the most famous Ramanujan sum 1+2+3+...=-1/12

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  • เผยแพร่เมื่อ 4 ต.ค. 2024

ความคิดเห็น • 775

  • @Nondas8552
    @Nondas8552 5 ปีที่แล้ว +3413

    When you have to prove that the sum of all natural numbers equals -1/12 at 10 pm and go on a date at 11 pm

    • @blackpenredpen
      @blackpenredpen  5 ปีที่แล้ว +610

      Yup!! : )

    • @leif1075
      @leif1075 5 ปีที่แล้ว +37

      @@blackpenredpen isnt it only true if you include inaginary numbers like negative one square root..otherwise it is impossible and incorrect! Because the sum,always increases..

    •  5 ปีที่แล้ว +8

      @@leif1075 If you taking the sum of all counting numbers from one to infinity then your sum is already increasing continuously.
      What controversy on this integral sum!!

    • @johnny_eth
      @johnny_eth 4 ปีที่แล้ว +68

      It's not equals. The sum is divergent. The Ramanujan summation is a transform that assigns values to divergent series. Kind like how a Fourier transform gives you the domains of frequencies and phases of a periodic signal but it NOT equal to the signal.

    • @19divide53
      @19divide53 2 ปีที่แล้ว +9

      @@johnny_eth The equal in OP's comment is obviously in a Ramanujan summation sense

  • @alanturingtesla
    @alanturingtesla 5 ปีที่แล้ว +1031

    Square root of -1‚ now convergent-divergent series. In a few years, I expect dividing by 0.

    • @tricky778
      @tricky778 5 ปีที่แล้ว +67

      @Alan Turing, which size of 0? a big 0 or a little 0? I'm sure if you divide by a big 0 you get a smaller result than a little 0

    • @arnavanand8037
      @arnavanand8037 5 ปีที่แล้ว +61

      I feel like for that we need to redefine division. Just like there's gamma function for factorials

    • @GynxShinx
      @GynxShinx 4 ปีที่แล้ว +18

      lim(x->0+) 1/x->infinity
      If you're too lazy to write the whole thing then 1/0+=infinity

    • @arnavanand8037
      @arnavanand8037 4 ปีที่แล้ว +20

      @@GynxShinx I think everyone knows the limit already. But people feel unsure about the actual answer

    • @oracle7858
      @oracle7858 4 ปีที่แล้ว +4

      Eagle Shows Down 1/0+ is infinity but what is 1/0 🤔

  • @badmanjones179
    @badmanjones179 5 ปีที่แล้ว +1043

    black pen red suit

  • @radiotv624
    @radiotv624 5 ปีที่แล้ว +577

    This is fascinating, I love Ramanujan

    • @kingbeauregard
      @kingbeauregard 5 ปีที่แล้ว +32

      Me too, especially the chicken-flavored stuff.

    • @davidrheault7896
      @davidrheault7896 5 ปีที่แล้ว +13

      The monster is back again...i know it from physics waves in vacuum. -1/12 casimir effect

    • @radiotv624
      @radiotv624 5 ปีที่แล้ว +2

      David Rheault That’s right! What is/was your major

    • @davidrheault7896
      @davidrheault7896 5 ปีที่แล้ว +2

      @@radiotv624 I did a specialisation in physics
      It is above major.

    • @indicgamer2907
      @indicgamer2907 5 ปีที่แล้ว +23

      Ramanujan's work opened a new world of mathematics that astrophysicist use to study black hole , time travel , free energy quantum tunneling

  • @moumous87
    @moumous87 4 ปีที่แล้ว +58

    2:00 you got to love this guy for putting the R on top of the = and for actually showing what the heck is this "Ramanujan summation" thing. Thank you

  • @themeeman
    @themeeman 5 ปีที่แล้ว +423

    Looking sharp

    • @blackpenredpen
      @blackpenredpen  5 ปีที่แล้ว +40

      Clingfilm Productions
      Thank you!!!!

  • @saxbend
    @saxbend 5 ปีที่แล้ว +377

    Mathologer wants a word.

    • @NateROCKS112
      @NateROCKS112 5 ปีที่แล้ว +92

      Mathologer actually hinted at what is going on in this video. He showed that the area under the x-axis of f(n) = n(n+1)/2 is -1/12, which can be interpreted as a definite integral from -1 to 0 of n(n+1)/2. n(n+1)/2 is a graph of this infinite series (as n→∞) since it's the sum of all natural numbers up until n.
      Also, BPRP used the proper notation with the Ramanujan summation, and did not claim that the natural numbers "summed" to -1/12, just that they could be assigned to it.

