Thank you. I've learned a lot from you videos. The sound is clear, your accent is very understandable and the way you explain helps with writing apps that use the algorithms. Great job!
Just a quick thanks, I've been reading through Sipser as part of a fundamentals of computer science course, and these examples really helped me get a grasp of converting from NFAs to DFAs. Appreciate it!
Trust me when I say that I don't even bother looking at other TH-cam channels when it comes to the Theory of Computation. The explanation is very clear here. I love it.
are there like two methods? I saw one method in which there was one extra step of removing the edge and if the vertex1 is initial and vertex 2 is not then we make vertex 2 as initial. in that method the answer is different and I don't know why the answer is different
Epsilon (also commonly referred to as lambda) is NOT a symbol. It doesn't mean empty symbol. It's a string, and it is the reason why the set of symbols for a language will never include epsilon (a.k.a. lambda). Regardless, this is the best video for this topic.
yeah, epsilon is an empty string. But, I don't think its ever referred to as "lambda" too. Epsilon definitely is included in a language, as an example you can consider a language 'L' that accepts strings formed with an equal length of 0s and 1s from the alphabet {0,1}. One of the simplest possible stings you can form is: no string at all--Epsilon.
In this example, must make states A, B, C all initial states! the rules for that: pre = pre input, post = post input If q state includes a final state in its E*_pre then make q final. If an initial state exists in E*_pre of q state then make q initial.
in the input output table(0,1), would you only include states that have epsilon? For example, if A did not have an epsilon and went on 1, would you include that in the table.
The best thing for the instructor to do would be to start from scratch with the rendering of this state machine and describe the various layers. Then provide the solution. He understands the syntax but we do not.
All you need to know is the notation and syntax. I see a, b, and c but do these circles definitively represent distinct states? Just depends on the grammar, etc: ahhh..::according to our instructor yes they do. Kewl!! Not as hard as it seems.
Can't we use only 1 arrow for transitions between 1 pair of states on both input? For ex: why don't use just one arrow for inputs 0 and 1 from A state to B state?
Can't the NFA finally obtained be minimized to just one accepting state with a self loop at any input? Since this one is also going to accept any input string to it due to all the states being accepting.
please, if i have 2 states q1 and q2,q2 is not final state, and there is epsilon transition between them and i have not another transition with q2 , what is the rule?
create a transition table, write all the transitions, you will get sets of states for each transition, make these sets a new state define the transitions for these states, repeat the process till there are no new states and all transitions are defined. Use the table to construct a DFA.
Watching after 7 yrs
7 yrs 7 months
Your videos are the greatest series in Automata theory.
Nice explanation
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Kewl
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Thank you. I've learned a lot from you videos. The sound is clear, your accent is very understandable and the way you explain helps with writing apps that use the algorithms. Great job!
Holy Moly! I was struggling for about half an hour on this, thanks man your method is absolute.
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Just a quick thanks, I've been reading through Sipser as part of a fundamentals of computer science course, and these examples really helped me get a grasp of converting from NFAs to DFAs. Appreciate it!
Trust me when I say that I don't even bother looking at other TH-cam channels when it comes to the Theory of Computation. The explanation is very clear here. I love it.
watching it an hour before exam
Rest in peace my G🤍
This method is amazing! Much better than our lecture told.
are there like two methods? I saw one method in which there was one extra step of removing the edge and if the vertex1 is initial and vertex 2 is not then we make vertex 2 as initial. in that method the answer is different
and I don't know why the answer is different
As of my knowledge B should also be initial state and edge A to B should be label as only 1 as I saw in other method
THANK YOU VERY MUCH FOR THIS VIDEO. THIS LITERALLY HELP ME A LOT ON MY PAPER
Epsilon (also commonly referred to as lambda) is NOT a symbol. It doesn't mean empty symbol. It's a string, and it is the reason why the set of symbols for a language will never include epsilon (a.k.a. lambda). Regardless, this is the best video for this topic.
yeah, epsilon is an empty string. But, I don't think its ever referred to as "lambda" too. Epsilon definitely is included in a language, as an example you can consider a language 'L' that accepts strings formed with an equal length of 0s and 1s from the alphabet {0,1}. One of the simplest possible stings you can form is: no string at all--Epsilon.
@@iflowlikewater Lambda being used instead of epsilon is not uncommon it isn't a matter of opinion.
Watching it on the day of the exam. Thanks for the work.
Always making great videos !! as a student I find these videos extremely helpful.
Another great lesson! Thank you for this!
very well explained the concepts of epsilon NFA , thank you
Thank you very much! I understand much better, now!
thank you . your explanation was precise and clean
Brilliant! Thank you
Great teacher. my teacher plays your videos in lectures
Your video is solve every automata theory
wow
Thank you so much Neso Academy
Everything is well understood.
