this question misled all students...

If you're reading this ❤️. What do you think about this problem?
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‪@higher_mathematics‬
#maths #math

[@patriciaceli1536]

Nice!

[@mxrvvn]

Nice one!

[@thenationalist8845]

I got it in 15 seconds through vedic mental calculations
Edit.
Vedic maths is ancient system of calculation in ancient India

[@Patrik6920]

Nice, -but its unfourtunetly wrong..-
ex: 4^4^4 means 4^(4^4)=4^256 NOT (4*4*4*4)^4
√(4^256) = 4^(256/2) = 4^128 NOT 4^16
√(20^20^20) means 20^( (20^20)/2) [20^52428800000000000000000000]
NOT 20^10^20
NOT 20^20^10
-NOT 20^(10*20^19)- *_incorrect statement_*
AND NOT 20^10 * 20^19
Correction as suggested the corect value is 20^(10*(20^19))
wich is equal to 20^(52 428 800 000 000 000 000 000 000)
..i keept the rest for educational purposes, its easy to do mistakes with nested exponents .. the example with 4's as an example as it also easy to check...
4^4^4 means 4^(4^4) = 4^( (2^4)(2^4) ) = 4^( (16)(16) ) = 4^256
√(4^4^4) = 4^( (2^4)(2^4)/2) = 4^( (2^3)(2^3)2) = 4^(2(4^3)) = 4^(2(64)) = 4^128
explanation: √(a^b^c) = a^( (b^c)/2) = a^( ( ( b/2)^c )( ( b/2)^c) )/2 ) ->
a^( ( (b/2)^c )( (b/2)^(c-1) ) ) ->
a^( ( (b/2)^(c-1) )( (b/2)^(c-1)(b/2) ) ) ->
a^( ( b^(c-1)(b/2) ) )
a=4, b=4, c=4 give 4^( (4^3)2 ) = 4^128
...a note: for clarification use parenteses

[@thenationalist8845]

​@@Patrik6920look what I did
It is
(20^(20^20))^1/2
= 20^((20^20)/2)
=20^(((2^20)*(10^20))/2)
= 20^((2^19)*(10^20))
=20^((2^19)*(10^19)*10)
= 20^((20^19)*10)
Formal method

[@thenationalist8845]

@@Patrik6920 correct urself
The answer given by the video creator is right
Value of (20^19)*10
Is the same as the number u provided

[@Patrik6920]

@@thenationalist8845 thats correct...

[@thenationalist8845]

@@Patrik6920 yep 👍
Mentally it can be done just by jumping some values

[@OneTrueBadShoe]

if my intuition is right it's c
[ edt ]
Awesome video

[@johnchastain7890]

The problem is with the notation. A correct answer could also be 20^(20*20*1/2), or 20^(20*10)

[@zihaoooi787]

it's a fact of rule that exponentiation always works from bottom to top. there's no ambiguity here.

[@AbbasGuclu-jn3po]

a

[@Iloveminecraftverymuch]

b

[@mxrvvn]

​@@Iloveminecraftverymuchc

[@Iloveminecraftverymuch]

@@mxrvvn d

[@nezz0r]

sqrt(20^20^20)
20^20 = x
sqrt(20^x)
(20^x)^(1/2)
20^(x/2)
20^((20^20)/2) =20^((20 * 20^19) /2) = (20^10*20^19)