My tip to juniors to score 95% + in 10th Boards 1. Watch Lecture from TH-cam 2. Make Notes 3. Solve Last 10 Years for Each Subject 4. Solve 10 Sample Papers for Each Subject 5. Solve Text Book Exercises along with Examples
I was searching Mole concept video from the last two months. But I have not understood a bit...Sir this video became so much helpful to me that I cannot express through my words.. I wanted just like this video which could clear my basics.. Your explanation is really next level..Thank you Sir for all your efforts.. 🎉🎉
Sir with utter respect... I want to clarify a mistake that in the numerical in which we had to find the no of electrons present in 1.6g of methane, the answer will be 6.022*10 to the power 23 becoz it will also get multiplied by the no of electrons present in the compound methane which is 10
Really Thank you sir I’m having a test based on this tomorrow and this effort of yours really helped to understand the confusing portions of this chapter🙏🙏 Really proud to see Banarasi acing everywhere proud to be one🙏🙏
@Sony sub it's very simple....just understand the concept... it's physical chemistry...or physical chemistry thodi tough hoti hi hai.... numericals practice karo 🤟🏻
@@uniquenessandclassy just figure out... what is given in the question and what you're required to find out...... To get expert in numericals....just try as much questions as you can
Thankyou sir for your efforts. When I didn't come in your video and only study by book,I thought that this chapter is very tough and I can't do it but in this video is make this chapter very easy . Thankyou sir again ❤❤❤❤
Sir you explained the concept in a simpler way and i could cope up with your teaching and i think now I can do well in my exams by practicing more. Thanks alot sir🙏
My favourite teacher is sir tarun rupani i was really afraid regarding my English performance but suddenly found someone ready to help me on TH-cam and it was you sir ❤❤❤❤❤.Plz sir continue making such amazing videos
Q) 200ml of C2H4 is burnt in just sufficient air (containing 20% of oxygen) as per the equation - C2H4+3H2O = 2CO2+2H2O. Calculate the resultant mixture composition (at 100°C and constant pressure) Q) A mixture of 10cm³ of CO, 60cm³ of H2 and 25cc. of CH4 are mixed with 750cm3 of air (containing 20% oxygen) and ignited. Calculate the composition of the resultant mixture on cooling to room temperature.
Thank u so much sir 🥰❤ I have my H.Y exam tmrw & I didn't know anything in mole concept not a single numerical but after this I'm able to solve most of the ques from book even from PYQs also 😇 Sir is God for us ❤
Tarun Sir, thank you so much for making us learn these topics. it was very enriching. I searched this topic a lot and saw few videos also but yours was the best. Now I am confident about this topic. i liked and subscribed your channel. 👍
Thank you ..thank you very much sir .i was really unknown to this chapter before but now it's clear just because of you.Thank you sir gor your much efforts for us.Pray for your good health..
I had been struggling to understand the concept of mole concept since a week... But after watching this video I understood the whole part.... Thank you sir for the great explanation
Thank you sir for your marvelous presentation of this concept which you did last year helped us this year also And I will ask classes for some topics in future,l hope you do that need full to us 👍😊 l will be waiting for your reply
Who are going to give chemistry exam on Monday.....Best of luck
👇
Me🥲
Same to u bro
Thanku bro
Dhanyavad Bhai 🫂🙏🏻
Sukhriya Bhai
Kon kon sir ke videos ko 1.5x pe dekhta h😁😅
Editor= guys tq soo much for this many likes, chlo God bless sab ke paper ache jae..stay blessed ❤
Tumhare baap log
No bro it's 2 x 😢
Me on 2x
Nhi bro....hm to 4x me dekhte hai
Me 2x
U TEACH BETTER THAN MY CHEMISTRY TEACHER
Is your preparation completed?
@@ayush9598 same doubt bro
True bro
Same
Comment karna chodoo aur padhai Karo Bhai log 😅😅
He makes us understand stuff in one video which we dont understand in almost a whole year .
