Prove: (tanθ+secθ-1)/(tanθ-secθ+1)=(1+sinθ)/cosθ. Class-10 Trigonometry important problem

Prove: (tanθ+secθ-1)/(tanθ-secθ+1)=(1+sinθ)/cosθ

[@chintakayalaravi9139]

Awesome👏👏

[@khajaacademymathematica1729]

Thank you! Cheers!

[@luckykhosla6439]

Well explained sir please post more videos

[@dasguptad5629]

Good explanation thank you so much sir

[@khajaacademymathematica1729]

You're most welcome

[@shaikzahid5566]

Well explained 👌

[@khajaacademymathematica1729]

Glad you liked it

[@Ruthvik07]

Sir one doubt why didn't you kept the value of 1 in denominator

[@krishnaacademy9839]

Superb explanation 👌 👏 👍

[@RajuSingh-ch5nq]

Well explained sir thank you

[@kanishkkumar4339]

Super explanation thank you so much

[@khajaacademymathematica1729]

You are welcome

[@KabirSabseTej]

Sir why didn't you replace +1 by sec2-tan2?

[@khajaacademymathematica1729]

Thank you for your support.
And I didn't change the denominator because if I change both the numerator and denominator I will not get RHS
So in this problem we should change only the numerator.

[@KabirSabseTej]

@@khajaacademymathematica1729 sir is this applicable Everytime or in some cases ?

[@mohammedfurqanali6158]

bahuth bahuth shukriya sir

[@vanyaheer7191]

explained it so well sir 🫶🏻 Nailed it, tysm

[@KabirSabseTej]

Please explain sir

[@hindustaniashugamer9679]

Isn't that a little hard for us ... Like out of nowhere these values comes from?

[@seshreddy9470]

Op

[@rajukumar-fw1us]

😮

[@ivaan3282]

👏

[@KARTHIK-ft2ns]

thank yoouu

[@harshavardhankumar8028]

Well explained sir please post more videos sir