@@swastikbiswas8293 amar mone hoy mathematician er pore second best profession 'bor ke stalk kora'!! kobbui stalk mitti hoyechhish kneo amar dosh? talk ki dekhbu oi lokta tor moton khanikta!
@@swastikbiswas8293 eshob bole amay porte boshano na bessi bessi(*insert one of your 33 koti names*)! aar amio eshob shune porte boshe jai amar ki korun obostha!
Osar X - That's your point of view, for me he nailed it. I am very happy he's a part of our politics, he's brillant and very original it can only be a big plus for our political landscape.
3^3=15^2-3^2 -( 4^3+5^3) integer^3=integer^2-integer^2 - sum consecutive integers cube. Give sum consecutive integers cube.approaching to infinity. It seems difficult exists Z,X and Y integers which satisfies Z^n=X^n+Y^n.
3^3+4^3+5^3=216=225-9=15^2-3^2. Z^3+(Z+1)^3+..+(Z+a)^3=1/4*(Z+a)^2*(Z+a+1)^2 - 1/4*Z^2*(Z-1)^2. Z^3+(Z+1)^3+..+(Z+a)^3=integer^2 - another iinteger^2. Sum of consecutive integers with exponent cube=integer^2-another integer^2. Z^3=integer^2-another integer^2-sum of consecutive integers with exponent cube. If give sum approaching to infinity it seems difficult finding integer Z that satisfies equation Z^n=X^n+Y^n.
3^3+4^3=(4*5/2)^2-(3*2/2)^2=100-9=91. 3^3+4^3+5^3=15^2-3^2=225-9=216 3^3=10^2-3^2-4^3 3^3=15^2-3^2-4^3-5^3. 3^3=a^2-3^2-4^3-5^3-6^3-....endless. How exists Z,X and Y integers same time satisfy long winded forms of Fermat when (a) move from 1 to 3,6,10.15....endless.
" I have discovered a truly marvelous demonstration of this proposition that this margin is too narrow to contain." z^n=z^(n-3)*{[z(z 1)/2]^2-[(z-m-a-1)(z-m-a)/2]^2 - [z(z-1)/2]^3 + [(z-m-a)(z-m-a 1)/2]^2 - (z-m-a)^3}. when (a) move from 1 to 2,3,4....endless The equation (z^n=x^n +y^n) with z,x,y are the integers which is the cause of an unreasonable.
z^n=z^(n-3)*{[z(z 1)/2]^2-[(z-m-a-1)(z-m-a)/2]^2 - [z(z-1)/2]^3 + [(z-m-a)(z-m-a 1)/2]^2 - (z-m-a)^3}. when (a) move from 1 to 2,3,4....endless The euqation (z^n=x^n +y^n) mean many other equations with a =1,a=2....endless. If exists a reasonable equation all other equayions are unreasonable
What makes you say that? My friend's mom quit a well paying job to become a parole officer. It's very meaningful work. I imagine it feels great to witness a "screw-up" turn their life around.
Yeah I know. I am a french scientist. I watched plenty of his talks in french. Listening to him speaking in english just makes me smile.
And I also think that he's accent and pronounciation is sooooooo attractive too.
he is so funny and interesting.... great talk
Amazing talk...He clearly expresses everything from his body language
Thank you, Cedric Villani, for speaking in an English I can at last, as an average Parisian, understand ! :-)
Very rare class of good speaker who is mathematician
Which part of the talk did you like so so much, hm? I have a feeling it is Andre Weil's quote, right?
@@riddhimanna8437 bessi korishna stalker bou amar!!
Talk e te na mon diye , prothom comment e mon🤦
@@swastikbiswas8293 amar mone hoy mathematician er pore second best profession 'bor ke stalk kora'!! kobbui stalk mitti hoyechhish kneo amar dosh? talk ki dekhbu oi lokta tor moton khanikta!
@@riddhimanna8437 paguus re!! Tui maths pore Fields ba Abel medal pa. Ami nije toke TH-cam e stalk kobbus
@@swastikbiswas8293 eshob bole amay porte boshano na bessi bessi(*insert one of your 33 koti names*)! aar amio eshob shune porte boshe jai amar ki korun obostha!
I love the "preparatory classes" system
I LOVE the final phrase...
