After a week of lecture from my professor I had no clue how to do op amps. Watching this 30 minute video now I feel confident in solving almost any! Thank you so much!
I agree with most of the other comments - this guy does an amazing job of explaining not only the math, but first describes how the circuit works. Once that is understood, the math is much easier to understand. Thank you so much for making the time to post this video. All the best to you and take care!
How does he really do it? Making maths and science so simple to understand!!!! This guy is more than a just a teacher! Every time I watch these videos, I just can't stop!!
Been looking for the reason that the +1 is disregarded in the gain formula for the inverting configuration, finally found my answer here explained perfectly. Thanks!
I have been watching your videos and subscribed to your excellent website so that I could get through Uni- You are quite literally A SUPER HERO- an a massive massive THANK YOU- ...your Laplace lectures are invaluable-
amazing, how you have so much info about how/why things are assumed how things are measured while explaining this..... i appreciate the filling in of gaps.
THANKS!! Three things: 1) Why introduce Rg at all? 2) You didn't mention the advantage of the high impedance compared to the inverting amp 3) 23:00 I was anxious for you to say the gain could go to 0. Not just much lower...
While working with ideal op-amps in college, I learned in real life that there's no such thing as ideal op-amp. For instance, v1 is not equal to v2 and i1 and i2 is not equal to zero. Makes big difference in embedded circuit design.
Sir i am very exited to see wualified person's technical video. Please through some light in phase error in inverting and non inverting teminals. Thanks
For the purple equation of 16:56, why is it not v1=v0(RsRf/(Rs+Rf))? If we use KCL on such a circuit, we get (v1-0)/Rs = (v0-v1)/Rf, and then we transform this equation into the equation above.
I was trying to find the video about the inverting op amp and I couldn't. I have some questions connected to inverting op amps, for example, if I have Uout and Uin and f = 1000 Hz, are there formulas with which I can find Rf and Rin? Thanks in advance!
MATH and SCIENCE, Do you have any video lessons about how to bias transistors because there is multiple methods are how to biasing a transistor. Some use the HFE, some use the resistor ratios of RC and RE to get the gain, some use the datasheets IC current. If you want a gain of 5 you would have to base the RC and RE ratio and use that first as the biasing method. Others use the HFE to calculate the gain, so it gets confusing which method to use for biasing transistors. When looking at Resistor Ratios you can tell the gain of an op amp or transistor stage amplifier.
Fantastic explanation, one of the best explanations of the op amp I've seen. I still don't understand how Rf and Rs are voltage dividers if its said that no current passes between the 2 terminals. If there's no voltage applied between the 2 terminals, how can there be a voltage drop on either resistor? If there's no voltage drop on any resistor (or at least Rg) what is the point of these resistors being in the circuit in the first place?
lmab1234 - so sorry this answer is 2 years after your question is asked. If I understand the non- inverting opamp, there is current flowing between Rs and Rf. The link to this video below shows it in this animated video. I believe it is using an AC signal, as the current is changing direction between Rs and Rf. th-cam.com/video/_o4ScgRZtNI/w-d-xo.html
Why can’t you use two opamps , off the same AC input, one into the inverting input and the other into the non inverted input , and use this as a phase inverter before a push- pull power amp?
babu might be a little late for the reply, but it’s because you want to know the voltage drop across Rs to know the value of V1, because V1 is the voltage drop across that resistor, so you multiply by Rs, and divide by the sum of both resistors
These are great videos. The instructor has a web site where he charges $ for these ( monthly or yearly) . I wonder why these are here for free? Are these legit? Or did someone post and ripping him off?
This guy is the absolute best teacher I've ever learned from.
I agree! He is very easy to understand.
@@dougitman5579 ko jo jo I luhhhhu
After a week of lecture from my professor I had no clue how to do op amps. Watching this 30 minute video now I feel confident in solving almost any! Thank you so much!
