Math Olympiad | Wonderful Exponential Problem | VIJAY Maths

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[@dinlendiricidrtv]

Thank you very much my dear friend,

[@dongdongjoe3911]

It’s easy question, but difficult because of big number.

[@crazyindianvines1472]

Great problem & explanation

[@NadiehFan]

Exactly. The key to factoring the equation as (t − 666)(t + 667) = 0 is right in front of his nose once he gets 444222 = 6v(6v + 1) with v = 111 because we need to find to numbers with sum 1 and product −444222 and these can then only be −6v = −666 and 6v + 1 = 667. But he didn't see that.

[@BN-hy1nd]

Come on bro!! You wouldn't have known that until he has done all the hard work. His painstaking method is brilliant.

[@geralynpinto5971]

Neat and clear explanation. Ingenious solution. Many thanks as I have learnt much from you.

[@HarshColby]

You could have stopped at T(T+1) = 6V(6V+1); obviously the same by substitution.

[@superiorlyrics8326]

👏👏

[@Jiuge2004]

666 and -667

[@sumit-mn6ys]

Nice one 👍

[@dimitriskontoleon6787]

3:25
t²+t=t(t+1) =6v(6v+1) so t=v=666. Why all this math's later?
And when the one solution was 666, the other one must be - 667

[@res5139]

Awesome!!!

[@vijaymaths5483]

Thanks a lot ⚘️

[@sr6424]

I solved this in seconds. T^2 + T is equivalent to T(T + 1) which is approximately T^2 . The SQRT(444222) is between 600 and 700. Then factorise - obviously divisible by 111. This gives 4002. Then divide by 6 which gives 666 which is between 600 and 700.

[@SurreyMuso]

Just use t^2 + t = (6v)^2 + 6v

[@BN-hy1nd]

Brill, thank you

[@jaggisaram4914]

-167 , 166

[@KeithAllen-pg8ep]

Done in less than 30 seconds: 444222 = 222 x 2001 = 222 x 3 x 667 = 666 x 667 => (t - 666)(t + 667) = 0.
Thus t = 666 or -667.

[@derwynparry2939]

6v(6v+1) gives 666 x 667
t(t+1) = 444222 = 666 x 667
The product of two consecutive numbers is 666 x 667.
Hence t = 666

[@asimov2144]

i don't understand why you spend almost 4 min to find the solutions. at 3:48 if you replace V with 111. you can directly check that the factorisation is (t+667) * (t-666) !!!

[@vijaymaths5483]

अरे भैया मुझे ख्वाब नहि पडा था की इस प्रश्न का उत्तर 666 & - 667 है

[@nantesloire]

​​@@vijaymaths5483 چی میگی ؟ مگر فرمول ساده حل معادله درجه دوم را هنوز نمی شناسی ؟ ax² + bx + c = 0

[@padraiggluck2980]

Hint: t*(t + 1) so nearly the square root.