Moment(M) is a force(F) acting around some center or axis times lever arm M = F * r so moment acting on a center can be replaced by a force on a the end of the moment arm
the directions of moments due to vertical rolling resistance force and the horizontal replaced one are different. Is it not wrong? How can u replace one moment in one direction with a moment in reversed direction ?
Maybe for comfort riding, as street roads and vehicles not always follow ideally straight and plain road, bumps and ditches are there.... Also in locomotives metal wheels are used, less energy loss, completely different scenario than roads, on track
Rolling resistance occurs as a result of shifting of normal reaction right??and we r replacing it also by another force.then why do we again include normal reaction in free body diagram??
Sir, as you said that rolling resistance force is added in order to replace a moment, so is this a real force? Do we consider it if we use F=m*a in X-direction?
I have a bit of a problem understanding why does the force shift foward due to the elastomeric property of the tire. Is it related to the reaction or something else ?
I think this is only the depiction of the rolling resistance force from front. Actually it is caused due to this shift in reaction force when a tyre starts to roll.
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The best possible explanation for rolling resistance.
It is ISO 8855 code for vehicle dynamics sign convention. (SAE J670e works too)
Gosh, I really wish be like this Sir, just espetacular.
thank you so mush sir we are very fortunate as we can access your lecture.
Excellent! Thank you very much.
dlamberts equation is the equation what will happens when N limit tends to 1 to infinity. U_n/U_n+1
how can you replace a moment by a single force?
like you did for opposing moment at the end of lecture?
Moment(M) is a force(F) acting around some center or axis times lever arm
M = F * r
so moment acting on a center can be replaced by a force on a the end of the moment arm
We are not replacing moment. We are replacing force by force.
Excellent 👍
the directions of moments due to vertical rolling resistance force and the horizontal replaced one are different. Is it not wrong? How can u replace one moment in one direction with a moment in reversed direction ?
same ques from me too.
since elastomers follow same path in loading and unloading than why we use visco elastic material which produces hystersis loss
+Car Tech (AutomotiveTechnology) Viscoelasticity is the property of the elastomer. Elastomer itself is a visco elastic material.
Hi /Car Tech, Please share the link with examples. So that doubts can be clarified.
Thank you
Maybe for comfort riding, as street roads and vehicles not always follow ideally straight and plain road, bumps and ditches are there.... Also in locomotives metal wheels are used, less energy loss, completely different scenario than roads, on track
Rolling resistance occurs as a result of shifting of normal reaction right??and we r replacing it also by another force.then why do we again include normal reaction in free body diagram??
Sir, as you said that rolling resistance force is added in order to replace a moment, so is this a real force? Do we consider it if we use F=m*a in X-direction?
I have a bit of a problem understanding why does the force shift foward due to the elastomeric property of the tire. Is it related to the reaction or something else ?
More specifically, are we considering that a thread has a “length” where one side is being loaded and the other not?
I think this is only the depiction of the rolling resistance force from front. Actually it is caused due to this shift in reaction force when a tyre starts to roll.
If we are using the vulcanised rubber tyre then there may be very low or no hysteresis losses.
5:44 and pause - Professor, are you a fan of the Gremlin? 😄
Sir!!
How does the combined effect of cornering, braking/accelerating and steering torque (input) affect the shape of the contact patch?
Make it readable😊
what is this D'alembert's Force? why take it into consideration when you take longitudinal force = m*a into consideration, isnt it the same?
The D'alembert's force is the force on account of the inertia of the vehicle which is m*a.
D'alembert's Force is just a pseudo force -> -m*a treated as a force so that equations of static equilibrium can be applied.
okay
iso 8855 not iso 8555