Bro last question can be done in more easy way, calculate volume of NaOH by subtracting from 1000-20=980, Now u can calculate normality of NaOH using W/E=N*V/1000, you will get normality of NaOH=0.102N, now just place all values in N1V1-N2V2=NtVt. Just Try.
Every other videos on this topic were missing logic . They were just using formulas and solving the question without any logic. Thanks for making the concept clear.
20:32 Dai, h2so4 lai kina 98 gm lekhnu vaako? Eq. Weight ta 49 haina ra? Ani 98 lekhna ko lagi h2so4 lai 2 ley multiply garnu parcha. Tya 2 × h2so4 nai chaina. Teta ma confuse vaye kya. Esso reply gardinus na. 😊😊😊
h2so4 ko equivalent weight bhaneko 49 ho ni ta but esma only weight ho so we can do h2so4=2+32+4*16 garda 98 huncha ani in case of naoh same goes naoh=(23+16+1)*2 which is 80 gram itself
maile jati garda ne na bujheko kuro 100ml HCL lai 200ml banayo haai yeti samma thikxa 200ml lai neutralize garna 218.4ml ligyo yo ni thik xa aani jaba aayo solve ko tali tba hamle 100ml of HCL ligyeu tara 200ml lai neutralize banauna ko lagi niskeko 218.4ml kina use garey ? tyo ta 200 ml ko lagi haina ra bhanya
the concept are crystal clear thankyou for the video sir but the background music of 5 minute craft is little disturbing will you please make video without any sound just you and your concept
umm for last one if we use the normality equation formula that u gave in part one , we will get the same answer . so can we directly use that one or else...
Sir hamile jun case ma pani 1 gram equivalent of one substance = 1 gram equivalentt of another substance formula apply garna milxa . Please reply me 🎉🎉
Here V¹ is volume of HCl,which won't change even after diluting the solution...200ml volume is after dilution of solution which simply means 100ml of water was added....i.e. no change in volume of HCl just concentration matra ghatya ho!
He is the most underrated youtuber
Seriously?
16K is underrated?
Grow up
In nepal
+2 channel ko lagi yeti pani derai thulo kuro ho btw
Noone is overrated here bruh!
This is the most underrated comment i have ever seen.
@@maheshrajpandit8964 lol
@@maheshrajpandit8964 sarcasm ho? 😂👌
Your short explanation is far better than our PhD holder teachers ... appreciated❤ understood each and everything that you taught❤
Chitrakaar ???😂
First time ever i solved all of those numerical related to volumetric analysis because of you men thank you .....
Bro last question can be done in more easy way, calculate volume of NaOH by subtracting from 1000-20=980, Now u can calculate normality of NaOH using W/E=N*V/1000, you will get normality of NaOH=0.102N, now just place all values in N1V1-N2V2=NtVt. Just Try.
❤️🇳🇵
@@shishirsapkotaofficial sir hamiloi ni sikaune ho tw yasto idea
exactly...
thanks bro🖤
Normality tw 0.05 aauxa tw?
Finally found a better channel for learning... Keep it up and add more videos!
Tomorrow is my exam ... I can’t be more thankful to you ❤️❤️❤️
I am also going through same phase exam anxiety....🥲🥲
tomorrow is my exam
@@nabinbist1554 mine is coming near
@@rijan118 Best of luck boi🤞
Everything will be fine ✌️
The real definition of teacher ❤❤
Every other videos on this topic were missing logic . They were just using formulas and solving the question without any logic. Thanks for making the concept clear.
Your speciality is that you make any things very simple and easy to u derstand.
Parsi exam xa , it's helping me a lot ❤️
Yesto babal easy yr
Ailey samma bujethyena balla bujey
Ekdum underrated
You worth more than 500k subs ❤
He is the best teacher I ever see on youtube😊 literally
Yo video kina pailai paina mailye ksm sab bujye majalye garna sakchu dhanyabad ❤
your last sentence about self realization melted my heart
Khatrai bujhaunu vaxa dai . Maile sab bujheko tapaikai video baata ho . Aafno teacher baata ta yek bujhina
I am your big fan bro and l respect the way you teach. In my view you are Alakh Pandey of Nepal.
