I am not from a one of the circuit branches, however it is so nice that you explain from the basics. It makes it easier for a chemical engineer like myself to apply electrical basics in my work.
Wonderful. I hadn't really thought about it, but I'd be willing to do guest lectures or tutoring if anyone ever asked. No university has ever asked, though.
9:38 i was waiting for this part to come up so good, tho you did skip over some very important highlights you brought up such as amplifiers to boost the 1.5mV ? can you elaborate on that aspect of which amplifier are you refereeing name/model number? also it did not pick up clear on what you meant to say when you placed the strain gauge over the wheatstone bridge covering only R1 "what does this mean for the rest of R2 R3 and R4 ? are they still being used at this point?
Frank Lopez they are still being used. In a q bridge circuit they would be fixed resistors with the same resistance as the strain gauge (when un-strained). This makes your single strain gauge the only variable. A change in resistance due to strain unbalances the bridge and produces an output voltage. You can then use the gauge factor and excitation voltage to calculate strain. As long as you know the test materials youngs modulus you can use the strain to calculate stress
I really don't know how they keep the bad profs at my school :( ... I am not saying this as a complement but I really love the way you are teaching. I might propose some of Electrical Engineering topics and I want you to explain them. Is that OK sir?
@purdueMET Will do! P.S your book 'Engineering the Guitar', great too! You should definitely do a youtube video on some of the concepts, excellent job ;)
im building a humanoid robot and im using this as finger tips for end efflector. your formulas should help me on my calculations and predication algorithm for its movement when i do my C++ Classes or function calls
First class explanation. Not many university lecturers do such a good job.
I'm glad guys like you give students like me a chance to catch up without having to deviate from youtube, thanks
I am not from a one of the circuit branches, however it is so nice that you explain from the basics. It makes it easier for a chemical engineer like myself to apply electrical basics in my work.
Number 1 Top Rated Lecturer! I'm getting nice marks because of his videos!
OMG.... I wish you were my professor. You really made it so clear sir
THANK YOU SO MUCH
Thank you very much for your help. You are such a great professor. This tutorial is SO CLEAR !
Thanks for the video, it really helps to understand the circuit.
Glad it helped :-)
I'm in Chemical Engineering so electricity was never my forte, but this helped so much. Thank you!
Great video man. Your explanations are so clear
Great Stuff. EE here attempting to do a science fair experiment with my 8th grade daughter. We're having fun
thanks so much, I am really glad to have found this video, I really needed to catch up in understanding this experiment and how it works.
Tanks alot! Great way of exlaining things!!!! Best regards from Germany
Great Video, your approach is clear .Thank you
Nice basic understandable and clear with application explanation.
You are so amazing! Keep up the great job. You made it crystal clear for me! thank you so much.
This was awesome teaching! Thanks very much!
Great sir.
was looking for this kind of explanation
Awesome thank you. I know this was posted a long time ago. but awesome and still relevant!
Thank you so much you just explained everything so clearly saved my mid-term LOL.
Thank you so so so much for your video. It helped me understand a lot... Thank you
Incredible, 2-3 minutes in and i was smiling
Wonderful. I hadn't really thought about it, but I'd be willing to do guest lectures or tutoring if anyone ever asked. No university has ever asked, though.
thanks for the presentation.
Clear and concise!
This helped me alot!
Thank you very much! Really nice lecture
u r an amazing teacher
You're most welcome. I'm glad the videos help.
helped me a lot, thank you very much
A very useful tutorial, Thanks a lot!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
How do you connect four or two different strain gauges together into a wheatstone configuration like for building a bathroom scale?
Thank you sir its really interesting
Very helpful!
Why not use a current source and measure the change in voltage over the resistor?
Thanks for your videos, really helpfull
wouldnt the resistance go down if the wire wasnt bundled up when pulled to a longer extension?
9:38 i was waiting for this part to come up so good, tho you did skip over some very important highlights you brought up such as amplifiers to boost the 1.5mV ? can you elaborate on that aspect of which amplifier are you refereeing name/model number? also it did not pick up clear on what you meant to say when you placed the strain gauge over the wheatstone bridge covering only R1 "what does this mean for the rest of R2 R3 and R4 ? are they still being used at this point?
Frank Lopez they are still being used. In a q bridge circuit they would be fixed resistors with the same resistance as the strain gauge (when un-strained).
This makes your single strain gauge the only variable.
A change in resistance due to strain unbalances the bridge and produces an output voltage.
You can then use the gauge factor and excitation voltage to calculate strain.
As long as you know the test materials youngs modulus you can use the strain to calculate stress
Thank you!! You're my hero!!
@arlil1 Thanks very much. If you like the videos, please spread the word. - RMF
purdueMET im watching this in 2017...and its helping me a lot...thanks a lot..
Excellent. Thank you.
Helpful 🙏
Glad it helped 😊
It's really helpful for me too.. Thank you so much
I really don't know how they keep the bad profs at my school :( ... I am not saying this as a complement but I really love the way you are teaching.
I might propose some of Electrical Engineering topics and I want you to explain them. Is that OK sir?
Thank you! Great video
I ran the numbers again and got (120.06*120-120*120)/(240*240)*12V = .0015V = 1.5 mV
I think this is right. Thanks for keeping me honest :-)
RMF
Thanks a lot!!!!
Thank you!
@purdueMET Will do!
P.S your book 'Engineering the Guitar', great too! You should definitely do a youtube video on some of the concepts, excellent job ;)
im building a humanoid robot and im using this as finger tips for end efflector. your formulas should help me on my calculations and predication algorithm for its movement when i do my C++ Classes or function calls
Thnq so much
Thank you
its 15 mV sir not 1.5
Please come teach at georgia tech. please.