    • @angelmendez-rivera351
      @angelmendez-rivera351 5 ปีที่แล้ว +106

      NateROCKS112 Mathologer did show this, but he equally also spoke against any association between adding the natural numbers and obtaining the result -/12 via analytic methods.
      The problem lies in how poorly and inconsistently the technical terminology of calculus is being used, and how poorly the word “summation” is interpreted. The problem is that, nowadays, when dealing with sequences of partial sums, we tend to associate them to summations themselves, without much justification, even though these summations are not sequences, but numbers, and the summations are furthermore the result from a set of rules of arithmetic operations on a field, whereas statements about these sequences are statements about vector spaces and linear functionals.
      When we see the sentence 2 + 2 = 4, this statement is provable. This has nothing to do with sequences. It is a statement that is the consequence of the rules of addition and basic arithmetic. When we see that f(x) = x^2, and we calculate f(1) + f(2) + ••• + f(100), this is also a statement about arithmetic, and summation notation is merely a notation to abbreviate this result: the operation is ultimately still addition. I see no reason why 1 + 1/4 + 1/9 + ••• = π^2/6 should be treated any different. In fact, to prove this identity, we typically just use algebra and trigonometry, not much from calculus itself though. I see no reason why 1 + 2 + 3 + ••• = -/12 should be treated any different either. Caught hated the concept of infinity. He was, so to speak, an ultra finitist. This is why he invented the concept of a limit, and whenever we wanted to speak of adding infinitely many numbers together, he rejected the idea, and instead proposed to talk about the limit of the sequence of partial sums. For some practical purposes, and for his specific theoretical, both mathematical and philosophical purposes, this definition works just fine. Nowadays, we treat it is a method to assign value to infinite sums, but strictly speaking this method does not give you the sum itself. In fact, as I already said, Cauchy would have said such sums do not exist, and the expressions are nonsensical, precisely because he did not believe in the notion of infinity. So associating actually adding infinitely many terms with these limits is conceptually incorrect, and an equivocation of bounded behavior with infinite quantity, which should not happen. What the limit of the sequence of partial sums tell us is information about the asymptotic behavior of some function, and this function represents an algorithm. In the case of the natural numbers, what this limit does is answer the question, “What happens when, at every step of some process, I add the next natural number to the total I already have?” It tells us that this process will result in a number which at every step is larger than it was before, and at an increasing rate. I am not succeeding in getting closer to some value when I do this process. This is the proper meaning of what divergence is for this case. This tells us nothing about ACTUALLY adding the natural numbers, which intuitively and arithmetically should have nothing to do with sequences (because if we defined addition by sequences, it could never be commutative or associative, but we know addition is a commutative operator for fields). In fact, it tells us nothing about adding infinitely many numbers in general in the first place. We make the association because we want to and because it is practical in some contexts, but again, they strictly are not the same thing, especially when you understand the mathematical logic behind the axioms and definitions. Obviously, mathematicians tend to understand this, but when students learn calculus, they do not learn any of the rigorous details behind the definitions or theorems involved, so naturally they get confused.

    • @Lolwutdesu9000
      @Lolwutdesu9000 5 ปีที่แล้ว +4

      @@angelmendez-rivera351 this is a brilliant post.

    • @literatedouchebag
      @literatedouchebag 5 ปีที่แล้ว +7

      @@angelmendez-rivera351 i couldn't have said it any better. Amazing post my dude

    • @angelmendez-rivera351
      @angelmendez-rivera351 5 ปีที่แล้ว +8

      VeryEvilPettingZoo “But it’s the only definition that makes any conceptual wrong.”
      And that’s obviously wrong, as mathematicians from the 17th century have proven with their understanding of divergent series, which literally preceded any understanding of limits of sequences. The fact that surreal numbers and transfinite addition exists, without need to use limits and all, further proves this point. You must know any mathematics beyond those of your calculus II textbook if you think it’s the only conceptually sensical definition.
      But the other reason you are wrong is because there is no such a thing as “the ordinary conceptual understanding” of something in mathematics. That doesn’t exist. Mathematics is strictly and exclusively about what axioms you work with. And depending on the axioms, something is true, or it isn’t. And here is the catch: there is no standard set of axioms that is used in every field of research. Even within the same field of research, if we are having a conversation and I decide to get a different level of rigor, even there we’ve already changed the scope of the axioms and of the theory. Because of this, there is no ordinary understanding of anything: any understanding of anything just comes from axioms and that’s that. Math has nothing to do with intuition, and because of this, nothing is ordinary or conventional. That is what people refuse to understand. The only reason some things seem conventional to some people is because they’ve been limited to only specific math courses or they were exposed to something first for the longest time before being taught something they personally would consider “non classical”. If you had been raised with a calculus course learning about Ramanujan summation first and then being exposed to it continuously to work with it in engineering for the rest of your life, then you would perceive that to be the only conceptually ordinary sense to add infinitely many things. But that too would be an illusion. If there were such a thing as an ordinary conceptual understanding, then it wouldn’t be necessary to learn maths in such a way that in every new course, everything you learned previously is a lie and that there is another way to look at things. And look: mathematicians said the exact same thing about complex numbers centuries ago. The fact that people continuously make these claims and centuries later are always disproven is an obvious indication to the fact that such ideas about understanding are subjective and merely illusions, artifacts of tradition, not real in any mathematical or logical sense.
      “...of what it would mean to add up the terms of that series “forever”.”
      There is no such a thing as adding things up “forever” in mathematics. I don’t care if you put it in quotation marks or not: that word should not be in that sentence, not even in a remote, metaphorical sense. You’re projecting feelings and intuition that don’t exist in mathematics into the subject. Adding infinitely many numbers does not have anything to do with time. If I add one by one, then yes it would take me a very long time to finish the process, mechanically speaking, but processes don’t define anything in mathematics. If we can agree that a sum of infinitely many numbers can have a value, then that has nothing to do with time. Talking about time only furthers the misconception about what infinite sums represent notionally. If I have a way of adding infinitely many numbers and knowing what that is, then in principle there is no reason I shouldn’t be able to do this immediately, in less than a picosecond, or faster. And if time was of relevance, then it would be impossible to talk about infinity in the first place, so the concepts of convergence and divergence would make no sense whatsoever.
      “Conceptually, it’s indisputable that adding up the series “indefinitely” drives the sum up towards infinity, not -1.”
      And once again you made the mistake I pointed out in my comment. It’s like you just missed my point altogether. If you have a sequence defined by steps, where in every step, you add the next natural number, then yes, you get a process by which this number will increase to infinity as more and steps are performed, arbitrarily. And unfortunately for your argument, that’s NOT what the sum itself is. Summation is an operator, not a process. Nothing in mathematics in any field is a process. The only field in mathematics that talks about things related to processes may be some subfield of discrete mathematics concerning computing power and what not. But those things don’t define operations, nor should they. A mathematical identity and the process you get by it computationally are strictly unrelated. Perhaps children have a strong association between operations and processes, because it’s the only exposure they’ve ever had of operations, since they cannot really understand the abstract essence of what operations are, but that’s it. If I can add all the powers of 2 at once, then there is no “driving the sum” anywhere because there is no process, there is no sequence. Any extension of an operation should capture this abstract essence of what the operation is rather than any false non/existing notion of a procedure. You can choose to create a mathematics which is based on procedures, maybe define something call procedure theory. But that wouldn’t be arithmetic of real numbers anymore, that would be, well, procedure theory.
      And worse for the argument is that this concept of limit to infinity depends strictly on the type of infinity you are choosing to use as a boundary condition on the real line. Calculus on the projective line looks very different. Which only proves my point further.
      I will watch the video, though I hardly doubt they’ll say anything fruitful I haven’t already addressed, unless they end up agreeing with me. I say this as I’ve been in over 50 different discussions about the subject.