Awesome!
th-cam.com/video/YtI294cjKMc/w-d-xo.html
@@MathAndScience b Bo in no h PPggggg
CV
Ggvv🥴😌😏🤪😌🥰☺️
I agree with most of the other comments - this guy does an amazing job of explaining not only the math, but first describes how the circuit works. Once that is understood, the math is much easier to understand. Thank you so much for making the time to post this video. All the best to you and take care!
this is absolutely the best video for non inverting op amps
How does he really do it? Making maths and science so simple to understand!!!! This guy is more than a just a teacher! Every time I watch these videos, I just can't stop!!
Thanks so much!
@@MathAndScience sir I can't see that inverting amplifier in detail
Man you really know how to speak to the people… the best of the best
Absolute legend. This makes the inverting and non-inverting concept so much easier to understand. You’re the best
My lecturers never explain anything this well. Thank you so much!
Finally a lecture that closely matches my teachers notes... thanks a lot for the easy explanation of the op amps
So happy you liked it!
Jason, MathAndScience.com
Been looking for the reason that the +1 is disregarded in the gain formula for the inverting configuration, finally found my answer here explained perfectly. Thanks!
Brilliant teacher - detailed and logical explanations - makes it look so simple. Thank you
THIS IS THE BEST VIDEO I MAY HAVE EVER WATCHED I WAS SMILING THROUGH THE ENTIRE VIDEO!
The best tutor I've seen in life
I have been watching your videos and subscribed to your excellent website so that I could get through Uni- You are quite literally A SUPER HERO- an a massive massive THANK YOU- ...your Laplace lectures are invaluable-
amazing, how you have so much info about how/why things are assumed how things are measured while explaining this..... i appreciate the filling in of gaps.
I love how these great teachers give us these lessons for free. TY TY tY
Yes He is the absolute best teacher . No doubt about that
This class is a masterpiece. Thank you!
THANKS!!
Three things:
1) Why introduce Rg at all?
2) You didn't mention the advantage of the high impedance compared to the inverting amp
3) 23:00 I was anxious for you to say the gain could go to 0. Not just much lower...
Rg, I assume, is for smoothing ripples from source trigger signals (transients).
9:24 why input is also grounded , the one applied to non inverting terminal?
You have a gifting to teach clearly and best, nice job, its cleared my doubt
Your teaching method is really Amazing.
A very clear and concise explanation
wonderful explanation sir need more numericals relevant to inverting and non inverting opamps
Legend, op-amps now make sense :))
This was a great tutorial. Well done, dude.
He is well explained to dummy like me💕
While working with ideal op-amps in college, I learned in real life that there's no such thing as ideal op-amp. For instance, v1 is not equal to v2 and i1 and i2 is not equal to zero. Makes big difference in embedded circuit design.
Thank you so much. My community college professor is trying to teach this and he's so lost. It's not really all that complicated is it?
Sir i am very exited to see wualified person's technical video. Please through some light in phase error in inverting and non inverting teminals.
Thanks
Respect from Bangladesh
For the purple equation of 16:56, why is it not v1=v0(RsRf/(Rs+Rf))? If we use KCL on such a circuit, we get (v1-0)/Rs = (v0-v1)/Rf, and then we transform this equation into the equation above.
thank you very much it is very good lecture. clear and easy.
Very clearly explained. Thank you Sir
Well explained sir, thank you for your explanation.
You are the best👍💯
What is the effect of sound signal if we use inverting amplifier for amplification?
I was trying to find the video about the inverting op amp and I couldn't. I have some questions connected to inverting op amps, for example, if I have Uout and Uin and f = 1000 Hz, are there formulas with which I can find Rf and Rin? Thanks in advance!
This virtual short between the 2 input terminals of the op amp applies only if there is a negative feedback on the op amp, right?
