Thank you so much! You explained what nobody else would: I.e. the coil curve based on the bypass factor. Everyone else just brushes over this part and then tries to sale you software license subscription.
Please , could you explain a factor 0.02 in formula for outside air total heat OATH= 0.02 x v1 x (h1-h2). Also , is Grand total heat vale on which we have to choose a colling power of the coil?
Point b is nothing but Alignment circle. Alignment circle is a reference point on the psychometric chart. It lies within Comfort condition. It generally lies within 24° to 26° DBT and 50%-60% Relative Humidity.
Yes thanks,given instruction says "if two- third of recirculated room air and one- third of fresh air are mixed before entering the cooling coil" so I don't understand how to get point point 3 in order to get DBT3 to be used on trial and error method
The Outside Air Total Heat impoted to the room should have been calculated as: 100/60/0.911*(85-47.5)= 68.6 kW (not 15 kW as presented). Meaning that GTH should be 125.32 kW instead of 71.72 kW. Yet, I appreciated the work. Thanks.
I used to see that, GTH =Total sensible+ Total Latent, What is oath ?? Do we really need that? I just never saw that calculation while finding GTH. Can you explain please?
You have to assume the approximate values of td4 and td6 in such a way that...you are getting the RHS as 0.1. The value of td6 should be less than td5 (td5 is nearly 12.7 degree from psychrometric chart) and value of td4 should be more than td5. And the difference between td4 and td6 should be approximately 1.5 degrees.
As in question, it is given that two third of recirculated room air and one third of fresh air are mixed so it means... Line 1-2 needs to be divided into three parts...now how we will get the location of point 3... So...as two third of recirculated room air is given...it means concentration of recirculated room air is more... So the point 3 should be near to point 2. If we want to change the formula in terms of length... It will be like... Length 1-3 = length 2-1 * 2/3
Excellent information as well as clear way of explanation. Thank you How would you in detail using the psychrometric chart calculate the sensible heat for the following: Hot water entering a counter flow cooling tower : 1 ib mass/min at 85 f to be cooled to 70 f Using 1 ib mass/min of air entering the cooling tower at 78 f and 50% RH What is the temperature of the existing air Thank you
Thankyou mona. Im doin my study for exam tomorrow. The problems given on the 2018 exam is the same with the example in this video. So glad That i found ur channel.
Thank you so much! You explained what nobody else would: I.e. the coil curve based on the bypass factor. Everyone else just brushes over this part and then tries to sale you software license subscription.
AAPKI videos kaafi informative hai
Maan gaye devi ji mera dimag to pura hil gaya..... But.... It helped me a lot thanks....
I think this is a best video,
Please add more videos such examples
ek no. ur vdo was of great help. Thanks
My goodness explanation is wow. Thanks alot mona
Simple and effective explanation thank u
Good making mam
Very effective and helpful presentation, thank you so much mam
Crisp and clear 👍🏻
❤
thank you for explaining trial and error method
well explained
Hi.. good one. Can you add more vedios with different problem?
Please can I get a title of the book you are using?
Nicely explained
Now my doubt clear thankyou mam💯
Nice voice👌
THANKU SO MUCH MAM
if we take Td4 = 10 and Td6 = 8 than also bypass factor is 0.1. so how to insure the values in trial and error method
Super..sister👍👍
th-cam.com/video/aQ3pmELl_3I/w-d-xo.html
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Nice
Please , could you explain a factor 0.02 in formula for outside air total heat OATH= 0.02 x v1 x (h1-h2). Also , is Grand total heat vale on which we have to choose a colling power of the coil?
thanks, mum, you are so good everything is now clear to me, but how did you get RH 50% and DBT 26 degrees which is point "b"
Point b is nothing but Alignment circle. Alignment circle is a reference point on the psychometric chart. It lies within Comfort condition. It generally lies within 24° to 26° DBT and 50%-60% Relative Humidity.
Thank you very much, another question how to get point 3 which is in between point 1 and 2
@@blessingxaba5810 At 9:24....there is one formula...based on the condition given in the question...through which the location of point 3 is decided
Yes thanks,given instruction says "if two- third of recirculated room air and one- third of fresh air are mixed before entering the cooling coil" so I don't understand how to get point point 3 in order to get DBT3 to be used on trial and error method
Mam how we will take alignment circle
Please upload psychrometric chart also in description 🙏
th-cam.com/video/aQ3pmELl_3I/w-d-xo.html
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not for beginers
there is a mistake while calculating OASH and OALH and fresh air is not considered at load calculation
I think, everything is okay, until she added 15kW to get GTH. I think GTH SHOULD BE. EQUAL TO 66. Do you agree with me? Or you meant other things?