  • @angelmendez-rivera351
    @angelmendez-rivera351 5 ปีที่แล้ว +234

    The discrepancy between saying that the series diverges and the sum is -/12 is that they are not even talking about the same thing. The fact that it diverges is a statement about asymptotic behavior and sequences, whereas the latter is a statement about arithmetic and infinite sets. Calculus is a theory about sets and functions. When we deal with summations in calculus, we never truly deal with an infinite summation, so to speak, although we do call them this out of bad tradition (just like how calling imaginary numbers imaginary is bad tradition). In calculus, what we do deal with instead is sequences of partial sums. Why? Because this tells us about the algorithm of after one number after another. If I start adding the natural numbers, in a specific order, and form a sequence for every step, then what is the behavior as I increase the number of steps? The behavior is that this sequence simply becomes infinite, every number I get is larger and larger on several orders. Although we tend to associate this with adding infinitely many terms, this is not what is truly happening and is merely an informality that happens in the calculus classroom, since explaining the real details behind standard analysis is complicated and outside the scope of the syllabus. In a sense, using the limit of the sequence of partial sums is already a way of assigning values to infinite series. It already is “a summation method”, but it is an error to call it a summation in the arithmetic sense because it obviously is not, since it has very different properties.
    This bears no contradiction with what Ramanujan postulated because Ramanujan is not talking about sequences and their limits. What Ramanujan is trying to do instead is imitate more closely the properties of summation as given by number arithmetic. Naturally, since we are adding elements of infinite sets, the results we produce are counterintuitive and outside of what induction can allow us to prove.
    Keep in mind, though, that using Ramanujan summation is not the only way to arrive at this result. Abel summation and Borel summation are both more intuitive than Ramanujan summation, and they also give -/12 as a result. Also, here is an interesting article by Terrence Tao that justifies this non-classical result in a very convincing way. terrytao.wordpress.com/2010/04/10/the-euler-maclaurin-formula-bernoulli-numbers-the-zeta-function-and-real-variable-analytic-continuation/#zeta-s
    One thing I find interesting is that the integral from -1 to 0 of x^2/2 + x/2 is 1/6 - 1/4 = 2/12 - 3/12 = -1/12. It is interesting because this integral is the area between the x-intercepts of the function f(x) = x^2/2 + x/2 = x/2•(x + 1), which is equal to the nth partial sum of the sequence of natural numbers for x = n.

    • @user-ft2vp5yw6p
      @user-ft2vp5yw6p 5 ปีที่แล้ว +7

      Wow, just wow. Amazing

    • @noname_whatsoever
      @noname_whatsoever 5 ปีที่แล้ว +15

      Very well written. This clarifies what seems contradictory when the topic is usually discussed without a proper perspective. Thank you.

    • @DanNguyen-oc3xr
      @DanNguyen-oc3xr 5 ปีที่แล้ว +3

      "Naturally...counterintuitive." Damn it.

    • @suprafluid3661
      @suprafluid3661 5 ปีที่แล้ว +1

      @@DanNguyen-oc3xr But i was going to say that hmmm.. 😣

    • @abustefano8225
      @abustefano8225 5 ปีที่แล้ว

      Mmmm... Something wrong here.
      According to Abel-Olana formula en.m.wikipedia.org/wiki/Abel%E2%80%93Plana_formula the series diverges.
      Please elucidate

  • @dayzimlich
    @dayzimlich 5 ปีที่แล้ว +79

    One of your best videos yet - keep up the great positive attitude in 2019!

  • @nekososu
    @nekososu 5 ปีที่แล้ว +92

    or you should say the zeta(-1) is -1/12

    • @abhiruppaul5601
      @abhiruppaul5601 3 ปีที่แล้ว +3

      correct bro

    • @arnoldo-probjeto3111
      @arnoldo-probjeto3111 2 ปีที่แล้ว

      Not correct bro. In fact, ACzeta(-1)= -1/12, where ACzeta is the analytic continuation of zeta function, that is NOT the zeta function.