MATH and SCIENCE, Do you have any video lessons about how to bias transistors because there is multiple methods are how to biasing a transistor. Some use the HFE, some use the resistor ratios of RC and RE to get the gain, some use the datasheets IC current. If you want a gain of 5 you would have to base the RC and RE ratio and use that first as the biasing method. Others use the HFE to calculate the gain, so it gets confusing which method to use for biasing transistors. When looking at Resistor Ratios you can tell the gain of an op amp or transistor stage amplifier.
He is so underrated
has the inverting op amp been deleted?
Very straight forward. Thank you
have you uploaded a video on transistor as a switch?
if yes , link plz...
Brilliant lecture!
Do you guys have videos over Circuits 2 with Laplace transform and Fourier analysis?
Fantastic explanation, one of the best explanations of the op amp I've seen. I still don't understand how Rf and Rs are voltage dividers if its said that no current passes between the 2 terminals. If there's no voltage applied between the 2 terminals, how can there be a voltage drop on either resistor? If there's no voltage drop on any resistor (or at least Rg) what is the point of these resistors being in the circuit in the first place?
lmab1234 - so sorry this answer is 2 years after your question is asked. If I understand the non- inverting opamp, there is current flowing between Rs and Rf. The link to this video below shows it in this animated video. I believe it is using an AC signal, as the current is changing direction between Rs and Rf.
th-cam.com/video/_o4ScgRZtNI/w-d-xo.html
Fully understand that topic thanks sir
Great explanation.
amazing teacher !!
What I’ve found from using op amps is for linearity they can’t even go near the rails or they saturate even unity gain ones
Great explanation thank you
ok, if Vg is equal v2 ,so why we use Rg???does it use for noise or control current???
Hi I need the link to the video on inverting op-amp. Thanks
Pete Repete - how do I configure a noninv. opamp to less than 1 in gain?? ;)
It gets difficult to track down the next video from your channel. Could you help on that, sir? @math and science
Why can’t you use two opamps , off the same AC input, one into the inverting input and the other into the non inverted input , and use this as a phase inverter before a push- pull power amp?
I should pay this guy my tuition not the uni
what is the role of rg?
worth appreciating
waiting for more videos in this section please
Exelent episode very clear, only one thing I can not figure out what is the function of Rg, thanks
The input impedance of a non inverting opamp is approximately equal to infinity,it has no function there
Thanks Guru Ji.
Can I use it on stabilizer
Really helpful...
thnk u soo much!! God bless u
I en ideek op.amp er inngangene U1 og U2 lik (U1=u2).
Det er ikke noe strøm som går gjennom selve op.ampen
Thank you sir
Wish you wired circuit clearly and took electrical measurements to clarify everything
Rg isn’t in the textbook for me.🤔
A more simplified formula is usually shown in elementary textbooks. The complications are added in later!
Where is the next video of this one !???
Thank u now i understand
Wonderful.
This type of explanation is said to be real.
Explanation
Thank you so much
anybody has this full course? can you send it to me
Which grades
SthombeD Dubazana University level
감사합니다.
thanks sir
Sir need further videos on operations of OP-Amp.
Why v1 is v0 times rs/sum and why not rf/sum??????
babu might be a little late for the reply, but it’s because you want to know the voltage drop across Rs to know the value of V1, because V1 is the voltage drop across that resistor, so you multiply by Rs, and divide by the sum of both resistors
i think u shld clearly label the earth
tidak mengerti bahasanya tapi paham penjelasannya
These are great videos. The instructor has a web site where he charges $ for these ( monthly or yearly) . I wonder why these are here for free? Are these legit? Or did someone post and ripping him off?
Translate to Indonesian 🙏, i'm so not understand
nice
6+ min of intro?!
bro called me a monkey :(
so hard
Excellent letcures
But toooo much talkative
Please brief little bit
Why do you make everything so complicated? Remember KISS? All the gibberish is useless.
This isn’t complicated though. I read the book and then came here. Understood it very well. He’s pretty good.
Thanks 🙏👍💯😊