Absolutely
Frrr
true\
You understand this in one video because you were practicing it for whole year
True...😅
Jis jisko chemistry mein 80/80 chahiye wo like karo 👇👇
Did you get??
@@emaki_draws_anime Roast bhai roast 🤣🤣
Who want 4x for sir tarun rupani's video ⏩⏩⏩
True😢 2x is not enough
5:26 numericals on gay lussac law
People who didn't study anything 😭😭😭😭😭😭😭😭😭😭😭😭😭 like karo
😅😅😅😂😂 mai to mai batch me huu class abhi chalu hi hua hai
Who else's watching one night before exam??XD btw all the best for your chemistry exam
tomr ❤🎉
Finally Mole concept ho gaya, ab chemistry faad ke auga :)
Mai to abhi krne baitha hu sar ke upar se sab par hora😅 mole concept krle ge to 15 marks to uth hi jaye ga😃👍
Tomorrow exam ha
Best of luck 🎉
2024 -2025 batch attendence
Like
Bhai ab tk toh tumhara syllabus finish ho gya hoga ?
59:53 q-4 answer will be 6.022 * 10^24 electrons
KON KON AAJ DEKH RAHA H 😂
😢
mei
😢
Me
Aapan
My tip to juniors to score 95% + in 10th Boards
1. Watch Lecture from TH-cam
2. Make Notes
3. Solve Last 10 Years for Each Subject
4. Solve 10 Sample Papers for Each Subject
5. Solve Text Book Exercises along with Examples
Hello!😅
😊Are you also a pokemon fan?
Plz, replay
😢I am waiting!
😢😢😢😢😢😢
I was searching Mole concept video from the last two months. But I have not understood a bit...Sir this video became so much helpful to me that I cannot express through my words.. I wanted just like this video which could clear my basics.. Your explanation is really next level..Thank you Sir for all your efforts.. 🎉🎉
Acha majak tha... Kya joke mara re tune 😂😂
Hey sir !! Pls do it for 2024-2025 session questions 😢
Koi Bkl hi hoga Jo sir ke videos ko 1x se upper dekhta hoga 😂
(Bohot khass log)😂😂😅
2 hours before chemistry paper 1:19:33
Sir with utter respect... I want to clarify a mistake that in the numerical in which we had to find the no of electrons present in 1.6g of methane, the answer will be 6.022*10 to the power 23 becoz it will also get multiplied by the no of electrons present in the compound methane which is 10
i was quite literally searching for this comment
Really Thank you sir I’m having a test based on this tomorrow and this effort of yours really helped to understand the confusing portions of this chapter🙏🙏
Really proud to see Banarasi acing everywhere proud to be one🙏🙏
This chapter is tough .......gas law was best in class 9th 😢....
Yes actually 😢
1:13:19 sir can we use VD formula for this ques?
VD- Mass of gas/2
then RMM=2*VD
???
Yes yes why not
Yes of cause
Monday ko Jo koi exam dega like kro
merq birthday hai monday ko🙂🦷🙂
@@anushkajaiswal7502happy birthday in advance
@@anushkajaiswal7502 party
Nhi denge. Koi jabardasti hai 😂
Me
Watch 1 night before 2024 exam 💀🗿
Thx god not alone 😂
😂😂
watching on day of exam☠☠☠
Me watching 6 hours left of exam ☠️
@@cutelifewhenyoulike8193 all the best 💀
1:50:27 this line is heaven
Dear Juniours !..If anyone want any help in chemistry...then you all can tell your doubts 🤟🏻
@Sony sub it's very simple....just understand the concept... it's physical chemistry...or physical chemistry thodi tough hoti hi hai.... numericals practice karo 🤟🏻
@sonysub7029mole concept to ekdam achhe se padh lo
11th me 1st chapter hi he
How to deal with the numericals?
@@uniquenessandclassy just figure out... what is given in the question and what you're required to find out......
