Averages 1 | CAT Exam Preparation 2024 | Arithmetic | Quantitative Aptitude
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- เผยแพร่เมื่อ 22 ก.พ. 2019
- CAT PREPARATION 2024 I QUANTITATIVE APTITUDE PREPARATION for CAT 2024
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thank you, you are really doing amazing work. people who cant afford coaching can learn from you, its an example of humanity. may the force be with you!
preparing foe cat too?
Did you recently started preparing for cat?? Is it possible to crack cat from Starting from scratch??
@@yes3635 any thing is possible bro even i started 2 weeks ago
@@vinaygupta609 we're in same boat⛵
@@yes3635 how much you have prepared
Best playlist on the internet if you want to understand aptitude conceptually.
Thank you sir.🙏
Ravi Sir, if I make it this year I owe everything to you. Every bit of happiness, all that will ever come to me, shall belong to you first in all honesty.
I might not be able to directly pay you back for the greatest part you’re playing in my journey; unaware and carefree of it, but sir I promise to you that I will follow your legacy forever. I promise to guide, help, teach and mentor anyone and everyone that might need my help in their journeys. I shall be a true Rodha student Ravi sir.
Thankyou for every sigh of breathe you’ve taken to educate the world. Thankyou for making the world brighter and happier. 🌻
OH wow!
hey! its been 6 month i hope you have made it.
i just want to know that is this whole series enough to prepare for quants?
i will be gratefull if you reply.
Did you clear cat with the help of these quantitative aptitude videos?
@@mahimasinghal6983This video has 99K views, do you think all 99K aspirants who watched these video got a seat in a Top B school ???
No but maybe a few of them got in, These videos are meant to clear your concepts and it's not different from what they teach you in paid coaching, there they charge you to make you understand these concepts and here you're getting it for free but neither of them guarantee you a seat in IIM so take advantage of these free lectures rest all is your hardwork
@@eventuallybored correct
Thank you so much sir. You are the best educator. You explain in such a way that anybody can understand the toughest topics. The way you have been giving us all the CAT related content & that too free of cost is just truly commendable. We will be forever grateful for your hard work sir. May God fulfill all your wishes 🙏
the patience for you to teach average........very great sir.....i wish i could work hard as you
Another approach to AVG of 143 terms questions.
.....P-4, p-2 , p , p+2 ,p +4....
143/2=72.5 therefore 71 terms on either side.
We find P71 taking P as first term
P71 = P + 70*2= P+140
Similarly for last 67 terms
... N-4, n-2, n,n+2,n+4...
67/2 = 33.5 therefore 33 terms on either side n33= n+32*2 = n+64
Since both are last terms they are equal
P+140=n+64
P= n-76
nice method. Accuracy increases by this method
Great way 👌👌
Y ur multiplying with 2 sister
It is odd integer so it should be -/+1.... like that..??
143/2 = 71.5
should i contnue with the videos sequentially or should i complete percentages first and then continue with averages
anyone can give exam easily and get IIM THANKS SIR ❤️👍
Sir, why u have only completed age related questions of average there are ratio, speed time based question also?
These videos are so helpful, thank you so much ❤️
Thank you sir,the video was really helpful
thank you sir gonna watch all the playlist and score good marks in cat lets go
Last question is wrong, the A.P should be 1,3,5,7...,167
In question given is series and not sequence...
I think I have an easier solution or alternative to the last question :
t1+t143/2 = t72 = p
Assume the last 67 terms as another AP (as sir said)
now, t1+t67/2 = t34 = n
Now, t143-t67 = t76
therefore, t76 + t34 = t110 = n
I guessed this by myself because I found difference by 1 method tiresome to always remember
❤
I salute your hardwork....sir.....keep doing
Where are you preparing for CAT?
Hi ,How we can get complete course ??
Hello Sir,
I am really very thankful for all the learning resources you have provided. It really helped me a lot in uplifting my preparation to another level.
Thanks a lot again Sir!!
Brother I have created a group for cat aspirants on wp, my number is given in the about section of my channel...text me if you want to be added.
Hey, r u preparing for CAT?
Can you share your experience of CAT preparation from rodha?
Starting to fall in love with quant for the 1st time in life after watching your videos.
Just few weeks before I was the person who had this Quant Phobia.
Basically I am weak in all the 3 sections, Quant, LRDI and Verbal too but mostly quant and LRDI section. But started to gain confidence now in Quant, Starting DI-LR soon. Hope I shall start liking and get confidence in that too.
Thanks a lot @Ravi Sir for the amazing content that you made free for students like me who want coaching but currently can't afford it.
Thanks a lot once again 🙏🙏🙏
For which cat are u preparing?
Can you share your experience of CAT preparation from rodha ?
