Multivariable Calculus | Showing a limit does not exist

แชร์
ฝัง
  • เผยแพร่เมื่อ 26 ส.ค. 2024
  • We introduce the notion of the limit of a function with more than one variable and provide a strategy for showing that the limit does not exist.
    www.michael-pen...
    www.randolphcol...

ความคิดเห็น • 7

  • @steveying1305
    @steveying1305 4 หลายเดือนก่อน

    Amazing video

  • @cycklist
    @cycklist 4 ปีที่แล้ว +1

    Very interesting.

  • @JossoJJossoJ
    @JossoJJossoJ 4 ปีที่แล้ว +2

    How can we know if we've checked all directions?

    • @Boringpenguin
      @Boringpenguin 4 ปีที่แล้ว

      In order to say that the limit exists for a function at a certain point, the answers coming from all directions must be the same.
      So, to prove that the limit does not exist, you only need to find two "directions" such that their answers don't agree with each other.

  • @xahiru
    @xahiru 4 ปีที่แล้ว

    isn't the limit of (-y)^2/y^2 = 1? @4:55

    • @SuperDreamliner787
      @SuperDreamliner787 4 ปีที่แล้ว +1

      Yes, but we had to consider -y^2/y^2 instead of (-y)^2/y^2

  • @georgettebeulah4427
    @georgettebeulah4427 4 ปีที่แล้ว

    I can see it but they all look the same I can not understand a lot from it and can not make so much sense of it.