To get expert in numericals....just try as much questions as you can
@@anay_gupta__ Thanks for your suggestion....Just one qns I want to ask....what is more important solving pyqs/sample paper?
Ko n kon 2x pe dekh raha h
Me😅
20 days left still I have hope😎
Thankyou sir for your efforts. When I didn't come in your video and only study by book,I thought that this chapter is very tough and I can't do it but in this video is make this chapter very easy . Thankyou sir again ❤❤❤❤
Ediot, he is earning for himself
@@zunaidmondalmondal318 First learn the spelling of 'idiot' and then talk
Sir you explained the concept in a simpler way and i could cope up with your teaching and i think now I can do well in my exams by practicing more. Thanks alot sir🙏
army💜
1:17:51 Stoichiometry
My favourite teacher is sir tarun rupani i was really afraid regarding my English performance but suddenly found someone ready to help me on TH-cam and it was you sir ❤❤❤❤❤.Plz sir continue making such amazing videos
For finding the volume can we take the given volume of reactant as well as product for finding 1 volume ?
Kon kon sir ki vedio 2x pr dekhta h , specially exam time
🖐️
Me
Itss meeee
Bhai spelling error aur voh bhi 10th icse.... Wah bhai.... Topper re
Video rehta hai vedio nhi
Lol Today is board exams in 2hrs and im watching it now.Thanks sir for simple explanation now I can relax 😅😅😅😅
Samee😂😂😅😅 I can relax too now😂
ab toh top karenegh.. 😂😭💗✨
He is the most hard working teacher in youtube now
Watching it 16 hrs before boards, don't worry this is a revision for me😊
Q) 200ml of C2H4 is burnt in just sufficient air (containing 20% of oxygen) as per the equation - C2H4+3H2O = 2CO2+2H2O. Calculate the resultant mixture composition (at 100°C and constant pressure)
Q) A mixture of 10cm³ of CO, 60cm³ of H2 and 25cc. of CH4 are mixed with 750cm3 of air (containing 20% oxygen) and ignited. Calculate the composition of the resultant mixture on cooling to room temperature.
Sir did the 1st one
Ye kya hai 😭
40 and 400
41:21 sir mole ki value 6.023×10 23 hai sir
Seeing the video 3 hr before the board exam 😅😅.... I am having my boards exam at 11:00 and I am here at 9 😅😅
Can anyone explain this part pls 51:01
you have your phone with internet so that you can search anything you want
@@anilsir2277 bechara explanation maga tha bhasan nhi 😂
Sir, so the limiting reagent is chlorine right ?
Yaya
Sir please help me i learned whole lesson but can't able to score more in exam
Chemistry is the only subject which i score less. you are the only hope
Very fantastic explanation sir . No one can explain like you .
What about Alakh pandey
Sir you made the topic I have been struggling for years as simple as the abc's, thank you for all your hardwork I really appreciate it.
Thank u so much sir 🥰❤
I have my H.Y exam tmrw & I didn't know anything in mole concept not a single numerical but after this I'm able to solve most of the ques from book even from PYQs also 😇
Sir is God for us ❤
1:18:22 / 1:52:05
Its 2 33 am and I have my Chemistry Boards Exam from 11 00 am...and I am here to study empirical formula now...😅😅
Sir, 8:20 me apne 1 volume of acetylene nikala hai usse 5 volume of oxygen kaise ayega?🤔🤔🤔
Tap on this multiple times 😂👉 03:43 👈 at 2x
1:04:23 vapour denisty does not have a unit
I watched whole video.. it's super best explanation 😃 thank you so much sir !! It's really very helpful for me 🙂
39:33 sir 1 dozen ki value 12 hoti hai
Kal jis jis exam hea like 👇👇👇👇👇👇👇👇👇👇
All the best for everyone
Study + motivation = free = topper
Tarun Sir, thank you so much for making us learn these topics. it was very enriching. I searched this topic a lot and saw few videos also but yours was the best. Now I am confident about this topic. i liked and subscribed your channel. 👍
Thank you sir!!!! Samaj me nhi aa rha tha
Par apka explanation mast tha thank you so much
legends watching 2 days before exam
Thank you ..thank you very much sir .i was really unknown to this chapter before but now it's clear just because of you.Thank you sir gor your much efforts for us.Pray for your good health..