    • @19divide53
      @19divide53 2 ปีที่แล้ว +1

      @@arnoldo-probjeto3111 But we call the analytic continuation of zeta function by ζ(s) as well. A bit of abuse of notation but I think that's the convention. In fact, in Riemann's 1859 paper he did denote the analytic continuation of zeta function (sum of n^(-s) over all positive integers n) ζ(s), which you can see by looking at the paper online.
      There's no reason to say ζ(s) may only be the sum of n^(-s) over all positive integers n. When I'm doing some other problem unrelated to the Riemann Zeta function, I could define a function, say, s^4sin(3s)-cos^5(s^2)+6/s-9/s^7, and call that ζ(s). That's just as valid as calling my function f(s) or g(s).

  • @benjaminbrat3922
    @benjaminbrat3922 5 ปีที่แล้ว +38

    Thank you very much for this much-needed relativism when talking about divergent series. You could go even further by presenting several alternative summations (Cesàro, VP, Lambert, Borel, etc), I know Cesàro to be quite easy to grasp, and this would contribute bringing diverging sums enough breathing room for actual exploring, instead of bantering. Happy New Year!

  • @elthomaso10
    @elthomaso10 5 ปีที่แล้ว +14

    This is hands down the most terrifying video title I've ever seen.

  • @spudhead169
    @spudhead169 2 ปีที่แล้ว +82

    Thank you, both Numberphile and Mathologer didn't really explain this properly, that it's a "non-canon" summation.

    • @rykehuss3435
      @rykehuss3435 7 หลายเดือนก่อน

      Nice way of saying its just made up by Ramanujan to goof around with

  • @YourPhysicsSimulator
    @YourPhysicsSimulator 5 ปีที่แล้ว +103

    So elegant... I'm talking about you, though.

    • @blackpenredpen
      @blackpenredpen  5 ปีที่แล้ว +17

      Thanks!!

    • @punambanik5310
      @punambanik5310 หลายเดือนก่อน

      @@blackpenredpen sir, can you please tell me the name of the formula you used to find the summation??

  • @youtubecommentsguy9805
    @youtubecommentsguy9805 3 หลายเดือนก่อน +1

    That whole video was the kind of vibe it was in high school when you cannot follow a single step what the math teacher is teaching you understand nothing but don‘t dare to ask because you feel like he does a good job and is a genuine friendly guy so you don‘t want to interrupt him.

  • @angelmendez-rivera351
    @angelmendez-rivera351 5 ปีที่แล้ว +12

    UPDATE: I found that if one takes the polynomial in n of degree s + 1 that gives you the sum 1^s + 2^s + ••• + n^s, then if we integrate the same polynomial in x with respect to x from -1 to 0, one obtains the same value one would obtain if one applied Ramanujan summation instead. The key is in using Faulhaber’s formula, finding the antiderivative of it in x, where n =
    x, then set x = -1, and the resulting formula is equal to -B(s + 1)/(s + 1), where B(s) is the s-th Bernoulli number. This gives the same result as Ramanujan summation, which also gives the analytic continuation of ζ(s). I’m mentioning it because I thought it was interesting.
    So this generalizes the result from my first comment.

    • @submarino006
      @submarino006 ปีที่แล้ว +6

      I like your funny words, magic man

  • @biswadeepghosh5568
    @biswadeepghosh5568 5 ปีที่แล้ว +18

    Great presentation, felt so good since this concept is related to the work of Ramanujan, many thanks to help me understand this concept.

  • @martind2520
    @martind2520 5 ปีที่แล้ว +83

    This is awesome.
    Can you do a video proving that Ramanujan Summation is consistent with regular summation for non-divergent series?

    • @MrLecancre
      @MrLecancre 5 ปีที่แล้ว +3

      Try with cv riemann series

  • @SebastienPatriote
    @SebastienPatriote 5 ปีที่แล้ว +10

    This just went next level!!

  • @jamesnapier3802
    @jamesnapier3802 ปีที่แล้ว +2

    The infinite series 1+2+3+... never converges to -1/12. Claims to the contrary are simply false.

    • @stratonikisporcia8630
      @stratonikisporcia8630 ปีที่แล้ว +2

      I does not converge, it diverges to an infinite number that can be represented as -1/12 but is not EQUAL to -1/12

  • @fCauneau
    @fCauneau 5 ปีที่แล้ว +3

    That's what I call a Christmas gift ! Thanks !!! And Merry Xmas to you and your readers !!

  • @federicopagano6590
    @federicopagano6590 5 ปีที่แล้ว +44

    we have 2 options depending on which class we are in. But wich one is the correct answer if u are alone no classroom and u have to answer

    • @blackpenredpen
      @blackpenredpen  5 ปีที่แล้ว +36

      That will be depending if I want to make my life easy or not.

    • @federicopagano6590
      @federicopagano6590 5 ปีที่แล้ว +3

      blackpenredpen OK got the point diverges lol

    • @angelmendez-rivera351
      @angelmendez-rivera351 5 ปีที่แล้ว +2

      Federico Espil He did not say that. Obviously you want him to say that, though, because you already are prejudiced and already believed beforehand the sum diverges. I wrote a comment addressing this.

    • @shoobadoo123
      @shoobadoo123 5 ปีที่แล้ว +2

      When applied in the real world, -1/12 is the answer. This appears in physics, string theory specifically. You can google to learn more there’s a lot of info!

  • @sanatankaushik456
    @sanatankaushik456 9 หลายเดือนก่อน +3

    This is the power of the "Man who knew Infinity"!

  • @djsmeguk
    @djsmeguk 5 ปีที่แล้ว +64

    What would be interesting is how the ramanujan summation formula is derived.. does it concur with convergent series as well?

