Thanks for the kind words! If you found the video useful make sure to check out my website adampanagos.org where I have a lot of other resources available. Thanks! Adam
Adam Panagos please help on few more topics i've my exams of signal n systems i don't wanna choke. topic -system with finite and infinite duration response
Thanks for the kind words! If you found the video useful make sure to check out my website (adampanagos.org) where I have a ton of other resources available and it's easier to watch my videos in a more organized fashion. Thanks, Adam.
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks much, Adam
The textbook used for the course is, "Signal Processing and Linear Systems" by B. P. Lathi. You can check out the course videos here: www.adampanagos.org/ct-signals-and-systems www.adampanagos.org/dt-signals-and-systems
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (540+ videos) you might find helpful. Thanks much, Adam
Can i ask if the order of transformation is not a problem when you have the scaling factor right? I’m advised by my uni tutor that we should always start with scaling or reverse, then shift
As I showed in the video, if you have a signal that has been scaled and shifted, there are always 2 different ways to arrive at the same signal. You can shift then scale (Approach #1) or scale then shift (Approach #2). However, note that the VALUES you use in these operations are different. Since they are equivalent, it's really up to you which you prefer. Or, if your instructor (or the problem) specifies the order then you should do it in the way they request. Hope that helps, thanks for watching! Adam
Thanks for the nice video. I do not understand, regarding 2nd approach. When scaling @ a factor 2, then why shift for 3/2 rather than 3? Further, there is a precedence rule, that prevents scaling first. What do you say? By the way what software you use for this demo. Thanks.
It's not that there is a rule about one way or the other, it's just that the order/values do matter. So, if you want to take x(t) and get x(2t+3), there are two ways. In Approach #1, you shift by 3, then scale by 2. In Approach #2, if you scale by 2 first, then you need to shift by 3/2. In both cases, you end up at the same signal of x(2t+3), but the first approach is the "easier" approach since the values of 2 and 3 are more easily seen in the problem statement. It's for that reason I suaulyl recommend always shifting first, then scaling, because you can then use the "obvious" values of 2 and 3 that you can "see" in x(2t + 3). For most of my videos, I use Doceri (an app for my iPad, apps.apple.com/us/app/doceri-remote/id412443803?ls=1) that lets me pre-record all the writing. Then, I can "play back" the writing while I record the audio. It’s a very useful tool for me. Hope that helps, Adam
If you watch the videos there are 2 different ways on working this problem. You can either shift-then-scale or scale-then shift. The second approach requires a shift of 3/2 so when we replace t with t+3/2 in the quantity 2t, the 2 in the numerator and the 2 in the denominator cancel, leaving the desired 3.
Can you plz help me ? If we have delta(2*(t - to)). How to plot this? We know , at t = to this function will be there. But if we do in the way that you did in this example then we will be getting impuls at some other location rather than to. What is wrong here?
I'm not sure if this will still help, but I made a video that's somewhat related to this topic; you can watch it here: th-cam.com/video/N03Dbc3nqqI/w-d-xo.html
Hello... In the approach 1, after doing time shift by 3 i.e. x(t+3), then while doing compression.. why is it done as x(2t+3) instead of x(2(t+3))? My question is how can multiplication be done only for t when the time expression is t+3? Thank you very much!
For both of these rules, the rule is "replace t by a some quantity". For example, when doing a time shift by some amount s, we replace t by (t+s). Similarly, if doing compression or expansion by some factor b, we replace t by bt. It's all about algebraic replacement of the variable t with some new quantity. That's why only "t" gets replaced. Hope that helps, Adam
Think about the signal x(t) = t. This is a line with unit slope that passes through the t = 0 origin with a value of 0. If we compute x(t+3), then we have x(t+3) = t+3. This signal also has unit slope but it passes through the time origin t = 0 with value 3. If you plot this signal, relative to x(t) it looks exactly the same except it is shifted 3 units of time to the left. Similarly, if you compute x(t-3), then we have x(t-3) = t-3. This signal has unit slope but it passes through the time origin t = 0 with value -3. If you plot this signal, relative to x(t) it looks exactly the same except it is shifted 3 units of time to the right. In general, x(t-c) is a shift to the right for c>0 and a shift to the left for c < 0. Hope that helps.
WHY don’t lecturers teach like this? I’ve learnt so much from these short videos than in my 2hr+ classes! 😭 God bless you sir ❤️
Thanks for the kind words! If you found the video useful make sure to check out my website adampanagos.org where I have a lot of other resources available. Thanks!
Adam
You are better than my lecturer which gets loads of money. Thank you very much.
Thanks you are amazing
you make it so easy a piece of cake
Keep the good work 👍👍
Glad I could help, thanks for the kind words. Best,
Adam
you are such an amazing tutor
Thanks for the kind feedback!
Adam Panagos please help on few more topics i've my exams of signal n systems i don't wanna choke.
topic -system with finite and infinite duration response
I would say thanks for every step you taught me at this lesson
thank you
You're welcome, thanks for watching.
Sir you're excellent in tutoring thanks to your simplified explantions now i really have much least problems solving such problems thank you very much
Thanks for the kind words! If you found the video useful make sure to check out my website (adampanagos.org) where I have a ton of other resources available and it's easier to watch my videos in a more organized fashion. Thanks, Adam.
its nice lecture to understand and give more feedback about a system and signals from you sir thank you
Your explanation is really awesome. Thanks a lot....:)
Glad you found it helpful. Thanks!
