D+(K2/+(In+(K1/L)%2B1))-273.15&source=bl&ots=TieimX1G-1&sig=ACfU3U2XJl8rk2VNdH4Qz9zupOG9xLcIQw&hl=en&sa=X&ved=2ahUKEwi1o5KU-NCEAxUJxTgGHQT1DBQQ6AF6BAgfEAM#v=onepage&q=BT%20%3D%20(K2%2F%20(In%20(K1%2FL)%2B1))-273.15&f=false Page 105
It looks like he used level 1. You can tell from the name of the original Landsat data file name at 2:10, it starts with LC09(Landsat 9)_L1TP (level 1 terrain corrected).
You can create a new feature class (polygon) in the geodatabase, then draw your ROI by creating a feature. After that, you can clip the area with clip tool.
Thank you very much
There is an error in brightness temperature equation, this equation is correct: BT=K2/ln(k1/L+1)-273.15
In step 4, why doesn't the sign change to a plus when subtracting the minimum NDVI value? Does the term "NDVI_min" in the formula refer to an absolute value?
Thanks for this wonderful video. Please my LST value is showing some negative values. what are the condition for obtaining a negative value considering am in the tropical zone.
Kalo gitu nanti pengaruhnya ke apa kak? Keefektifan atau gimana pls jwb
i also get negative values in very dry zone so how did you correct them
I'm creating a 2023 synthetic drought map and I want to use Landsat images. So should I use Landsat 9 level 1 or level 2 images? Because as far as I know, Landsat level 2 has been processed based on level 1.
Can you share more information with me?
Thank you very much
Hi, I want to know whether the formula in step 6 is wrong. I mean the formula should be: LST = (BT / (1+（10.895*BT / 1.4388）* ln(E))). Also, should 𝑂𝑖 ( the correction for Band 10: 0.29) be considered in the formula in the first step? Thanks for your time!
hi, have you gotten answers?
if you use 10.895 then you should use 14388 I think it's a matter of units. As for the value 10.895 I think that's for landsat 8, it seems to be 11.5 for landsat 9 however I'm not sure about that I'll have to do some more research.
EDIT: I looked it up and it says between 10.6 and 11.19 µm which means the average is 10.895 so maybe it's a mistake.
Does anyone know what units he is using at the end? I got a result of 4.05 to -36.63 despite selecting a map from July in a place with relatively hot summers.
I got the same value how did you solve your problem? Can you tell me, please? any assistance would be appreciated.
Dear owner of this video /guys please help me, in the step 2 (convert TOA to BT), this formula BT = (K2/ (In (K1/L)+1))-273.15, how we type "In" in the raster calculator? is this same with Ln? because I use Ln and my BT result getting -25 to -48. Please for the help guys, thanks
I had same issue to bad you never got a response
@@jspain7690 I have the same issue
BT = (K2/ In ((K1/L)+1))-273.15, this the right formula. see here
books.google.co.in/books?id=hBZuEAAAQBAJ&pg=PA105&lpg=PA105&dq=BT+%3D+(K2/+(In+(K1/L)%2B1))-273.15&source=bl&ots=TieimX1G-1&sig=ACfU3U2XJl8rk2VNdH4Qz9zupOG9xLcIQw&hl=en&sa=X&ved=2ahUKEwi1o5KU-NCEAxUJxTgGHQT1DBQQ6AF6BAgfEAM#v=onepage&q=BT%20%3D%20(K2%2F%20(In%20(K1%2FL)%2B1))-273.15&f=false
Page 105
i have used it and got the correct results. Thank you
@@jspain7690just search the function Ln on list of matematical operetors (left on window)
Is this for level 1 products or level 2?
It looks like he used level 1. You can tell from the name of the original Landsat data file name at 2:10, it starts with LC09(Landsat 9)_L1TP (level 1 terrain corrected).
Sir how to calculate STR from Landsat data?
How you crop the area of interest from the MAP
You can create a new feature class (polygon) in the geodatabase, then draw your ROI by creating a feature. After that, you can clip the area with clip tool.
If you have polygon mask of your area, You can also use "Extract by Mask" tool for raster datasets.
your PV is WRONG. - (-) = +