    • @angelmendez-rivera351
      @angelmendez-rivera351 5 ปีที่แล้ว +4

      djsmeguk I believe the answer is yes, but I’m not 100% certain.

    • @nathanisbored
      @nathanisbored 5 ปีที่แล้ว

      i dont think its derived, its just a definition

    • @angelmendez-rivera351
      @angelmendez-rivera351 5 ปีที่แล้ว +5

      nathanisbored It is inspired by some derivation. The definition only plays in a role in the domain of functions to which it applies. It is a function of functions.

    • @angelmendez-rivera351
      @angelmendez-rivera351 5 ปีที่แล้ว +5

      Markus Steiner “I think it's neither derived nor it's just arbitrary.”
      Be more specific with what is it that you mean when using the word “derived”. This may not have a derivation from the axioms, but it has a rigorous foundation on time-scale calculus, which is a theory of which the calculus of sequences is a special case. It also has equally rigorous foundation in complex functional analysis and set theory. It uses the projective extension of the complex plane, known as the topological Riemann sphere. Also, it is not arbitrary, because it can be shown that, given any argument from heuristics, the continuation entailed by the heuristics is formalized with this method presented in the video. If any continuation to summation should exist so that divergent series could be evaluated, then this must be the one. Namely, had the method of convergence of the sequence of partial sum never existed, the field axioms of addition would heuristically entail these results.
      “The thing is that it also has to work for not divergent series.”
      It does. In his following video, which sums all the square numbers of the natural numbers, I wrote in the comments section that it is easy to prove that this series sums every convergent geometric series to its correct value, and it appears as though it does so with series involving trigonometric functions as well, as well as for the sum of all 1/n^2 for n in N.
      “So there might be more possible formulas which achieve this with different results for divergent series.”
      There are. Borel summation exists, as well as Abel summation and stronger linear methods. Wheel algebra and transfinite set theory can also derive these results independently.
      “Choosing one of these possibilities is in fact arbitrary.”
      No, it is not. If two different theories derive the same conclusions, then this entails the theories are, at the very least, consistent, but it could be the case that one is a sub-theory of the other, or even more radically, that given some super-theory containing both theories, that they are equivalent theories. Being able to prove the law of cosines using either Classical Greek geometry, or else using a Hamiltonian algebra of 4-ions does not mean that choosing either theory as the foundation for a method to obtain results is arbitrary. That is not how math works, obviously, nor has it ever been this way.

    • @sl.murarikumar9675
      @sl.murarikumar9675 5 ปีที่แล้ว

      th-cam.com/video/odn6weKzk1Y/w-d-xo.html
      Ohhhhhhh Nooooooo
      Ramanujan questions answer is right or wrong
      Very confusing
      -1/12. OR. -1/8 🤔🤔🤔

  • @late7245
    @late7245 5 ปีที่แล้ว +80

    1-1+1-1+........=1/2 confirmed

    • @hamsterdam1942
      @hamsterdam1942 5 ปีที่แล้ว +2

      Nope

    • @xevlonperc
      @xevlonperc 5 ปีที่แล้ว +2

      No, it's 0.

    • @late7245
      @late7245 5 ปีที่แล้ว +7

      (-1)^inf = 0 so (1-(-1)^inf)/(1-(-1)) = 1/2 like Ramanujan

    • @angelmendez-rivera351
      @angelmendez-rivera351 5 ปีที่แล้ว +1

      Xevlon Perç How would it be 0?

    • @angelmendez-rivera351
      @angelmendez-rivera351 5 ปีที่แล้ว +1

      Георгий Шередеко The results of the video imply the equation.

  • @basedoppenheimer1497
    @basedoppenheimer1497 ปีที่แล้ว

    Bro I don't even know what to say. This is mind blowing in such ways you feel like you got transported to another dimension.

  • @beatoriche7301
    @beatoriche7301 5 ปีที่แล้ว +17

    Great video! If I may ask, how do you actually derive this formula?

  • @harshitkumar4760
    @harshitkumar4760 5 ปีที่แล้ว +2

    It means that negative numbers are greater than positive and smaller too, it means its a cycle which repeats positive after negative and again positive. Think it this way as we increase the angle in tangent function its value reaches to infinity and then negative! And then again positive.

  • @matthiashannesson7239
    @matthiashannesson7239 5 ปีที่แล้ว +26

    -1/12th?

  • @NoNTr1v1aL
    @NoNTr1v1aL 5 ปีที่แล้ว +2

    Thank you Ramanujan, very cool!

  • @sohamkumar2346
    @sohamkumar2346 5 หลายเดือนก่อน +1

    Love from India 🫡 Proud of Ramanujan

  • @jzanimates2352
    @jzanimates2352 5 ปีที่แล้ว +27

    You should make a collab video with 3blue1brown or numberphile!

  • @jjeherrera
    @jjeherrera 5 ปีที่แล้ว +9

    Nice as always. Still, it would be interesting to understand what is Ramanujan doing that helps him to make the analytic continuation.

    • @science-y9209
      @science-y9209 3 ปีที่แล้ว +1

      Ramanujan is dead but he was a genius..

  • @lautamn9096
    @lautamn9096 5 ปีที่แล้ว +5

    Happy new year bprp!

  • @anindyabiswas1551
    @anindyabiswas1551 5 ปีที่แล้ว +1

    I've waited a long time for this video. Thank you very much.

  • @mitchelvalentino1569
    @mitchelvalentino1569 5 ปีที่แล้ว +4

    Yes!!! I’ve been waiting for this exact content. Very well explained. Thank you!!