❤️💞
Before this video volumetric was nightmare 😂 thanks a lot ❤️
Thank you dai.❤❤so much tapai ko karan yoh volumetric balla bujiyo
Finally found perfect explanation of numericals.Thanks a lot❤️
Hey
Woww balla numerical ma confidence aayo thank you so much❤ 🙏🙏🙏
20:32 Dai, h2so4 lai kina 98 gm lekhnu vaako? Eq. Weight ta 49 haina ra? Ani 98 lekhna ko lagi h2so4 lai 2 ley multiply garnu parcha. Tya 2 × h2so4 nai chaina. Teta ma confuse vaye kya. Esso reply gardinus na. 😊😊😊
Maile ni tei sochirako thia🙄
@@stellayamin3394 Aee Aee. Kun clz ho timi dost ?
h2so4 ko equivalent weight bhaneko 49 ho ni ta but esma only weight ho so we can do h2so4=2+32+4*16 garda 98 huncha ani in case of naoh same goes naoh=(23+16+1)*2 which is 80 gram itself
Voli ko exam ko 1.30 hrs kasari katni sochirathey,
Jhanna aauta numerical garera jani vo❤
Haha
😅😂
Same for today
@@livewithme4334 Best wishes Dee 😍
Aba bio ma ni A+ hanna parxa
Waaa 😍😍 you make it sooo easy to understand😌 thank you soo much ❤🌱
What a method to understand...
Really 😮😮😊😊
Thankyou so much sir 😊😊😊
Brilliant videos, can u make videos according to my necessity in chapters ?
Thank you dai hjrle khatra bujayar padhau nunxa ❤️you should appreciate more 😔
Dherai dherai Dhanyabad dai....ekdumai help vayo malai ❣️❣️
Voli ko lagi ahile herdai xu
All the best 💜
Dai hajur ko explanation is good but it would be good if you remove background music ..😊
Great way of teaching dai👌
Thank you so much 😊
After 4 year it helps me sir thank u❤❤❤
Your video deserves a lots ❤️💗 thank you very much 🙏
Finally after this video buj ❤
Dai tapai le padako na bujne murkha ho tesko kaam xaina duniya ma love you dai please continue to make such videos ❣ hope for your best bro❣❣
Thank you so much dai.It is really very helpfull.♥️😍🙏🙏
You are the best sir it really helped me plz upload more vedios for this batch of students 2078 🥺 questions
Waw daju khatra yestai padauni teacher chaiyo 😉
10:19 ma E ko value kasari 10 aauxa sir plzzz cmt mai vayeni ekchoti vandinuna mailey calculate garna janina
solve hana kto 0.128-0.048=0.08\E and finally answer is 10
You are the best explainer dada💕
@@shishirsapkotaofficial boki
@@animenepal1183 boki..?🥺🙄
@@shishirsapkotaofficial Boko hos k
@@animenepal1183 Thank you for your comment Daju ❤️
@@animenepal1183 Best wishes for your exam 😊
You deserve more subscribers
how to know what will be the product of the reaction in 3 number 20:30 ? like how to predict that NaOH + H2SO4 = Na2SO4 + H20
Criss cross method bro
Double substitution method
balla ati ramro channel vetyo yarr aaba chai a plus sure .😍🤣
The fact he says "tapai haru le bujhnu vayena vane ni tyo mero galti ho."😂😂
Lots of love dai 💖💖💖💖
Thanks Ganesh bhai ❤️
Yo vanda ramro ta mailey padhai dinxu😏......
Vanera vanepar ta Mero comment mah sab risaundei reply garna aaunaxa Ani Mero cmnt viral🎉🥳
Please add more video and thank you so much. You have millions smile of dollars. ☺🤔🥰🥰
Brother, Your video is so good as your voice...❤️
Thank you Sir ,You are doing a great Job🙏🙏
maile jati garda ne na bujheko kuro 100ml HCL lai 200ml banayo haai yeti samma thikxa 200ml lai neutralize garna 218.4ml ligyo yo ni thik xa aani jaba aayo solve ko tali tba hamle 100ml of HCL ligyeu tara 200ml lai neutralize banauna ko lagi niskeko 218.4ml kina use garey ? tyo ta 200 ml ko lagi haina ra bhanya
oi reply gara na kosaile ma marna lagisake
:(
Maile ni yehi nabujeko
khai initial concentration nai chaincha hola
the concept are crystal clear thankyou for the video sir but the background music of 5 minute craft is little disturbing will you please make video without any sound just you and your concept
20:00 ma tyo H2So4 ko value 98 GM kasari vayo. Atomic weight *2 k Karan le gareko ho
No bro.