Are all the videos are in correct order because after percentage 3 average has come and percentage 4 is after some videos
Sir I couldn't understand this that if the there are consecutive odd integers then how come their average is even a even number ...hoping for your reply sir
Odd+odd=even
In the question... Avg of 7 consecutive even intergers is 36.... Why didn't we take a only as the first integer instead of a+2... As a is also an even number
sir i have a doubt. in 3rd question t76 you took it as t77 but then when you subtracted t110 and t72 it would be t38+1 i.e t39
sir plse upload more videos of percentage
Good concept sir
in last 2 nd question , in which we got answer ( n-76) , why we subtract by minus 2 why not minus 1.
Because it is odd integers , and the difference between odd no is 2
Thank You so much sir for all the hardwork! You make every concept crystal clear. #dontgiveup
cat?
As there are odd integers danger difference must be of one digit not to decide and four thirty eight digit difference
Sir!, How you senses that even consecutive integers will always have a gap of 2 it can also be in gap of 4,8, 12 and so??
Bro consecutive means - ek ke bad ek
Sir from where i can found questions on this topic
Where can I get this type of questions for practice.
u r awesome god bless u sir
Sir practice question kaha mile gai
Your the doing really great sir
when t67 to t143 terms are 77 (143-67+1 = 77) then it should be 39 from back t110 to t72. why is it 38 at 21:38?
at 11:35 he literally took less than 5 secs to solve it. insane speed 🔥🔥🔥
HE uses a shortcut
Sir, from t72 to t110 there are 39 terms, not 38 terms as you said , difference + 1 so 110 - 72 = 38 , so 38+1 = 39 and 39 *2 = 78 therefor p = n-78 should be the answer I think, please correct me If I am wrong.
Bro 39 = total no. of terms , but not the u only have to go 38 terms back to get t72.
Ex: from 1 to 10 there are a total of 10 terms , but when u want to go back to T1 u have to subtract (10-1)9 terms only ( only then 10-9 = T1 ) ( but u will not subtract 10 no. of terms that gives 10-10=0) .
@@msaisubbarajuvarma5406 great 🔥❤️
I think u r correct
What is the the meaning of the last part of the question in 2nd last question i.e., finding P in terms of 'n'?
it means u have to find P from N
Thank u so much sir, love u❤
Thank you so much rodha classes ❤❤❤
Bhai cat 23 de rhe ho?
What does it mean to find 'P' in terms of 'n'? I don't seem to get this. May be as a result, i don't understand why P= n-76 i.e., what is even being gained after finding this expression?
Did you understand the question now ?
If yes then please tell me
Any one can provide questions for practice
Thank you for Everything sir❤️
Amazing question
thank you sir for explaining !!
likewise when am counting backwards shouldn't it be 38+1=39 terms like from 110 to 72
Those aren't the number of terms, those are the no. of terms you are going back.
Thank you, sir.
your voice is not audible clearly but apart from that the content you provide is very useful.
How did we get that super hard second-last question (for a beginner) but the last question was a total freebie... lmao
Sir i am get confused P=t72 .
T76+T143=109.5 so avg is t109 & t110= n
And if n is not a part of A.P how we calculate? n-2,n-4...
it will start from t77, (difference +1 )....i.e.(t143 - t67 + 1) = t77
Can someone tell me what is even and ord
Thankyou sir
Thank you sir
can anyone tell me how did we assume that the difference between each term is 2 in the t143 question? im confused.
It's given in the question that the series is of consecutive odd integers (like -3,5,7,9) here the difference is of two between them so in that series it will also 2
21:57 if we take avg for 76 terms and add avg for 67 term we should get P right?
Sir what about percentage more video?
Thats what you can expect from free classes😆😆
@Sim Sidhanti from arun sharma books
Here: th-cam.com/video/bigCbKeUPO4/w-d-xo.html
Sir Could you share the telegram link
thankyou so much sir for your hardwork
Thank you guruji ❤
Thank you so much sir❤
Thanks sir , really
can anyone explain what's the difference between term & an odd Integer
if 143 consecutive odd interger is 1,3,5,7,9........................143
and
T1 = 1, T2 = 3 , T3 = 9
then average of last 67 term should be
T6 = 11
If you are assuming the first term of AP as 1 and since the common difference is 2 your last term cannot be 143 it must be 285. So the value of your 143th term would be 285. 143 is the position and 285 is the value. This is the difference. Hope it helps ❤
Plss answer anyone. I want to do more questions like this where I get type of question
Sir , How can you write t1+t143 = t144 ? Explain please !
Bro when we take need to find average and series is in AP we take first and last term and divide it by 2.
hello sir how can we contact u ??
ek question ni aya samajh i having a DOUBT ON THAT HOW COULD I clear my doubt sir reply immediately.... thank u
telegram group, facebook group.
Thanq sir
Thank You Sir
Can some1 explain y it’s t110 n not t109
Completed Done🎉
Sir you said avg of odd no is always part of series but in case of 12consevutive odd no's 30 is not part of the series also t6 and t7 can be 27 and 33 also whose avg is also 30
If no. Of terms are even then avg may not be part of series here no. Of term is 12
He did not say avg of odd no is part of series, instead he said average of odd number of terms is a part of series
In the question no of terms is even so, it's not a part of the series
P= N-76 OR P=N +76 is the answer? I got P= N +76 as the answer... please correct me if I am wrong...
