Oxford University Entrance Exam Tricks

[@RyanLewis-Johnson-wq6xs]

10^Log(0.5+0.5Sqrt[5])+100^Log(0.5+0.5Sqrt[5])=1000^Log(0.5+0.5Sqrt[5]) x=Log(0.5+0.5Sqrt[5])

[@PakMaths-u5m]

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[@RyanLewis-Johnson-wq6xs]

Log(0.5+0.5Sqrt[5])=Log(1+Sqrt[5])/2

[@EC4U2C_Studioz]

x = log ((sqrt(5)-1)/(2)) to base 1/10.

[@nikolayplatnov5148]

Exam for schoolboys ?
Equation Z+Z^2=Z^3- is it really difficult ? Z is 10^x

[@prollysine]

let u=10^x , u^2-u-1 , u=(1+V5)/2 , 10^x=(1+V5)/2 , x=log((1+V5)/2)/log10 , x=(1+V5)/2 , test , 10^x+100^x=4.23607 , 1000^x=4.23607 , OK ,