OMG I love this. My teacher showed it to us and I tried it on every equation she gave us and I got every one right and I think I was probably the first one finished (hard to tell with online class!!). This makes it SO EASY!!!!!!! I love you!!!!!!!!!!!!!!!!!!!!!!!
I could not balance this equation until I found your video!!!! FeS2+O2--->Fe2O3 + SO2 made me crazy until your method. Lots of boxes, it worked!!!!!!!!!!!!!!!!!!!!!!!!! THANK YOU 😊
Your videos are fantastic, and I've used your stoichiometry video in my chemistry class. But I do wish you'd included a couple of complex reactions here where the same element is in multiple molecules on one side of the equation, like 10 HSiCl3 + 15 H2O → 1 H10Si10O15 + 30 HCl. I think this method would stump a few of my students where they're adding boxes for multiple molecules with H and/or where the balanced coefficients are so high.
Hi, thanks so much for using my videos! Yes, I agree, this method becomes unwieldy as equations get more complex. It is a good method for ~intermediate equations. I'm not sure there is any getting around counting atoms, and this method is one way of doing that. I think it could be used with the type of equation you wrote, if only because it lays out each and every atom on both sides. It would require a large sheet of paper! Thanks for you comment.
There are instances when the polyatomic ion would be left alright but there is a new element and it is hard to guess whether it has been made by polyatomic ion A or polyatomic ion B on the reactant side On that case things would start to get messy and confusing to which to label as what
@@CrashChemistryAcademy yes but now there is always a nagging question that when we should do it and by doing that we are actually INCREASING our run time by a minor amount and that is for complicated setups certainly but that is where this is WANTED. This system only saves you a minor amount of process time but that amount is very VERY appreciated but if we are confused whether to use the ionic system as one thing or not and then actually processing it and also thinking whether we should use the system in the first place in the place it starts consuming exorbitant amount of time. In such case not having a system is better than having one. But appreciate the effort anyway and I do hope you will come up with a revised and more useful edition of the trick for stuff soon.
I think you are right that I could have been more clear about what I meant, using an example, of when the polyatomic ion breaks apart. I decided against it, but maybe that was the wrong decision. I'll give you an example, but regardless of the method, or system, you use, it always is just a way to count atoms. All balancing is counting atoms. An example of a polyatomic ion breaking up is: Cu + HNO3 --> CuNO3 + NO2 + H2O. Here the nitrate ion, NO3, both stays together (CuNO3) and breaks apart (NO2 + H2O). So you cannot count the NO3 as a single unit, you have to count the N and O separately. It does not matter that one of the products has nitrate in it, because there has to be nitrates in the reactant side that lose oxygen to the hydrogen, and so you have to count the N and O separately. I hope that helps. Whether my method or some other method is better for balancing this is really your choice.
This is SOOO MUCH EASIER!!! You're a total life saver
OMG I love this. My teacher showed it to us and I tried it on every equation she gave us and I got every one right and I think I was probably the first one finished (hard to tell with online class!!). This makes it SO EASY!!!!!!! I love you!!!!!!!!!!!!!!!!!!!!!!!
great work sir,you cleared my age long confusion in mere minutes
I could not balance this equation until I found your video!!!! FeS2+O2--->Fe2O3 + SO2 made me crazy until your method. Lots of boxes, it worked!!!!!!!!!!!!!!!!!!!!!!!!! THANK YOU 😊
Brilliant! This is such a beautiful straightforward and visual method. My students will love this, thank you very much for posting!
Thanks for your comment. I especially enjoy hearing from teachers!
Great explanation! very visual and straight forward! Thanks!
Great ! Amazing Sir! Love from India👍🇮🇳
हेलो इंडिया! 💖 थैंक यू वैरी मच!
Thank you sir! I'm also from India 🧡🤍💚
GREAT!!!! So straightforward!
You're amazing, the way you talk is so clear and simple
Thank you!
MIND BLOWING haha 2nd time taking this class and man this just help me understand
OMFG!!! this was the most helpful video in chemistry for me!!
it made me understand the most difficult thing in chemistry 4 me!
thx for uploading!!
😊
You are a saviour
Your videos are fantastic, and I've used your stoichiometry video in my chemistry class. But I do wish you'd included a couple of complex reactions here where the same element is in multiple molecules on one side of the equation, like 10 HSiCl3 + 15 H2O → 1 H10Si10O15 + 30 HCl. I think this method would stump a few of my students where they're adding boxes for multiple molecules with H and/or where the balanced coefficients are so high.
Hi, thanks so much for using my videos!
Yes, I agree, this method becomes unwieldy as equations get more complex. It is a good method for ~intermediate equations. I'm not sure there is any getting around counting atoms, and this method is one way of doing that. I think it could be used with the type of equation you wrote, if only because it lays out each and every atom on both sides. It would require a large sheet of paper!
Thanks for you comment.
Just beautiful. Thank you so much Mr.
life saver, thank you so much
Wow. Very good.
THANK YOU ❤🙏🏽🙏🏽
Best teacher
Top 10 ways to balance a chemical equation! Number 4 will surprise you!
What’s the best way?
omg this is great. perfect. thank you.
Trott
It really helped me a lot 😄...thank you☺
Great!
THANKK YOUUUU!!!!!
extremely helpful!!!
The best for sure.
Thanks!!
Thank you, Sincerely. Thank you!!!!
You're Welcome!
Very good
Deadass, you saved me
There are instances when the polyatomic ion would be left alright but there is a new element and it is hard to guess whether it has been made by polyatomic ion A or polyatomic ion B on the reactant side
On that case things would start to get messy and confusing to which to label as what
If you are not sure then you should split up the ion and count its atoms individually.
@@CrashChemistryAcademy yes but now there is always a nagging question that when we should do it and by doing that we are actually INCREASING our run time by a minor amount and that is for complicated setups certainly but that is where this is WANTED.
This system only saves you a minor amount of process time but that amount is very VERY appreciated but if we are confused whether to use the ionic system as one thing or not and then actually processing it and also thinking whether we should use the system in the first place in the place it starts consuming exorbitant amount of time.
In such case not having a system is better than having one.
But appreciate the effort anyway and I do hope you will come up with a revised and more useful edition of the trick for stuff soon.
I think you are right that I could have been more clear about what I meant, using an example, of when the polyatomic ion breaks apart. I decided against it, but maybe that was the wrong decision. I'll give you an example, but regardless of the method, or system, you use, it always is just a way to count atoms. All balancing is counting atoms. An example of a polyatomic ion breaking up is: Cu + HNO3 --> CuNO3 + NO2 + H2O. Here the nitrate ion, NO3, both stays together (CuNO3) and breaks apart (NO2 + H2O). So you cannot count the NO3 as a single unit, you have to count the N and O separately. It does not matter that one of the products has nitrate in it, because there has to be nitrates in the reactant side that lose oxygen to the hydrogen, and so you have to count the N and O separately. I hope that helps. Whether my method or some other method is better for balancing this is really your choice.
You literally made me smile and wipe my tears after two days of crying over this thing lmao, thanks!!!
Damn this was truly helpful
Thanks!
Cooool method.
Thanks!
It is better than 45 minutes class.
H must be N balance
First
Thanks Owen. I've been waiting.