Sir aapne to ekdam Mole ko khol ke rakh diya...🙏🙏🙏
Sir at 59:50 the answer is wrong according to concise the answer is 6.022*10^23 electrons. Pls reply.
Kal exam hai bhai😂😂😂
Parso ha
one of the best teachers out there
I had been struggling to understand the concept of mole concept since a week... But after watching this video I understood the whole part.... Thank you sir for the great explanation
Yeah bro i am just doing reactions bro after this video 🎉🎉
Maine sir ka video dobarra se dekha pahli baar smjh nhi aaya tha esliye ess baar pura smjh aa gya in November😊
Live chat replay is on. Messages that appeared when the stream was live will show up here.
Good explanation Thank you sir ❤
Keep watching
Thank you sir for your marvelous presentation of this concept which you did last year helped us this year also And I will ask classes for some topics in future,l hope you do that need full to us 👍😊 l will be waiting for your reply
sir can you bring a vedio on spectrum of physics as per the current session of 2024
39:30 1 dozen=20 😂🤣🤣🤣😃😄😄😅😅😀😆😉
Chuma chuma chuma for your teaching 😂❤❤
I wish you were my school's chemistry teacher 😊
Sir we need videos on acid,base nd salt and electrolysis..
Soon....👍
Kon sir video 1.75x Pe dekhta h
Sir in molar volume, 1 mole of any substance means only gaseous molecule will occupy 22.4 l ?
yes
All preperation one night before 2024 board exam 😢
Sir aap legend ho jo Mai whole year nhinsamajh paya or boards ke 10 days before Samaja gaya salute 🫡 ❤
Jst 4 hours before boards chemistry 2024😭🫂
Watching 2 hrs before chemistry board exam 2024 🗿
Same
Me watching after class 10
For 11 class😢😢
Thankkk youuu sooo sooo much sir🥹✨......this video helped me alot
Maine toh he chap se ummeed hi chord di thi...ab raatko board exam se pehle 12 baje dekhri hu...or kon ko 😢
Mujhe fever ho gya tha to mummy ji ne kha ki soo jao 1 ghanta to me soo gya par baadme mummy ji ne uthaya hi nhi ab meri aakh khuli h apne aap 😢
@@SakshamSingh-rk8jt yaarrr...isliye mai kabhii mummy pe wishwaas nhi krtii..bit hogyi prepम
Very good sir i like your teaching alot thank u for teaching us the entire year without consuming any money
Kon kon sir ke vedeo 2x pr dekhta hai 😂
40:18 mole concept start thank me now. Hehehhe
you teach like a SIR!😎
sir, I love your video. 59:45 the answer was wrong.
Who watches at 2x speed😅😊
2x ki nahi 4x ki jarurat hai Aaj exam hai
I thought that tarun's sir are extra lengthy and not worth the time but I am glad that I watched your video.. thank you so much sir
Thanks sir for this excellent explanation😃
1:17:00
Sir pls next video on Transpiration please
Maza aagya sir ❤
Aapne itna accha padhaya ki ek din me hi Pura mole concept tayyar ho gya. ❤❤❤
Mene toh 1hr mein hi kar liya ye video see😅😅
Right broo mai ladhki bol rahi hu bhai ki ID haii ye isliye
Kal ka paper phodhhhh kai aayyye gai!!!!!!❤❤❤
59:57 sir book mai answer alag diya hai
You're genius sir 👍👌👌
The number of chloride ions in 111g of anhydrous calcium chloride ? Sir bta dejeyr
Sir bta dejeye
Sir is bar to pura syllabus hi aaraha hai plz help us in this chapter.
Thank you so much sir for such an excellent explanation.....