Émerveillement inlassable. Je me delecte. Gratitude. Mo d
domb
He is so attractive isn't it? I m a big fan of Cedric Villani from Korea. I think he's just great
Bae Jooyoung Sorry but he fucked up in politics
Osar X - That's your point of view, for me he nailed it. I am very happy he's a part of our politics, he's brillant and very original it can only be a big plus for our political landscape.
Yes! I was searching for the right word...you are right the word is 'attractive'! Also sometimes I laughed so much I had to pause the video lol
3^3=15^2-3^2 -( 4^3+5^3)
integer^3=integer^2-integer^2 - sum consecutive integers cube.
Give sum consecutive integers cube.approaching to infinity. It seems difficult exists Z,X and Y integers which satisfies Z^n=X^n+Y^n.
3^3+4^3+5^3=216=225-9=15^2-3^2.
Z^3+(Z+1)^3+..+(Z+a)^3=1/4*(Z+a)^2*(Z+a+1)^2 - 1/4*Z^2*(Z-1)^2.
Z^3+(Z+1)^3+..+(Z+a)^3=integer^2 - another iinteger^2.
Sum of consecutive integers with exponent cube=integer^2-another integer^2.
Z^3=integer^2-another integer^2-sum of consecutive integers with exponent cube.
If give sum approaching to infinity it seems difficult finding integer Z that satisfies equation Z^n=X^n+Y^n.
lol youtube should include Latex, i can't read all these comments lol
I just love Cedric haha.
3^3+4^3=(4*5/2)^2-(3*2/2)^2=100-9=91.
3^3+4^3+5^3=15^2-3^2=225-9=216
3^3=10^2-3^2-4^3
3^3=15^2-3^2-4^3-5^3.
3^3=a^2-3^2-4^3-5^3-6^3-....endless.
How exists Z,X and Y integers same time satisfy long winded forms of Fermat when (a) move from 1 to 3,6,10.15....endless.
It's cute that you think that understanding ODEs puts you on his level.
It's only when he speaks English. When he's talking in French his voice is a lot more even and (obviously) his pronunciation is better.
" I have discovered a truly marvelous demonstration of this proposition that this margin is too narrow to contain."
z^n=z^(n-3)*{[z(z 1)/2]^2-[(z-m-a-1)(z-m-a)/2]^2 - [z(z-1)/2]^3 + [(z-m-a)(z-m-a 1)/2]^2 - (z-m-a)^3}.
when (a) move from 1 to 2,3,4....endless
The equation (z^n=x^n +y^n) with z,x,y are the integers
which is the cause of an unreasonable.
excellent. sums up in words thoughts of mine
YOUPI !!! i understand all the words ! merci !
Cédric you speak english very much great
z^n=z^(n-3)*{[z(z 1)/2]^2-[(z-m-a-1)(z-m-a)/2]^2 - [z(z-1)/2]^3 + [(z-m-a)(z-m-a 1)/2]^2 - (z-m-a)^3}.
when (a) move from 1 to 2,3,4....endless
The euqation (z^n=x^n +y^n) mean many other equations with a =1,a=2....endless.
If exists a reasonable equation all other equayions are unreasonable
Idk if the video has no audio at all or it is just my phone. Hopefully is gonna get fixed.
Me too! And I thought my phone ... :/
The sound is broken for me..?
There's a problem with the sound in this video, could the uploader please check this problem and fix it? Thanks in advance.
I like this guy !!
For sure
Ladies and Gentlemen: The real Sheldon!
Exactly ^^ He's amazing in so many ways.
Princeton has the most Fields Medalists.
+EdD5 not as former students, that's what he was talking aout
14. Parole officer?? I can't imagine that being one of the best jobs
What makes you say that? My friend's mom quit a well paying job to become a parole officer. It's very meaningful work. I imagine it feels great to witness a "screw-up" turn their life around.
stop going to the shade!
His English isnt bad at all:)
For a Frenchman, I agree ;-)
Entertaining talk, although oriented for the nonspecialists.
@classicmusic05 What about the bow tie? :P
j'adore sa voix qui part en couille ahah, trop de swag
what a fucking accent putain
cool guy
He sounds like borat when he speaks english^^. Just kidding, this guy is amazing!
Awesome... :|
Ted's like a weird cult now
Funny accent :D
There's no voice to this video
I find the idea of an idol overrated
He speaks like arabics ROFL
He shouldn't inhale helium ballooms before speeches. I gives a bad impression.
excellent. sums up in words thoughts of mine