There should be technically 12 routes so I think you're missing a few also it would have been a lot simpler if you just said one over six is equal to 1/2 * 1/3. You get to the answer sooner negative I
I guess you are not one of those geniuses that can solve it because your solution is wrong 😂. For example you missed 2 solutions when you said that x^3+1=0 implies x=-1. You should get 12 solutions, corresponding to the 12 corners of a regular polygon circumscribed into a circle with radius of 1. In the end, each solution can be written as e^(ik pi/6), where k is an integer between 0 and 11.
You can also do it by finding 12 complex root of 1?
There should be technically 12 routes so I think you're missing a few also it would have been a lot simpler if you just said one over six is equal to 1/2 * 1/3. You get to the answer sooner negative I
I guess you are not one of those geniuses that can solve it because your solution is wrong 😂. For example you missed 2 solutions when you said that x^3+1=0 implies x=-1. You should get 12 solutions, corresponding to the 12 corners of a regular polygon circumscribed into a circle with radius of 1. In the end, each solution can be written as e^(ik pi/6), where k is an integer between 0 and 11.
life would be easier without i's