It took me a very long time, but I managed the puzzle. One significant step was when I found a 4567 bent quad, three digits on the upper-right thermo and one on the lower-right thermo. After virtually all the thermos were either Sudoku-determined or filled in, I centermarked the grid. A no-doubt insignificant find was a finned swordfish in 2s. I kept trying to search for something. Finally I found that 5 (of 25) in R5C7 gave me an oddigon. 2 in the cell finally solved the puzzle. 9:50 5 is in the middle column of block 2. That forces the two 5s into the four bulbs below. Remove a couple of 5s. If R7C7 is 4, the thermo above must be (34)567. If R7C7 is 7, the thermo above must be (3)456. (That's what I called the bent quad.) 26:00 Now that you've narrowed the R8C6 bulb to 36, notice that 3 followed by 7 forces 3456 on the upper thermo -- a crash of 3s. Therefore, 3 must be followed by 4 (The 5 in that cell on the thermo should have been removed.) and also forces 4 into R3C6 -- eliminating 4s from around the circle. Therefore, R8C6 must be 6. 28:20 The centermarked 5s at the top in column 5... 33:50 Now that 5's were addressed, perhaps a simpler explanation for 3 in R8C6. It forces 4567 in the upper thermo, which forces 4 in the cell after 3 in the lower thermo, which eliminates 4s from the 45 circle. 51:20 I see how the pinned comment works, with R9C8 forcing blue to be 1. I don't know if I would have spotted it in my solve, had I kept the 12s colored.
A but frustrating. Got to the point in the video @52:30 in abut 20 minutes and then just sat there Looking for a hint, I think you got you over0used your deduction @52:30. Now I have a puzzle I have spent a lot of time staring at that I cannot finish.
Got stuck on the same point, but I got past, and can give my path. Consider R7C4, and the implications for each option. You'll likely find that, after tracing implications around the grid, they both end up with 2 in R5C7. That allows progress.
I'm not sure how I solved this the first time around, but I ended up with a lucky bifurcation this time that I only could figure out why it was right while thinking about it during watching BremSter's solve. My time did improve: 50:00 vs 28:08 (conflict checker off), but not fully happy with this solve. Still a cool puzzle, though!
@52:30 You don't have proper explaniation for why blue is 1 and not 2. I used the 1,3 in box 9 to figure it out.
That would be the correct way to do it.
If r9c8 is a 3, then through b7 blue is 1. If r9c8 is 1, then through b3 blue is 1.
Excellent spot.
Thanks for your explanation.
This puzzle should be called "If this is" I couldn't even count how many times you said this.
26:22 the end was not easy, indeed. Thanks to one comment hete I could find the solution. But thank you for the solve, as always! ☺
It took me a very long time, but I managed the puzzle. One significant step was when I found a 4567 bent quad, three digits on the upper-right thermo and one on the lower-right thermo. After virtually all the thermos were either Sudoku-determined or filled in, I centermarked the grid. A no-doubt insignificant find was a finned swordfish in 2s. I kept trying to search for something. Finally I found that 5 (of 25) in R5C7 gave me an oddigon. 2 in the cell finally solved the puzzle.
9:50 5 is in the middle column of block 2. That forces the two 5s into the four bulbs below. Remove a couple of 5s. If R7C7 is 4, the thermo above must be (34)567. If R7C7 is 7, the thermo above must be (3)456. (That's what I called the bent quad.)
26:00 Now that you've narrowed the R8C6 bulb to 36, notice that 3 followed by 7 forces 3456 on the upper thermo -- a crash of 3s. Therefore, 3 must be followed by 4 (The 5 in that cell on the thermo should have been removed.) and also forces 4 into R3C6 -- eliminating 4s from around the circle. Therefore, R8C6 must be 6.
28:20 The centermarked 5s at the top in column 5...
33:50 Now that 5's were addressed, perhaps a simpler explanation for 3 in R8C6. It forces 4567 in the upper thermo, which forces 4 in the cell after 3 in the lower thermo, which eliminates 4s from the 45 circle.
51:20 I see how the pinned comment works, with R9C8 forcing blue to be 1. I don't know if I would have spotted it in my solve, had I kept the 12s colored.
26:07 after using an XY-wing at the end.
A but frustrating. Got to the point in the video @52:30 in abut 20 minutes and then just sat there Looking for a hint, I think you got you over0used your deduction @52:30. Now I have a puzzle I have spent a lot of time staring at that I cannot finish.
Got stuck on the same point, but I got past, and can give my path.
Consider R7C4, and the implications for each option. You'll likely find that, after tracing implications around the grid, they both end up with 2 in R5C7. That allows progress.
@@Nick-jq5nl Ah yes - thanks. If 3, we end up with a conflict in box 9. Tough to spot that one.
This one made my brain hurt!
00:24:00
Really couldn't get my head around this one
GEOMETRY!!! Completed in 18m43s.
You need to write a better explanation than THAT 😂
I'm not sure how I solved this the first time around, but I ended up with a lucky bifurcation this time that I only could figure out why it was right while thinking about it during watching BremSter's solve. My time did improve: 50:00 vs 28:08 (conflict checker off), but not fully happy with this solve. Still a cool puzzle, though!
OW, that stung, aptly named, I guess
28 minutest to solve, the hardest part to find was the center quad thermo logic, but otherwise it felt pretty normal.
Coloring 89 in first row would have saved a lot of trouble, IMHO.
"This a 348 triple so this is a one".... No explanation as to why.
And it is literally the key unexplained logic that solves the rest of puzzle.
Yeah - that was a mistake, but there is an excellent comment by another solver that I have pinned that explains the key cell to break it open.