Tutorial 1-How to chose filter capacitor for power supply In tamil,design filter cap
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- เผยแพร่เมื่อ 20 ก.ย. 2024
- in this video I'll teach about filter capacitor design in tamil.
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DETAIL EXPLANATION OF FORMULA
Q = C * V, C = capacitance in farads, Q = charge in coulombs, V = voltage potential
Q = I * T, I = current flow in amps, Q = charge in coulombs, T = time in seconds
F = 1 /T, F = frequency in hZ, T = period in seconds
Therefore,
I * T = C * V, or C = (I * T) /V
The delta “Δ” symbol indicates a change, such as a change in voltage or a change in time
C = I * ΔT / ΔV
In this case, ΔT = 1 /F e.g. the time period of a 50hZ waveform = 1 /50hZ = 0.02seconds
Therefore,
C = I / (ΔV * F)
Now including the 70% factor we get the final relationship:
C = 0.7 * I /(ΔV * F)
C = capacitance in farads, I = current in amps, ΔV = peak-to-peak ripple voltage, F = ripple freq in hZ
Note that ripple frequency in a full-wave rectifier is double line frequency. For half-wave rectification, the ripple frequency is the line frequency.
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Very good explanation
super gokul. nalla panirika
Very very nice 🎉
Thanks a lot 😊
Thalaiva nee yen vedio podala pls vedio podu thala yenaku electronic rompa pudikum ana unna mathiri solrathukkuthan alu illa neraya youtupers yeppudi work pannuthunnu solvanga new mattuthan value varaikum yeppudi design panrathunnu solli erukka
Nyc explanation...Do more videos.....
Very soon
Congratz gokul
Good start all the best👍
Super bro .keep it up. Semma try bro.
Super super 👌 explanation, sir.
It's very nice way to explain about the choosage of capacitors.
Kindly put video for IC choosage in PCB circuit sir.
Thank you for your explanation 😊.
Sure I will
I am waiting for that one sir
Very good 👍👍
Super da keep going 🙌🥰
keep going bruh😉
Super explanation sir.
Thank you brother
Diode drop based on load only ya
Nice video nanba
Pls comeback
Intha month la irunthu continue va video podran nanba
@@minnanuviyal6175 🔥👍
I need to supply 1.8-to 1.9 A current from 12v battery to 11w bldc table fan that uses 6v rechargeable lead acid battery with max 4.5 A current carrying capacity. It also works on 220v AC direct power supply. The fan has a solar dc socket which can take power from PV panel through above battery. The question is how to reduce 12v battery voltage to 6v to run the fan on solar panel using sunlight?
Output peak voltage for full wave rectifier (12x1.4)-1.4.
0.7 ?
Hi sir your video is good and send your email id plies I have some doubt
How can I help you?