according to the second postulate , in question IV light shouldn't be affected like the baseballs in your example (though intuitively i understand it) so shouldnt the relative speed of light always be C ?
I have the same confusion, Mohab. This makes so much more sense. I guess part of the issue is exactly what does it mean for someone to 'measure the speed of light'?
Anne sees light leave her ship at speed c, it is just that sue is moving away from her, so Anne does not see Sue receive the light at speed c, but at the relative speed of 0.2c. Sue also receives the light at speed c, but does not see the speed of light to be c relative to Anne since Anne is moving relative to her.
Can somebody find the mistake in the following solution to Ann-Sue question part (iv), thanks! Take Sue/Earth as reference frame. time (measured by Sue) = 8.8 cy / c =8.8 year time (measured by Ann) = time (measured by Sue ) / (5/3 ) = 5.28 year
FANTASTIC! This cleared up many questions I had about Special Relativity. At last! Thank you!
Glad it was helpful!
according to the second postulate , in question IV light shouldn't be affected like the baseballs in your example (though intuitively i understand it) so shouldnt the relative speed of light always be C ?
It is. What are you referring to specifically?
Rocket girl will see light at speed c (no discrepencies) and also she'll see planets moving
I have the same confusion, Mohab. This makes so much more sense. I guess part of the issue is exactly what does it mean for someone to 'measure the speed of light'?
Anne sees light leave her ship at speed c, it is just that sue is moving away from her, so Anne does not see Sue receive the light at speed c, but at the relative speed of 0.2c. Sue also receives the light at speed c, but does not see the speed of light to be c relative to Anne since Anne is moving relative to her.
@@donerphysics please post more about this. It's the part that continues to surprise and confuse some of us.
Thank you!
Thank you so much.
You're welcome!
Can somebody find the mistake in the following solution to Ann-Sue question part (iv), thanks!
Take Sue/Earth as reference frame.
time (measured by Sue) = 8.8 cy / c =8.8 year
time (measured by Ann) = time (measured by Sue ) / (5/3 ) = 5.28 year
this helped. my textbook sucks.
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