ME 274: Dynamics: Chapter 17.1

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  • เผยแพร่เมื่อ 6 ก.พ. 2025

ความคิดเห็น • 7

  • @CloudExile1
    @CloudExile1 6 ปีที่แล้ว +10

    pretty sure that the radius on example 2 is 100mm, and the length is 450mm so it should be 100 + 450=550

    • @ColinSelleck
      @ColinSelleck  6 ปีที่แล้ว +3

      You are correct. Good catch! The MOI of the sphere about point O is 4.5975kg m^2. Tot MOI is 5.2725 kg m^2.

  • @joshuacharlery5826
    @joshuacharlery5826 4 ปีที่แล้ว

    For a thin circular disk, shouldn't the mass moment of inertia about the y axis be (1/4)mr^2

    • @joshuacharlery5826
      @joshuacharlery5826 4 ปีที่แล้ว

      The moment of inertia is of a cylinder about its longitudinal axis is (1/2)mr^2. Since the height is not involved in this formula, the disk itself can be thought of as a cylinder.

    • @ColinSelleck
      @ColinSelleck  4 ปีที่แล้ว +1

      @@joshuacharlery5826 The MoI of a thin disk about an axis perpendicular to the disk is 1/2 M r^2. hyperphysics.phy-astr.gsu.edu/hbase/tdisc.html

  • @husnainhyder6713
    @husnainhyder6713 5 ปีที่แล้ว +1

    Please can you explain why we are doing 1/2mr^2 first what is the logic?

    • @ColinSelleck
      @ColinSelleck  5 ปีที่แล้ว +1

      The MOI of a flat disk is 1/2 m r^2.