CBR Value Calculations of Soil according to ASTM D1883|CBR Test Graph Correction
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- เผยแพร่เมื่อ 25 ส.ค. 2024
- In this video, we are going to learn how to apply the CBR corrections and calculate the corrected CBR value of soil from Load versus penetration curve according to ASTM D1883. In this example we will learn the following
1) Plot CBR graph from Load versus Penetration Value
2) Apply the CBR corrections to get the corrected CBR Value of Soil
3) Calculate the CBR value at Maximum Dry Density of Soil
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I should pay you my university's fee. Even, in my university didn't provides examples.
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Nice Video. Good explanation! 👍
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Great work
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Very nice video
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very well explained.
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Good class👍👍
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Please send us an excel sheet representing these calculations of the California tolerance percentage for this sample
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Nice video ❤️❤️❤️
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@@MasterCivilEngineering Our group has been able to obtain 1cm in-situ survey data up to 25m.
The data has already been published in JGS.
Data on locations where soil samples are difficult to obtain.
We have measured up to the level of weathered rock.
How to handle singularities in data reduction?
We have determined C,φ by confirming and discussing the same soil strata.
thank you. I'll study more.
In my case Three point soaked CBR
For 10 blow CBR % at 5mm is greater than 2.5 mm
I used CBR % of 5 mm
While for blow 25 and 56
The CBR% of 2.5 mm is greater than of 5 mm. Which value should I use ????
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For 10 Blows, use CBR at 5 mm and for 25 and 56 Blows use CBR at 2.5 mm
Find Maximum Dry Density for each No. of Blows and Then Draw a graph between CBR and MDD as explained in the video
After that, find CBR at Percentage of MDD which you will achieve in field with compaction. That will be your CBR value for Road Design
@@MasterCivilEngineering Can you provide your contact WhatsApp plz
Which dry density uses whether unsoaked or soaked dry density for plotting in the graph relation between dry density and CBR values.
For simulating worst conditions we should use 4 days soaked samples for CBR testing.
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Ich wünsche Ihnen eine schöne Zeit🇩🇪🇩🇪🇩🇪🇩🇪🇩🇪🇩🇪
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where does the 13.44 and the 20.06 come from?
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13.44 kN and 20.06 kN are the loads required at penetration of 2.5 mm and 5 mm respectively for standard crushed aggregates.
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Where these 13.44 & 20.06 standard value is come from i mean the standard value is 70.35 and 105.53 my question is that from what calculation we get these values??
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Standard load values are 1370 kg and 2055 kg or standard pressure is 70 kg/cm^2 and 105 kg/cm^2
is the standard value given in the question? or do we need to calculate by ourselves?
and why do we use 2.54mm and 5.08mm for penetration?
thankyou in advance ( ◕ᴗ◕✿ )
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Standard load is same for all materials and is taken as 13.44 kN for 2.54 mm penetration and 20.06 kN for 5.08 mm penetration respectively
What if am using 2.5 and 5.0 as my penetration
Thank you😂
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