😀❤️❤️❤️
so much better than my teacher's explanation
Thank you for your lectures and effort.
In this example, must make states A, B, C all initial states! the rules for that: pre = pre input, post = post input
If q state includes a final state in its E*_pre then make q final.
If an initial state exists in E*_pre of q state then make q initial.
there must be only one initial state
Words can't describe the love I want to give to this man
Superb explanation sir. Thank you very much......
ALLAH BLESS you. What a great teaching skill you have.
tanks... you are the reason i can confidently study and get good grades...
very nice and perfect explanation
thank you for this, i am now ready for my quiz sir!
Thankkkk uuu .it's really helpful 🫰🏻🫰🏻
This is so helpful, thank you for making this tutorial series!
Thank you so much.This is very helpful for me.
Thanks for saving lives.
Perfect explanation....tq so much sir......
B and C should also be marked as the initial state.
This was little bit hard to understand, but I understood it. Thank you
Why was the reason for this procedure you didn't tell why we have to follow e* input and e*
thanks a bunch, your videos helped me a lot
Thankyou... U explained really well 💜
Pls explain this concept with other example that convert to dfa
it's easy once you get NFA you should converted from NFA to DAF
Thank you so much Sir!
Thanks a lot
Sir please make playlist on Advance computer Architecture
O thank you very much sir I am so afaired. Tomorrow my flat exam and I don't no anything tx sir you save me 😄
It's so sad to check out that you haven't made any lectures on "Epsilon NFA to DFA" !!!
I think you can just do Epsilon NFA -> NFA -> DFA
Please correct me if I am wrong. I think this NFA will be able to accept all strings over the alphabet a,b.
Thnaks dude, solved my doubt
Thank you! Very clear!
Thank You♥
Thank you very much sir.
If I didn't watched your video I would never understand it
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thanks, this is helpful
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Your videos r really awesome
Nice Sir 😊
Examguard!!!
Thanks a ton sir!
Buen video te aventaste
Great explain
should we put two different lines for 0 and 1,or just 0,1 in one line is okay,sir?
in the input output table(0,1), would you only include states that have epsilon? For example, if A did not have an epsilon and went on 1, would you include that in the table.
I don't think that state B is final, only A and C are final. F union A, so C union A is A and C.
Thank You so much💯💯
Thankyou
saved my life!
please video about E-NFA to DFA
Yes
Superb sir...
The best thing for the instructor to do would be to start from scratch with the rendering of this state machine and describe the various layers. Then provide the solution. He understands the syntax but we do not.
All you need to know is the notation and syntax. I see a, b, and c but do these circles definitively represent distinct states? Just depends on the grammar, etc: ahhh..::according to our instructor yes they do. Kewl!! Not as hard as it seems.
you are the only appearing GOD before the exams thanks a lot ❤🔥❤
Amaaazing videos !!
Can't we use only 1 arrow for transitions between 1 pair of states on both input? For ex: why don't use just one arrow for inputs 0 and 1 from A state to B state?
yes we can.
same question
Thank you .
Can't the NFA finally obtained be minimized to just one accepting state with a self loop at any input? Since this one is also going to accept any input string to it due to all the states being accepting.
man you are the best
Least useful channel our teacher does not uses you method
Why do you set the 3 states as accepting states? Shouldn't it be only C and A?
the answer is at 6:58 , this particular e-nfa accepts any word as it has e-transitions from initial state to an accepting state
Sir I think here A doesn't have the e*closure with c
Thankyou so much sir🙏. May I know your name...?
nice video brother
Good job sir
After conversion of the following epsilon NFA to NFA what is the number of input alphabets in the resultant NFA
Thankyou sir
We need epsilon nfa to dfa as well please
thank you sir
Thanks!
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If all the states are final states then what is the use of having NFA, let the machine accepts all the inputs
this is just to show how the conversion is done in a common scenario
please, if i have 2 states q1 and q2,q2 is not final state, and there is epsilon transition between them and i have not another transition with q2 , what is the rule?
Love it ❤
if i converted it to dfa what will be the accept state based on
So at the 2:25 mark it’s just a matrix.
A 3x2 one.
Can anyone tell me why e closures of A is all A, B and C . It should be only A and B
A on epsilon goes to B, and B on epsilon goes to C , so A goes to C on epsilon (Zero input)
oh goood thank you thank you
Hey, what about the final states if there are no states which doesn't reach final states on seeing epsilon ?
make them initial in your nfa simple
What kind of machine is this?
What about dead states ?
sir can u tell me the cnversion of epslion nfa to dfa
first convert to nfa then convert to nfa to dfa...
right
create a transition table, write all the transitions, you will get sets of states for each transition, make these sets a new state define the transitions for these states, repeat the process till there are no new states and all transitions are defined. Use the table to construct a DFA.
can u tell me the reference book of this method??