Measuring Internal Resistance - PRACTICAL - A Level Physics
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- เผยแพร่เมื่อ 28 ส.ค. 2024
- In this video I go through an AQA Physics A Level Required Practical that uses an electrical circuit experiment to measure the internal resistance of a cell or battery. (This is AQA Required Practical 6.) This is also the OCR A Level Physics PAG 3.3 Practical.
Internal resistance is the electrical resistance within the cell or battery that is powering the circuit. Measuring internal resistance can be done by changing the external resistance of the circuit and recording the terminal p.d of the cell. When a graph is plotted the gradient is the negative value of 'r' while the y-intercept should be equal to the e.m.f. of the cell.
See instructions for all the practicals at www.alevelphysi...
Thanks for watching,
Lewis
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Mate, you're a life saver!
Thanks
Literally made my day and was able to use this to analyse to different sets of cells and the results were astonishing! Thank you!! 😀
Wow thanks! I am taking an electricity and optics lab but because of covid it is all online and you are doing a better job at explaining this than my professor and TAs
You are a hero, have subscribed!
Hi, I was wondering what some of the key risks to consider are
Thank you for the great explanation!
Thank you for this video however what is the point in the switch?
It was an amazing explanation. Thank you 😄
Why doesn’t putting the voltmeter across the terminals give us electromotive force? Isn’t it measuring the pd of the terminal and the internal resistance?
It will give a value very close to the emf, but the voltmeter could draw a very small current so your terminal pd measured may be lower.
@@PhysicsOnline Would the value on the voltmere still equal the external voltage that goes to the rest of the circuit?
@@matteo5399 no
I don't know but if we want to measure the internal resistance of voltameter we should put the voltameter in series with the circuit, I know it have too much resistance, so we can measure it?
Very good but internal resistance of the cell and wiring, no?
This was so helpful. You made it interesting. Thanks! :)
Jordan Gatt All Physics is interesting!
+A Level Physics Online circuits and electricity is in no way interesting to me but your short, to the point videos are engaging and make everything intuitive for something you can spend 10x the time on and not get :)
+A Level Physics Online also I'd like to ask a question, have you covered the practicals on the gas laws? Some of the videos in the playlist are private so I wondered if those are them.
Thanks for the video sir! I was just wondering- wouldn't you need a fixed resistor to be in the circuit as well in order to have a better control of the current- for safety reasons?
It'll be like a 1A current at most, so I don't think it'll be that dangerous.
Sir,Will the resistance of the voltmeter and ammeter affect the calculation??
No
thank youu sooo much
Nice, but... What is the point of taking a few measurements? I see two: a) ascertain that internal resistance is linear in the range of drawn currents (because you obtain a straight line with certain slope) (and this does not need to be the case), and b) accuracy of the measurements. But technically, you could get this "internal resistance" using just a single measurement and dividing U/I. So, my question is: do you really get the true EMF and internal resistance using this method?
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