The Outside Air Total Heat impoted to the room should have been calculated as: 100/60/0.911*(85-47.5)= 68.6 kW (not 15 kW as presented). Meaning that GTH should be 125.32 kW instead of 71.72 kW. Yet, I appreciated the work. Thanks.
@@enderkazakli9557
Yeah!!!!
I finally found someone who is aware of this fatal mistake
Good focus, brother
where is the function of 100m3/min of fresh air? please make clear that.
Mam please can you please share more videos of turbo machineary problems....
short and properly explained. but calculation of OATH is wrong as you should use VF=100 m3 instead of V1.
I used to see that, GTH =Total sensible+ Total Latent, What is oath ?? Do we really need that? I just never saw that calculation while finding GTH. Can you explain please?
Any reference standard for alignment circle?
Hii mam this help me alot , but i have problem in td4 and td6 value , how did u get that value , can u plz rply n explain it .
Mam please tell how to solve trial and error method😢
alignment circle kya hai?
mere chart mei nhi haai
thank yo u
for your effort
Mam if possible plz explain heat load calculation in Excel sheet.
How to find trial and error method which use value use in to find td4 & td6
10:37
You have to assume the approximate values of td4 and td6 in such a way that...you are getting the RHS as 0.1.
The value of td6 should be less than td5 (td5 is nearly 12.7 degree from psychrometric chart) and value of td4 should be more than td5.
And the difference between td4 and td6 should be approximately 1.5 degrees.
Thanks a lot
Make videos on air conditioning load numericals .
Thank You Ma'am
th-cam.com/video/aQ3pmELl_3I/w-d-xo.html
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Can you explain how you got formula for point three?
How do we know length of 2-3= length of 2-1 * 1/3 and not length 1-3 = length 2-1 * 1/3
As in question, it is given that two third of recirculated room air and one third of fresh air are mixed so it means...
Line 1-2 needs to be divided into three parts...now how we will get the location of point 3...
So...as two third of recirculated room air is given...it means concentration of recirculated room air is more...
So the point 3 should be near to point 2.
If we want to change the formula in terms of length...
It will be like...
Length 1-3 = length 2-1 * 2/3
@@monayadav5499 I think it would be 30°C
B'cos 40-26=14 & 14/3 =4.6
So 26+4.6=30.6 =30
Pls make it clarify.
Please upload psychmetry chart
Excellent information as well as clear way of explanation. Thank you
How would you in detail using the psychrometric chart calculate the sensible heat for the following:
Hot water entering a counter flow cooling tower : 1 ib mass/min at 85 f to be cooled to 70 f
Using 1 ib mass/min of air entering the cooling tower at 78 f and 50% RH
What is the temperature of the existing air
Thank you
Kal exam h please upload
Thanks 😊
hello, what book are you using for the exmple? thankyou :)
'Refrigeration and Air conditioning' by Khurmi and Gupta.
Thankyou mona. Im doin my study for exam tomorrow. The problems given on the 2018 exam is the same with the example in this video. So glad That i found ur channel.
@@evelynpatricianastpl5271 same here 😂 .exam day after tomorrow..last time studies 😅
RS khurmi Example 19.1 nice
th-cam.com/video/aQ3pmELl_3I/w-d-xo.html
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th-cam.com/video/aQ3pmELl_3I/w-d-xo.html
How come the alignment circle point b??????????
Just name to Alignment circle is given as 'b', in order to complete line ab
hA ki value kaise nikale
هلو هل بالامكان الحصول على الملف بصيغة PDF
which app do u use for plotting the points please?
Microsoft powerpoint
@@monayadav5499 thank you sooo much
th-cam.com/video/aQ3pmELl_3I/w-d-xo.html
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Please upload
thanks
th-cam.com/video/aQ3pmELl_3I/w-d-xo.html
How b point came?
Amazing but how Did u plot point 3
At 9:24....there is one formula...based on the condition given in the question...through which the location of point 3 is decided.
Thk
kal subhe mera ppr h aur tu bol rahi h trail n error se kare aise toh teacher bhi trial n error se marks degi
It is to be done that way only...
If you know that method...then it will not be a problem
Everyone is being sarcastic
Good explanation
Please upload psychmetry chart
❤
Please upload psychmetry chart