What I did was when combining for C, I took 12*63 + 11*73 + 100/25 - it gave me less than 70 so I marked C but I got less than 70. Where did I go wrong?
You forgot the other 100. You have one score of 0 in your calculation that brought the average down. Remember there's 2 that scored 100, so you should've been doing (12*63 + 11*73 + 100*2)/25. The way i solved it was I multiplied the "mean" by the number (70*25), that way I just need to know "is the SUM > 1750?". Plus DI allows a calculator now, albeit not a very good one...
So you got the average less than 70. Now take (63 + 22*73 + 2*100)/25 and the average will be more than 70. So you can get the average as less than 70 and more than 70. So both statements together are not sufficient. Ans (E)
What I did was when combining for C,
I took 12*63 + 11*73 + 100/25 - it gave me less than 70 so I marked C but I got less than 70.
Where did I go wrong?
You forgot the other 100. You have one score of 0 in your calculation that brought the average down.
Remember there's 2 that scored 100, so you should've been doing (12*63 + 11*73 + 100*2)/25.
The way i solved it was I multiplied the "mean" by the number (70*25), that way I just need to know "is the SUM > 1750?".
Plus DI allows a calculator now, albeit not a very good one...
So you got the average less than 70. Now take (63 + 22*73 + 2*100)/25 and the average will be more than 70. So you can get the average as less than 70 and more than 70. So both statements together are not sufficient. Ans (E)
@@drasteilYeah, a very silly mistake which would lead to ans E as well as Karishma pointed out.
Oh, Thanks for another method!!
@@karishma.anaprep Yes, just found out my mistake.
Thanks for the clarification!