  • @angelmendez-rivera351
    @angelmendez-rivera351 5 ปีที่แล้ว

    Another way in which these results make sense is in wheel theory. The field of complex number can be extended by first equipping it with an involution operator / that satisfies certain properties. Then we introduce to new elements to the complex number, /0, and 0/0. Every element of this new set has a well-defined involution: for all z, /z is well defined. Whenever z^(-1), which is the reciprocal of z, or multiplicative inverse of z, exists, z^(-1) = /z, but even for z with no multiplicative inverse, /z is well-defined. Namely, /0 = ψ and 0/0 = θ, with the properties that /ψ = 0 and /θ = θ. Also, ψ + ψ = ψ - ψ = θ, ψ + a = ψ for any complex number a, 0ψ = θ, and aψ = ψ for any complex nonzero a. Furthermore, θ + z = yθ = θ for all wheel numbers z & y (by wheel numbers, I mean complex numbers plus the two new elements we added to the field, which is now a wheel). There are some identities I have not given concerning / for all these, though right now I cannot remember them all. But there is a Wikipedia article you can find if you simply search Wheel algebra on google.
    We can give this wheel the wheel topology. With this wheel topology, 0 and ψ are boundaries of this space. As such, ψ somewhat plays the role of infinity in this space, with a few key differences, since now this is the only infinity regardless of the direction.

  • @blazedinfernape886
    @blazedinfernape886 5 ปีที่แล้ว +71

    The views should be -1/12

    • @kishanthakor971
      @kishanthakor971 4 ปีที่แล้ว +1

      😂😂yaaa

    • @gabbarisback6052
      @gabbarisback6052 4 ปีที่แล้ว

      😂😂

    • @shivamchouhan5077
      @shivamchouhan5077 3 ปีที่แล้ว +1

      🤣

    •  3 ปีที่แล้ว +1

      your comment is at 69 likes already, so I'm using *this* comment as a like button instead

    • @pardeepgarg2640
      @pardeepgarg2640 2 ปีที่แล้ว

      @ I ruined that 69 likes 😈😈

  • @SartajKhan-jg3nz
    @SartajKhan-jg3nz 5 ปีที่แล้ว +1

    Everything in the video is🔥🔥🔥. The integral, the result and yes...you!

  • @maccook9951
    @maccook9951 5 ปีที่แล้ว +2

    At about 3 minutes in I had to actually check this wasn't uploaded April 1st

  • @adamwalker8777
    @adamwalker8777 2 ปีที่แล้ว +2

    If I take 1,2,3... coins from every inhabitant of the multiverse, then I will remain in debt.

  • @unironicaluser1867
    @unironicaluser1867 8 หลายเดือนก่อน +3

    i understood until about 0:17

  • @dppid083wk7
    @dppid083wk7 5 ปีที่แล้ว +1

    Love ramanujans work

  • @samueldeandrade8535
    @samueldeandrade8535 11 หลายเดือนก่อน +4

    I am not the biggest fan of blackpenredpen, but I have to say that from the several youtubers I saw talking about this, he was the most respectiful, intelligent and interesting. Simply amazing.

  • @kenhaley4
    @kenhaley4 5 ปีที่แล้ว +6

    Very nice! Without your depth of knowledge, I have explained to others that saying that the infinite sum of the positive integers equals -1/12 is simply an extension of our notion of infinite sums that is useful in certain circumstances. Your video confirms my explanation.
    But I miss you saying "isn't it?" as much as you used to.

    • @blackpenredpen
      @blackpenredpen  5 ปีที่แล้ว +2

      Awww thank you!! I think I say "well well" more often nowadays and I don't even know why. : )

  • @ToHoUSA1
    @ToHoUSA1 5 ปีที่แล้ว +3

    ive been waiting for this

  • @stevenjohnson9466
    @stevenjohnson9466 5 ปีที่แล้ว +2

    this dude loves simple maths you can see it in his smile :)

  • @batmanthedarkestknight
    @batmanthedarkestknight 11 หลายเดือนก่อน +1

    "I didn't make this up " made me laugh so much

  • @ulilulable
    @ulilulable 5 ปีที่แล้ว +5

    My reaction at 3:00 "what the actual... what the ... what‽"

  • @somnathdash4428
    @somnathdash4428 5 ปีที่แล้ว +1

    You got addicted to India!!! Love from India

  • @nicolasgoubin
    @nicolasgoubin 5 ปีที่แล้ว

    Whaaaaaaah so HANDSOME ! Merry Christmas & Happy New Year YAAAAAAAY

  • @tylertorsiello8450
    @tylertorsiello8450 3 ปีที่แล้ว

    this guy is my spirit animal

  • @archithtelukunta4599
    @archithtelukunta4599 5 ปีที่แล้ว

    Just few days ago I was just thinking whether u would ever upload a video on this series and here it is😃

  • @kimothefungenuis
    @kimothefungenuis 5 ปีที่แล้ว +6

    Better than numberphile

  • @anweshaguha7366
    @anweshaguha7366 5 ปีที่แล้ว +2

    Okay, so I'm in love with that "Hmm" before you start solving a tough integral, I mean tough for me😊

  • @b77vedantmore51
    @b77vedantmore51 ปีที่แล้ว +3

    Now. seeing this video....
    'Yes -1/12 '
    next video 'not-1/12'

  • @pianochannel100
    @pianochannel100 3 ปีที่แล้ว +1

    Its the characteristic number of the summation, im not sure that saying the sum is actually equal to -1/12 is right

  • @kostagerosky534
    @kostagerosky534 5 ปีที่แล้ว +1

    This video was so enjoyable, you explain things so nice!

