At the 1:40 mark you stated that doubling the series and parallel you double the voltage and the capacity. This is incorrect, it only doubles the voltage whilst the capacity remains the same. With regards to connecting additional cells but of a higher charge to that of the others at the 3:25 mark, the graphics doesn't agree with what you said because the 2 cells per string will discharge to 8 cells each, thus will not overcharge based in the 8 cells level of charge in the graphics. A better scenario would be the bank of four new pairs on the left be at the 95% but the other 4 banks of 8 would be at say, 90%. Also , because you are trying to fit a lot of information in 5 minutes, your video becomes mumble jumble to the average punter.
Thanks for the detailed reply. 3:25 "overcharge" might indeed not be the best word there as they won't go over 4.2V. The point is you would charge them with no regards to their C-rate. At 1:40 if you draw 1A at 3.5V for an hour you draw 3.5Wh, if you draw 1A at 7V you will draw 7Wh. How should I have described it better?
Very timely video…about to add an additional module to my battery pack! 😊
Great and informative! Keep up the good work
nice video!
Thanks!
At the 1:40 mark you stated that doubling the series and parallel you double the voltage and the capacity. This is incorrect, it only doubles the voltage whilst the capacity remains the same. With regards to connecting additional cells but of a higher charge to that of the others at the 3:25 mark, the graphics doesn't agree with what you said because the 2 cells per string will discharge to 8 cells each, thus will not overcharge based in the 8 cells level of charge in the graphics. A better scenario would be the bank of four new pairs on the left be at the 95% but the other 4 banks of 8 would be at say, 90%. Also , because you are trying to fit a lot of information in 5 minutes, your video becomes mumble jumble to the average punter.
Thanks for the detailed reply. 3:25 "overcharge" might indeed not be the best word there as they won't go over 4.2V. The point is you would charge them with no regards to their C-rate.
At 1:40 if you draw 1A at 3.5V for an hour you draw 3.5Wh, if you draw 1A at 7V you will draw 7Wh. How should I have described it better?