Bro mera bhi n+76 h
Sir I have doubt if we take 24,28,32,36,40,44,48 product of 2nd and 5th is 1120 also
BTW it also depends on given options also...
yes exactly, why you considered the difference as two ?
Consecutive even integers that's y..
But where is Averages 3 class????
If we subtract n-76 then answer will be 34 will come but p is =72 can anybody explain?
t110 is the no. of term and not the term itself so you cannot directly subtract it from 76
Sir plzz upload the fourth or another video of percentage. I stuck while solving questions.
Grt explanation sir❣️💥🌟
in last question, why he considered diff as 2??
i think bcoz consecutive odd numbers are given in ques
In 14:03 the series can also be a 27,30,33 na sir ?
Bcz of consecutive odd integers (gap should be of 2)
How did he just solve 32*38 without writing down anything? How do I get that good?
It's 2*8 =16 and 3*(3+1)=12 => 1216
Same way u can do for 31*39=1209
42*48=2016
@@aakashdinkar8096 sum of unit digit of both is 10. whenever u observe no. like this.
(i) find avg i.e. (32+38)/2=35
(ii) Now, (35-3)*(35+2)=35*35-3*3
done
watch speed math lectures to get a better understanding
use vedic maths
@@aakashdinkar8096 59*47?
I love you so much dear beloved sir,...
Your videos are Like sanjeevni to me .🙏
One request sir I'm unable to find out the Videos on Blood relation sir, if they are plse help sir ..
I will be highly thankful to you
I ll record & upload
T143+77=120
143+77/2=60
cant we take the difference of 4 the middle term question. Why does it have to be 2 only.
because they are odd integers
Sir, Sorry! but i don't understand how the difference between 10 to 20 is =11? it should be 10 only.
hello People, you can also answer if you want.
10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20 these are 11 terms now, so we have to start from 11 on wards not 10
But sir is it always the case that a series with even number has avg which is not part of the series . Because if we take 2,4,6,8,10 . The avg is 6 which is indeed part of the series .
Hyy by the even numbers he meant the number of numbers not the individual number is even or not
@@ananya7687 but avg of 2,4,6,8,10 is 6 and it is part of the series .
@@songoku-jx3cb yaa it is the part of series because the number of numbers is odd (5)
I will give you an another example find the average of 2,4,6,8,10,12 here the number of series is (6) and it is an even number so the average won't be the part of series ... The answer is 7
@@ananya7687 ok, thanks a lot . I finally understood it .
thankyou sir
Is calculator is allowed in CAT ?
Yes
@@swatibisht4572
Sir calculator are allowed in cat exam
On screen calculator not physical calculator
Odd number Wale no. Ka half kyse nikalte h samjh nahi aa raha - like 93 , 793 , 435 ,
Divide by 2
sir how did you do 32*38 mentally?
35*35-3*3
@@subhashinijanakiraman1018 check speed maths video in playlist
👍
why are we assuming a gap of 2 in all questions?
Consecutive numbers
@@AASAM777 Ooh ok thank you so much, bro.
@@user-wr4oc7hl8d 😉😊😇
Can anybody explain how he calculated 32*38 so fast?
Watch his Speed Math episode 5
32(40-2)
Sir 38*-2= -76
Then it will be n-(-76)
I.e., p=n+76
First how can P be more than n if these are 143 consecutive odd integer?? Second n is nothing but 110th term of the sequence and we are required to find 72th term thats y we are subtracting 76 from 110th term i.e. n to get the 72th term.
How can he find that the difference between the no's is 2 in last question
Sir ek request thi videos Hindi me banate toh aur acha rehta
God bless him
TX sir
22:00
DAY_5_Avg 1
Sir, what if there is more than two figures?
1. Chetan purchased two dozen mangoes of one variety@₹6, 4 dozens of @₹7, 1 dozens mangoes @₹9 per dozens respectively.
What will be the average cost per dozen of mangoes purchased by Chetan?
cost of 2 dozen = 6x2=12rs
cost of 4 dozen = 4x7=28rs
cost of 1 dozen = 1x9=9rs
so, 7 dozen mangos = 49
then, avg. cost per dozen mango is 49/7=7rs
I can’t find the 4th video for percentage. Pls help
I don't think there is a fourth video for percentage
they haven't uploaded it yet i think
Yea I too feel the same I guess they have deleted it
search amit surana cat he completed all topic of percentages
He has actually uploaded it, It's just that he forgot to add some videos in the playlist, Search it manually in the youtube search bar. th-cam.com/video/bigCbKeUPO4/w-d-xo.html (Ik this might not be relevant to you after a year, I've commented for other viewers who'll be watching this video in the future)