It is good to see that i should be careful about time shifting when do the expansion/supression first thank you for nice video. :)
I Love it very much, Thanks boss !!!
Thank you sir!
You're welcome, thanks for watching!
Thank youre the best
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks much, Adam
very helpful, thank you.
Sir which book are you using
The textbook used for the course is, "Signal Processing and Linear Systems" by B. P. Lathi.
You can check out the course videos here:
www.adampanagos.org/ct-signals-and-systems
www.adampanagos.org/dt-signals-and-systems
Thank you
Sir,Your teaching is nice.Can u give some more different examples.
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (540+ videos) you might find helpful. Thanks much, Adam
Can i ask if the order of transformation is not a problem when you have the scaling factor right? I’m advised by my uni tutor that we should always start with scaling or reverse, then shift
As I showed in the video, if you have a signal that has been scaled and shifted, there are always 2 different ways to arrive at the same signal. You can shift then scale (Approach #1) or scale then shift (Approach #2). However, note that the VALUES you use in these operations are different. Since they are equivalent, it's really up to you which you prefer. Or, if your instructor (or the problem) specifies the order then you should do it in the way they request. Hope that helps, thanks for watching!
Adam
Thanks awesome !
Thanks!
Super.....!!!! grate tutorial
Thanks!
think you very much ser
You're welcome; thanks for watching.
Thank you!
+Aaron Friedman You're welcome, thanks for watching!
Thank you sir
Thanks for the nice video. I do not understand, regarding 2nd approach. When scaling @ a factor 2, then why shift for 3/2 rather than 3? Further, there is a precedence rule, that prevents scaling first. What do you say? By the way what software you use for this demo. Thanks.
It's not that there is a rule about one way or the other, it's just that the order/values do matter. So, if you want to take x(t) and get x(2t+3), there are two ways. In Approach #1, you shift by 3, then scale by 2. In Approach #2, if you scale by 2 first, then you need to shift by 3/2. In both cases, you end up at the same signal of x(2t+3), but the first approach is the "easier" approach since the values of 2 and 3 are more easily seen in the problem statement. It's for that reason I suaulyl recommend always shifting first, then scaling, because you can then use the "obvious" values of 2 and 3 that you can "see" in x(2t + 3).
For most of my videos, I use Doceri (an app for my iPad, apps.apple.com/us/app/doceri-remote/id412443803?ls=1) that lets me pre-record all the writing. Then, I can "play back" the writing while I record the audio. It’s a very useful tool for me. Hope that helps,
Adam
greatttt greatt thankss
You're great !!
Thanks for the nice feedback, thanks for watching!
Why you shifted signal 3/2 sec but not 3 sec when the equation is (2t+'3') . Please help.
If you watch the videos there are 2 different ways on working this problem. You can either shift-then-scale or scale-then shift. The second approach requires a shift of 3/2 so when we replace t with t+3/2 in the quantity 2t, the 2 in the numerator and the 2 in the denominator cancel, leaving the desired 3.
Can you plz help me ?
If we have delta(2*(t - to)). How to plot this? We know , at t = to this function will be there.
But if we do in the way that you did in this example then we will be getting impuls at some other location rather than to.
What is wrong here?
I'm not sure if this will still help, but I made a video that's somewhat related to this topic; you can watch it here:
th-cam.com/video/N03Dbc3nqqI/w-d-xo.html
What about third method for y(t) = x(2t+3) = x(2(t+3/2)) ? :
.Apply shit ( t + 3/2) and compress with 2
Sure, that's fine too. They are many ways to get to the final answer.....
Hello... In the approach 1, after doing time shift by 3 i.e. x(t+3), then while doing compression.. why is it done as x(2t+3) instead of x(2(t+3))? My question is how can multiplication be done only for t when the time expression is t+3? Thank you very much!
For both of these rules, the rule is "replace t by a some quantity". For example, when doing a time shift by some amount s, we replace t by (t+s).
Similarly, if doing compression or expansion by some factor b, we replace t by bt.
It's all about algebraic replacement of the variable t with some new quantity. That's why only "t" gets replaced.
Hope that helps,
Adam
hello, why is (t+3) a shift to the left not right
Think about the signal x(t) = t. This is a line with unit slope that passes through the t = 0 origin with a value of 0.
If we compute x(t+3), then we have x(t+3) = t+3. This signal also has unit slope but it passes through the time origin t = 0 with value 3. If you plot this signal, relative to x(t) it looks exactly the same except it is shifted 3 units of time to the left.
Similarly, if you compute x(t-3), then we have x(t-3) = t-3. This signal has unit slope but it passes through the time origin t = 0 with value -3. If you plot this signal, relative to x(t) it looks exactly the same except it is shifted 3 units of time to the right.
In general, x(t-c) is a shift to the right for c>0 and a shift to the left for c < 0.
Hope that helps.
Thanks. Really helpful
its nice lecture to understand and give more feedback about a system and signals from you sir thank you
its nice lecture to understand and give more feedback about a system and signals from you sir thank you