Ramro sanga calculate gara na.
2+32+16*4=98
Thank you so much for this one it helped alot❤️
my favourite youtuber❤️💥
sir hjrko age kati ho thapauna milxa😁😚
Thank you so much sir ..your way of teaching is best ..I understand everything..
This makes me too happy 😊
thank you too 😍
last ko bujhena
I understood bro..👍
Your teaching✍️ method is very excellent..👌
Thankyou so much. Yo aarko sound lay disturb garyok Malai matra hoki hjur haru lai pani ho
20:37 ma eq wt chaidaina tesailey 98gm lekheko ho?
At 9:32 hamile dilute to 200ml garepaxi ta v1=200ml linu parne hoina ra?
umm for last one if we use the normality equation formula that u gave in part one , we will get the same answer . so can we directly use that one or else...
Best channel guys
found the best channel ..... thank you so muchhhhh:)
Glad you enjoyed 😊😊
Wooooooow . This is a life saver
Sir hamile jun case ma pani 1 gram equivalent of one substance = 1 gram equivalentt of another substance formula apply garna milxa . Please reply me 🎉🎉
wow wow love you from america
Keep it up...
Bro its helping me a lot..
Thanks
Please check out other videos too 😊
Love you bro
You are a saviour🔥❤️
Your explanation just awesome
Thank you so much 😊😊
This video was very useful😌
Happy to help you 😊
Well done bro
Lots of thanks, please go on for other video
Supportive 👍
Thank you so much♥️♥️
Majala bujhe bro🥰🥰🥰
Thank u sooooo much sir............LOts of love from Dharan
Tq♥️♥️♥️♥️♥️
Clear concept
Mention not 🙂
It helped a lot!❤🌻
a lotttt thanks bro..❤🎉
Thanks A lot Dai 🔥💯😊❤️
really this video
helps alot
superb dai😀
what if volume of hcl ,naoh are given in cc
Thankyou bro its helping me alot😊
Last question lai total gram eq = gram eq of acid - gram eq of base gara milxa ki mildai na ??
Tesari ni aaudai raixatw
Milxa milna ta tarw g/ltr nikalni bela ma normality*eq wt garna parxa teti bela eq wt kasko rakhni thahudaina tei vayera
Excellent explanation.love you bro ❤😘
Why so underrated 🙃
It helps a lot brother to me .
Everything on point but could you please remove the bgm , it kinda disturbs.
Understood sir👍
9:32 ma V1 KO value kina 200 narakheko ??
Kinaki 200 ml maa ta metal pani mixed xa. Hope you got it
no metal ta 100 ml ma dissolved gariyeko xa
Here V¹ is volume of HCl,which won't change even after diluting the solution...200ml volume is after dilution of solution which simply means 100ml of water was added....i.e. no change in volume of HCl just concentration matra ghatya ho!
2080batch, Thankyou sir
Next time please silent the background... it’s distracting.... u teach well ... u need don’t background music...😊its a request
huss, thank you
Thank you bro ❤️ 😊 u really help me
Thank you so much dada i can solve this portion in my upcoming 12 th board
I understood everything 😊
Thank u so much
Happy to help you 😊
very useful for me tq soo much pathsala
Glad to help you 😊
Achha hai achha hai⚗️💟
Keep it up bro
Good job ❤️
Thank you so much dai...kei garda ni bujeko thina...hajur le bujaidinu vayo
Got it !! Thanks a lot brother !!
Bujiyo its really helpful
Thank uh so much🙏❤️❤️❤️
Please share with your friends too 😊 😊
100ml of xN naoh solution is reacted completely with y ml of 0.1M h2so4 solution and 14.2 gm of na2so4 is produced .find the value of x and y