How to solve numerical on milk standardization | Pearson Square Method | Dairy Tech | Foodtech Geeks
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- เผยแพร่เมื่อ 6 ต.ค. 2024
- Hi everyone.
In this video I have tried to clear the concept on how to solve numericals based on milk standardisation by Pearson Square Method. This topic is very important for entrance exams and competitive exams related to food technology.
Hope it will be helpful to You.
#milkstandardization #pearsonsquaremethod #dairytechnology #foodtechgeeks #numericals
Amount of tonned milk is 580 kg
Because amount of cream removal is 20 kg.
Am I right?
Correct!✨Great .... U r the first to give the correct answer . Well done.☺️
Thank you😍
Dear Rachna,
Can you solve some more questions(#Algebraic method/other suitable method)
Q1. Calculate the efficiency in percent (rounded off to 1 decimal place) of an oil expeller which yields 37 kg oil containing 5% solid impurities from 100 kg mustard seeds. The oil content of the mustard seed is 38%.(GATE2023)
Q2. The weight of 10 kg dried cauliflower containing 5% moisture (wet basis) after rehydration is 60 kg. If the fresh cauliflower contained 87% moisture (wet basis), calculate the coefficient of rehydration (rounded off to 2 decimal places).(GATE2023).
Perfect explanation ma'am. I have been searching for this type of study content. Keep it up ma'am. You are the inspiration. Also, Please upload more videos related to dairy science. It would be a great help for all of us.
Thanku so much Garima for such motivating and encouraging words!
It gives lot of motivation when you people like the efforts.
Soon I will start series on dairy tech as well.
Thanku for your valuable input 😊
580kg tonned milk
30 part = 600 kg milk
29 part of tm = 29 ×600÷30 = 580 kg of tonned milk
Explain someone to me, please! Why on 4:15 I see "desired fat of milk" in the middle of square - equals 1.5%. But yat it's said "Double toned milk with 3% fat"? 3%! not 1.5%! Why?
There is a question for u all in the end of the video . Watch the full video and then try to solve the question..write down ur answer in the comment section ... let's see who is going to give the correct answer first.....😊
Awesome way to explain...
Please can you upload the video by mass balance concept also.
Thanku so much sadik.☺️. Yes, surely i will upload video on mass balance too.
TM prepared is 580 kg. and thanks it's really helpful
Hi need some help regarding milk standardization can you give Ur Instagram or answer here🙏
Mam one numerical problem i have please solve them mam -
Problem -
5000 kg of standardized milk testing 4.5 % fat is prepared by add mixing whole milk testing 6% fat and skim milk testing 0.5 % fat .
Calculate the amount of whole milk as well as skimmed milk that will be required for the same .
Please mam upload answer as soon as possible mam .
Hi need some help regarding milk standardization can you give Ur Instagram or answer here🙏
whole milk=3636.36 kg & skim milk used for std=1363.63
Method used Pearson square.
Cross checking using the fat =3636.36*6/100+1363.63*0.5/100=5000*4.5/100
(If some body needs the work out ,reply me with your email ID)
Very nice... Rachna... 👌
Nice one rachna
How to convert 4 fat 8.5 snf milk to 6 fat 9 snf milk
put fresh cream to standardize.
Pls can help how to make 2 ltrs tonned milk with 3.5 fat and 8.5 snf by adding water and skim milk only?
Hi need some help regarding milk standardization can you give Ur Instagram or answer here🙏