  • @ayushrathore9190
    @ayushrathore9190 5 ปีที่แล้ว +105

    Watching this at 2:45am. Any freaking maths lover like me?

  • @akk92278
    @akk92278 3 ปีที่แล้ว +1

    Although the Ramanujan summation of a divergent series is not a sum in the traditional sense, it has properties that make it mathematically useful in the study of divergent infinite series, for which conventional summation is undefined. ...

  • @integrando1847
    @integrando1847 3 ปีที่แล้ว +1

    very interesting that maths say the same thing in a lot of ways, this summ appears in quantum mechanics, infinite series, complex variable, etc..

  • @harshranjan8526
    @harshranjan8526 5 ปีที่แล้ว +1

    Ramanujan Summation WOW.

  • @jorgecanales4864
    @jorgecanales4864 4 ปีที่แล้ว +9

    Si lo tuvieras tus videos con sub titulos en español, serian aun mas geniales, eres un genio

    • @Podzhagitel
      @Podzhagitel 3 หลายเดือนก่อน

      has aprendido inglés?

  • @ianprado1488
    @ianprado1488 5 ปีที่แล้ว +7

    How many markers do you buy a month?

  • @raiedahmednishat8883
    @raiedahmednishat8883 5 ปีที่แล้ว

    You even dresses up for it.
    I love you man.
    あなたおあうしている

  • @adamhrankowski1298
    @adamhrankowski1298 5 ปีที่แล้ว

    Thumbed up without even watching. Loved Mathologer's vid. Have this stuff on a T-shirt. Really looking forward to what BPRP has to offer. #Yay

  •  5 ปีที่แล้ว

    Take that, Mathologer

  • @ssaamil
    @ssaamil 2 ปีที่แล้ว

    -1/12 is my favourite number. I love this.

  • @debabrataadhikari4879
    @debabrataadhikari4879 5 ปีที่แล้ว

    Out of all yt channel this is the best explanation

  • @peterheerens3093
    @peterheerens3093 2 ปีที่แล้ว

    It always amazes me how many way there are to prove 1+2+3+4+5+...... = -1/12. It is counterintuitive, but you cannot argue with the prove

  • @QuippersUnited
    @QuippersUnited 5 ปีที่แล้ว

    Quite the dapper jacket, Mr. Pen.

  • @moiqtheplayer
    @moiqtheplayer ปีที่แล้ว +1

    Something's wrong with Ramanujan's summation, although you made excellent explanation, I still disagree due to some invalid maths that Ramanujan did, but I don't think you guys realize it, do you?

  • @SupratheekSreedharaNagaVenkata
    @SupratheekSreedharaNagaVenkata 7 หลายเดือนก่อน

    @blackpenredpen 10:54 u can just say integral 1/x from -1 to 1 is zero bcoz 1/x is odd function so areas are equal in magnitude from -1 to 0 , 0 to 1 but opposite in sign

  • @matteoserafini7704
    @matteoserafini7704 2 ปีที่แล้ว

    For 1/X you just notice that the function in odd, so in a "simnetrical" interval the area in the positive part of the interval is the same of the area in the negative part of the interval, but with the opposite sign. So the sum of the two is zero

  • @scarbotheblacksheep9520
    @scarbotheblacksheep9520 5 ปีที่แล้ว +3

    If "diverges" and -1/12 are correct depending on how you think of it, could the domains of these be different? Like, is the Ramanujan summation including transfinite numbers in its sum, or something like that?

  • @sugarfrosted2005
    @sugarfrosted2005 5 ปีที่แล้ว +3

    Fun with analytic continuation!

  • @mulongoduncan9308
    @mulongoduncan9308 3 ปีที่แล้ว +1

    Thank you. Your derivation makes much sense.

  • @olegt962
    @olegt962 5 ปีที่แล้ว

    In fact we can say that if a serie converges conditionally or diverges, by Riemann's theorem there exists an arrangement of serie such that converges for any k real we want.

  • @procerpat9223
    @procerpat9223 3 ปีที่แล้ว

    The Ramanujan Summation is pure fiction

  • @rainbow-cl4rk
    @rainbow-cl4rk 5 ปีที่แล้ว +3

    Now calculate zeta(s) with ramunajan summation

  • @lewisbulled6764
    @lewisbulled6764 5 ปีที่แล้ว

    *Mathologer has entered the chat*

  • @coursmaths138
    @coursmaths138 2 ปีที่แล้ว

    Once upon a time, there was a group of French people who had always lived only in Paris. They had seen nothing else. One day, they had the idea to formalize what a human could be. So they looked at the humans directly at their fingertips, and listed different properties to try to characterize them. Since they had living examples of humans satisfying all these properties, it was clear that their properties characterized the humans of Paris. Which meant, in their minds, humans at all (having seen nothing else). One of these properties was "A human necessarily likes cheese". All humans in Paris satisfied it. But a far-sighted scientist thought that this property did not necessarily seem to be attached to the intrinsic notion of human itself, and that the choice of this property to characterize a human seemed arbitrary. So he tried a new list of properties by removing this property ("like cheese"). He unrolled the implications, and found with surprise that nothing in his calculations opposed the existence of such "objects" (humans not liking cheese). However, the shocked Parisians claimed loud and clear that it was "absurd", that one had never seen "someone who didn't like cheese", and "that these people couldn't exist". It was also heard that "they couldn't really be human". The idea was proposed to burn the scientist at the stake. To save his life, he had to flee his hometown and settle elsewhere.
    Time passed, and our scientist finally met humans in distant lands who did not like cheese. So he had found an example of existing objects, satisfying the properties he had posed. He returned to his city and presented them to the Parisians. The skepticism was palpable. They looked at them very fixedly. Then, after several days of observation, they finally had to face the facts: there were real humans who did not like cheese. Although this property seemed intuitive and natural to them, the facts seemed to show that their intuition (probably conditioned by their environment) was wrong. It now seemed very unreasonable to redefine the notion of human, to exclude those who did not like cheese. Because in them, everything worked almost like the humans they were used to. Time passed, and it was finally accepted that these individuals were indeed humans. They settled down and eventually settled in Paris. With even more time, it turned out that these humans even made an important civic contribution (through their work, knowledge and skills, ...) to this new, and richer, beautiful city of Paris. 🙃

