there's nothing as calming and reassuring when you are stressed about a particular topic, and you find a video with this guy because you know its all going to be all right
Everytime I get stuck up on a topic the first thing I do is check if Mr. Khan has a playlist associated with it. Only if I dont find it there I search elsewhere. You're teaching is that awesome!
As someone who regularly publishes scientific papers on photoelectron spectroscopy, I find this video frustrating. It's good that the author is trying to make it intuitive. It is not good that there are loads of factual errors. The intensities of the peaks are not proportional to the number of electrons in each shell - the photoionization cross-sections are very different for the different shells and subshells. (Sometimes by several orders of magnitude.) Core levels with angular momentum (i.e. anything but s) have spin-orbit splittings. These can be quite large for deep core levels. The kinetic energy of the photoelectron is not inversely proportional to the binding energy. Instead, Eb = hv - Ek - phi, where Eb is the binding energy, hv is the photon energy, Ek is the kinetic energy of the photoelectron, and phi is the work function. Photoelectron spectra are very rarely plotted on a logarithmic scale - a linear scale is almost always used instead. Also, MJ/mol is an unconventional choice of units. Electronvolts are used almost exclusively in practice. If you do use MJ/mol, for Ca, the peaks should not appear anywhere near where you have drawn them on the graph. (The Ca 1s binding energy is off by approximately one order of magnitude for example.)
That’s fair, but as a student in a chemistry class I can confirm that the same diagrams are used in the classroom. Doesn’t fully excuse the partial misinformation, but does pertain more to the kinds of questions students are likely to deal with in class.
there's nothing as calming and reassuring when you are stressed about a particular topic, and you find a video with this guy because you know its all going to be all right
I thought this was so complicated, this makes so much more sense
Everytime I get stuck up on a topic the first thing I do is check if Mr. Khan has a playlist associated with it. Only if I dont find it there I search elsewhere. You're teaching is that awesome!
Khan you are brilliant, I have so much to thank you and your videos :0) one day once I am qualified and earning I will donate to your academy
Sir ,
DO you keep on revising your topics before the actual uploading of the video or you know the content all by heart ?
Thank you for everything.🙏
Thank you for this! I was out of school the day we learned this and this helps immensely!
it's 2023 and I'm cramming for a chem test. words cannot describe how much this video helped out
Alhamdulillah. Beneficial video.
tysm my chemistry teacher is not that great and this helped me out a lot
thank you sal khan you're a lifesaver
Amazing video! thanks a lot
than you so much for this
Thank you so much for this video!
how does this man know how to do everything
Please detail of N², F², and O² molecule electronic spectroscopic
wow, you're the best
bruh i was confused for 2 hours and watch this video and understood in 5 minutes
thanks
As someone who regularly publishes scientific papers on photoelectron spectroscopy, I find this video frustrating. It's good that the author is trying to make it intuitive. It is not good that there are loads of factual errors.
The intensities of the peaks are not proportional to the number of electrons in each shell - the photoionization cross-sections are very different for the different shells and subshells. (Sometimes by several orders of magnitude.) Core levels with angular momentum (i.e. anything but s) have spin-orbit splittings. These can be quite large for deep core levels. The kinetic energy of the photoelectron is not inversely proportional to the binding energy. Instead, Eb = hv - Ek - phi, where Eb is the binding energy, hv is the photon energy, Ek is the kinetic energy of the photoelectron, and phi is the work function. Photoelectron spectra are very rarely plotted on a logarithmic scale - a linear scale is almost always used instead. Also, MJ/mol is an unconventional choice of units. Electronvolts are used almost exclusively in practice. If you do use MJ/mol, for Ca, the peaks should not appear anywhere near where you have drawn them on the graph. (The Ca 1s binding energy is off by approximately one order of magnitude for example.)
That’s fair, but as a student in a chemistry class I can confirm that the same diagrams are used in the classroom. Doesn’t fully excuse the partial misinformation, but does pertain more to the kinds of questions students are likely to deal with in class.
Suprb
good
why not 3d2?
4s comes first because of lower energy leveel
Is it true that american army has photoelectron weapon that has an effect on brain?( x-ray laser capable of conveying electron )
❤️❤️❤️
noice
hey mr. crumps students