Lec 12 Beams III

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  • เผยแพร่เมื่อ 5 มี.ค. 2019
  • Revisiting Sign Conventions for SFD and BMD, Drawing SFD and BMD- method of calculation in finding reactions and writing FBD for desired sections, SFD and BMD for simple loading situations, Principle of Superposition, Inter-relationship between Loading, SFD and BMD- Differential equilibrium relationships.
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ความคิดเห็น • 12

  • @thinkgrow4296
    @thinkgrow4296 3 ปีที่แล้ว +6

    Thank You sir .. for this great effort.... I was very much comfortable with the the first sign convention from the beginning but after understanding that you are going to follow the second one from now onwards I decided to follow that....

  • @surajkakati1140
    @surajkakati1140 6 หลายเดือนก่อน +2

    Sir,
    At time stamp 47:31
    How come we can know that M+delta(M) and V+delta(V) is as per the direction shown in the example the cut out section of lenght delta(x)
    If in the above section the direction of M+delta(M) and V+delta(V) is reversed we cannot arrive at the outcome equation
    Please explain the logic behind the consideration of the direction
    Regards

  • @janakamohotti
    @janakamohotti 3 ปีที่แล้ว +1

    Great lecture ❤️

  • @AmarSingh-kk3kx
    @AmarSingh-kk3kx 4 ปีที่แล้ว +2

    Sir please do not miss the middle steps and directly right the answers because sometimes getting confused.

    • @Inquisite1031
      @Inquisite1031 8 หลายเดือนก่อน +1

      I don't mean to sound like an asshole, but if u cant do such simple calculations, u need to revise highschool physics textbooks, if they have to repeat highschool level physics/mathematics every time we will never finish the course lol.

  • @user-lo6fg9ym7r
    @user-lo6fg9ym7r 8 หลายเดือนก่อน

    great sir

  • @shreytiwari5392
    @shreytiwari5392 3 ปีที่แล้ว +1

    Okay🙃

  • @ShivanSubhashhandge
    @ShivanSubhashhandge 5 ปีที่แล้ว

    Link for lecture 9

    • @melvindavis3629
      @melvindavis3629 4 ปีที่แล้ว

      th-cam.com/video/ef-5HtnBubU/w-d-xo.html&feature=emb_logo

    • @bhagyeshmadas456
      @bhagyeshmadas456 4 หลายเดือนก่อน

      th-cam.com/video/ef-5HtnBubU/w-d-xo.htmlsi=t16SL7P5QWknsPFR

  • @guesswho-og2wv
    @guesswho-og2wv 11 หลายเดือนก่อน

    A conceptual question if someone may answer : How can something called "force per unit length" be a continuous function as shown. Meaning what this function essentially means is for every value of x ; which are essentially discrete points on the x - axis ; there exists a value y, called force per unit length? How is force "per unit length" defined for a point ? I believe it can't be defined for discrete points? Has anyone got an explanation? Please do share 🙏

    • @Inquisite1031
      @Inquisite1031 8 หลายเดือนก่อน

      it simply means at distance x from the origin there is a force y, and who said the function representing force on a beam is always continuous ? it can be discontinuous, it can even be discontinuous and not be defined for all values of x.