  • @akshatsharma9882
    @akshatsharma9882 4 ปีที่แล้ว

    I love this guy.

  • @wolframalpha8634
    @wolframalpha8634 5 ปีที่แล้ว +1

    Happy new year bprp

  • @kamidhunkumar3021
    @kamidhunkumar3021 5 ปีที่แล้ว

    Integration of 1/x from -1 to 1 seems to be elementary. The definite integration is introduced as the area under curve and it is evident that the area ' enclosed '(l mean symmetric with respect to origin) by 1/x in the 1st and 3rd quadrants cancel each other.

  • @CosmicGoat-d3o
    @CosmicGoat-d3o ปีที่แล้ว +1

    I don't get it. adding positive numbers should be a positive number right?

  • @billmorrigan386
    @billmorrigan386 3 ปีที่แล้ว +3

    Ramanujan is a genius but Euler was the first to find that 1+2+3+....should converge to -1/12, although his method was different. It's fascinating to see that zeta function plays such a huge role in nature when we see Casimir effect and have to deal with negative energy density. That's the triumph of science and logic! Great video by the way. I'm subscribing.

    • @DTLRR
      @DTLRR 10 หลายเดือนก่อน

      So what's the real significance of it? In other words, what does it show or mean?
      I am confused. Does it converge or diverge?

  • @thingthingthingthingthingthing
    @thingthingthingthingthingthing 3 หลายเดือนก่อน

    Guys remember Riemann zeta function? -1 which is 1+2+3… seems to be going to -1/12

  • @EduardoHerrera-fr6bd
    @EduardoHerrera-fr6bd 5 ปีที่แล้ว

    Finally! I was specting for this including if I had to go for 2 weeks :c
    7:13 Balls Integral.

  • @fmakofmako
    @fmakofmako 5 ปีที่แล้ว +4

    Would it be possible for you to do a video on analytic continuation or smoothed sums? Both have relevance to this video and the riemann zeta function.

  • @Gezraf
    @Gezraf 8 หลายเดือนก่อน

    the "2" you wrote in 7:03 is the most beautiful 2 ive seen

  • @S1nwar
    @S1nwar 5 ปีที่แล้ว

    these values that can be assigned to non converging sums.. they seem more like a unique name label than an actual existing property of the sum.

  • @jevaughnclarke6174
    @jevaughnclarke6174 ปีที่แล้ว +1

    Maybe these sums have a greater meaning and we are not yet smart enough to know their meaning.

  • @TheNachoesuncapo
    @TheNachoesuncapo 5 ปีที่แล้ว +1

    looking good steve!

  • @김간디17
    @김간디17 4 ปีที่แล้ว

    The last two examples are appropriate!

  • @guilhermefreire8093
    @guilhermefreire8093 5 ปีที่แล้ว +6

    Can someone please explain me how he got to that first formula??? It makes zero sense to me

    • @JonJonFtheW
      @JonJonFtheW 5 ปีที่แล้ว +6

      The Ramanujan summation formula? He didn't "get" to it, he just wrote it down. The Wikipedia page screenshot is how you'd arrive at the formula.

    • @jjeherrera
      @jjeherrera 5 ปีที่แล้ว +1

      The truth is we ignore how he got many of his results, even though people have been able to come up with proper demonstrations. He was an exceptional genius.

    • @adrienanderson7439
      @adrienanderson7439 5 ปีที่แล้ว

      Sometimes you have to make an assumption that something is true in order to work with it, for instance I can take the derivative of something like x^3+3x^2+5 ( which is 3x^2+6x ), using the power rule, but i might not explain why the power rule works because its explained already somewhere else(en.wikipedia.org/wiki/Power_rule) and it would make finding derivatives take a long time to have to explain every time you do an operation thats maybe not + - / * or ^.

    • @guilhermefreire8093
      @guilhermefreire8093 5 ปีที่แล้ว

      @@adrienanderson7439 no this is different, because i assume that most of the audience does not understand ramanujan summation. More important than the derivation would be understanding just how a divergent series can be assigned a finite value.

  • @cagnusmarlsen4050
    @cagnusmarlsen4050 5 ปีที่แล้ว +1

    I love confusing my math teacher watching your videos :D.

  • @sahir313
    @sahir313 4 ปีที่แล้ว

    Sreenivasa Ramanujan is truly genius.

  • @meta04
    @meta04 3 ปีที่แล้ว +1

    3:03 Why _wasn't_ I expecting you to have played that...

  • @tensoescalar1
    @tensoescalar1 5 หลายเดือนก่อน

    This is a very impressive video, thank you very much, greetings from Mexico.