So for the second problem at 10:09, since it is the final table in phase 1 for a minimization problem , shouldn't all the values of Zj-Cj be 0,0,1,1,2,0. I'm confused. Could you please explain?
I'm still a bit unsure about all of the nuances, such as when you can drop rows like at 18:05, but your examples are definitely helping me to understand!
At this time, i am explaining Transition from Phase 1 to Phase 2. Phase 1 table is completed so usual minimum ratio rule is not applied, rather i am looking which variable we can take in phase 2.
If you using Two phase method, then we start by writing auxiliary LPP, and here objective function is Minimization=sum of artificial variables. So cost is +1. But if in auxiliary LPP you keep objective function as Maximization then it is Maximization=- (sum of artificial variables), so here you can take -1 as cost of artificial variables. So depending upon what we are considering objective function in auxiliary LPP accordingly you can choose cost of artificial variables. So selection of maximum/ minimum objective is irrelevant, you can select any. Similarly in BigM method, if objective function is Maximization then cost is -M, and for Minimization the cost is +M for artificial variables.
yes you are right i stuck again and again but seeing your cooment i understand that thanks to share your thoughts. moreover earlier they said when minimum ratio tie go with artificial variable but here she go with x_{2}. however answer in unaltered.
Screenshot: drive.google.com/file/d/1YNMVQtz98Hmim7uGctYeqxOdJBK0zW16/view?usp=drivesdk For optimality the vector with most positive c - z value (in this case x1) should be entered into the solution (Table 4.15), but author stressed that if x1 is allowed it will lead to infeasibility w/o any explanation, instead chose to go with s2. Can you please give a hint why he said so?
So for the second problem at 10:09, since it is the final table in phase 1 for a minimization problem , shouldn't all the values of Zj-Cj be 0,0,1,1,2,0. I'm confused. Could you please explain?
Calculation mistake at 6:02, Zj-Cj should be -11 for a2.
Yes ✅
I'm still a bit unsure about all of the nuances, such as when you can drop rows like at 18:05, but your examples are definitely helping me to understand!
Mam fantastic ☺️☺️☺️
is there any difference between the cost of artifcial avriables in maximization case and in minimization case
At 17.32 shouldnt min () be either 2/2=1?
And the pivot element corresponding to it?
At this time, i am explaining Transition from Phase 1 to Phase 2. Phase 1 table is completed so usual minimum ratio rule is not applied, rather i am looking which variable we can take in phase 2.
If you using Two phase method, then we start by writing auxiliary LPP, and here objective function is Minimization=sum of artificial variables. So cost is +1. But if in auxiliary LPP you keep objective function as Maximization then it is Maximization=- (sum of artificial variables), so here you can take -1 as cost of artificial variables.
So depending upon what we are considering objective function in auxiliary LPP accordingly you can choose cost of artificial variables.
So selection of maximum/ minimum objective is irrelevant, you can select any.
Similarly in BigM method, if objective function is Maximization then cost is -M, and for Minimization the cost is +M for artificial variables.
Thank you for the explanation, been struggling for a while with these topics. The best explanation video for these topics I've seen.
yes you are right i stuck again and again but seeing your cooment i understand that thanks to share your thoughts.
moreover earlier they said when minimum ratio tie go with artificial variable but here she go with x_{2}. however answer in unaltered.
Please make video on matlab code
I do hope to make matlab code in future. Thank you for watching videos.
Screenshot: drive.google.com/file/d/1YNMVQtz98Hmim7uGctYeqxOdJBK0zW16/view?usp=drivesdk
For optimality the vector with most positive c - z value (in this case x1) should be entered into the solution (Table 4.15), but author stressed that if x1 is allowed it will lead to infeasibility w/o any explanation, instead chose to go with s2. Can you please give a hint why he said so?