Introduction to Fourier Optics

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  • เผยแพร่เมื่อ 9 ก.ย. 2024

ความคิดเห็น • 18

  • @haya4895
    @haya4895 8 หลายเดือนก่อน

    that was one of the best explanations of Fourier optics! It is sad that you did not continue. Thank you very much.

  • @aasimpatel53
    @aasimpatel53 7 ปีที่แล้ว +6

    Please make more of these. This is fantastic. I think if you make more university level advanced physics lectures, you should be able to get a lot of viewers. I am completely in support of university level physics material and there definitely needs to be more of these kind of videos for students who are visual learners and don't like reading textbooks and notes that much. Please do a full playlist on Fourier Optics. Thanks.

    • @JordanEdmundsEECS
      @JordanEdmundsEECS 5 ปีที่แล้ว +1

      I also want to see more of these. In the meantime, I'm making my own: th-cam.com/video/X1PcupzuBm0/w-d-xo.html

  • @declanwk1
    @declanwk1 2 ปีที่แล้ว +1

    thank you for this brilliant video, very clear. If at the beginning of your video, you had said that you would show with just a few lines of algebra, that the pattern on the screen was the fourier transform of the aperture function, you would have upset people who don't like spoilers, but I was wondering where it was all going right up until the end

    • @haya4895
      @haya4895 8 หลายเดือนก่อน

      completely agree

  • @Maverick55555
    @Maverick55555 4 ปีที่แล้ว +1

    Thanks for the Excellent course!

  • @Yaquinito
    @Yaquinito 3 ปีที่แล้ว +1

    excellent video. Thx

  • @MajuKuriakose
    @MajuKuriakose 6 ปีที่แล้ว +2

    Well explained. Thank you

  • @comment8767
    @comment8767 หลายเดือนก่อน

    Brrrrravo!

  • @QuintinMassey
    @QuintinMassey 2 หลายเดือนก่อน

    21:36 Shouldn’t it be E0(y) “E not of little wye” now since you simplified the equitation?

  • @DW-iq8lt
    @DW-iq8lt 4 ปีที่แล้ว +1

    Thank you.

  • @onnobo7859
    @onnobo7859 4 ปีที่แล้ว +1

    Thanks!

  • @QuintinMassey
    @QuintinMassey 2 หลายเดือนก่อน

    23:18 is this where quantum optics steps in?

  • @mightbin
    @mightbin 6 ปีที่แล้ว +1

    a little jump around 23:00,otherwise perfect

  • @JordanEdmundsEECS
    @JordanEdmundsEECS 5 ปีที่แล้ว +4

    I love this video! And was sad to see it is the only one on this channel. (Shameless plug incoming) - I am making a more complete Fourier optics playlist: th-cam.com/video/X1PcupzuBm0/w-d-xo.html

    • @parameshwarhazra2725
      @parameshwarhazra2725 3 ปีที่แล้ว

      I love your videos sir. All Your presentations in dark mode is very enjoyable. Love it. ❤️❤️

  • @vishnuunni.c9802
    @vishnuunni.c9802 5 ปีที่แล้ว

    i dont understand how ky = k sin theta
    The theta defined is a contant for a point, and the wave from differet parts of the sllit has different values for the ky

    • @v.vigneshvenkatasubramania3456
      @v.vigneshvenkatasubramania3456 5 ปีที่แล้ว +2

      I can put his explanation in a different way:
      The thing is that you should NOT be considering ky to be defined for every part of the slit. the location Y of the point on the screen far way is a fixed value with respect to the origin. The origin is located at a single fixed point on the aperture. The multiplication of the k of the wave which is a fixed value irrespective of the location on the aperture, to the Y, which is also a fixed value, and to the R which is also fixed, yields a fixed ky. This is the definition of ky.
      Going back to his explanation:
      Not that for every point on the slit you take the sin theta and multiply with k to get ky. No. You take the theta only from the origin, and k*sin of this theta is always a constant.
      In conlusion, you can see that before introducing ky, the factor k*Y/R was always a constant. He is replacing the factor by a convenient notation called ky. Thats all he is actually doing. Does not matter anything else.
      Hope that answers the question. Please point out any mistake.