8-44| Principal Stress under Given Loading (Beer & Johnston)|

แชร์
ฝัง
  • เผยแพร่เมื่อ 12 พ.ย. 2024

ความคิดเห็น • 16

  • @kc9487
    @kc9487 13 วันที่ผ่านมา +2

    in getting the normal stress in the Y axis (for point H) why did we not include the compressive force 2500 ? i think it still experiences normal compressive force but there is no stress due to bending moment.

    • @engradnanrasheedmechanical
      @engradnanrasheedmechanical  13 วันที่ผ่านมา +1

      In y direction there is no normal force . You can check that again. Thank you

    • @kc9487
      @kc9487 13 วันที่ผ่านมา +1

      there is, due to force in the z direction (which acts perpendicular to the cross section)

    • @engradnanrasheedmechanical
      @engradnanrasheedmechanical  13 วันที่ผ่านมา +1

      @kc9487 which will be normal stress in z direction

    • @kc9487
      @kc9487 13 วันที่ผ่านมา +1

      @@engradnanrasheedmechanicalyou added the normal compresive stress (2500 lb) in the stress at x axis, so why would not we add it in the stress at y axis?

    • @engradnanrasheedmechanical
      @engradnanrasheedmechanical  13 วันที่ผ่านมา +1

      @kc9487 normal compressive stress is not in x direction its along z direction.

  • @justinseals2816
    @justinseals2816 6 หลายเดือนก่อน +1

    Can you explain why the clockwise torque around the z-axis isn't negative? Is the problem making the clockwise direction positive?

  • @HashemAljifri515
    @HashemAljifri515 11 หลายเดือนก่อน +2

    What a chapter man!! Very confusing

    • @engradnanrasheedmechanical
      @engradnanrasheedmechanical  11 หลายเดือนก่อน +1

      why is it so confusing for you?

    • @HashemAljifri515
      @HashemAljifri515 11 หลายเดือนก่อน +2

      @@engradnanrasheedmechanical There are two moments on each axis, also torsion.. It's mind blowing when trying to figure out what are the moments acting on each axis

    • @engradnanrasheedmechanical
      @engradnanrasheedmechanical  11 หลายเดือนก่อน +2

      @HashemAljifri515 yes first 2 times it will be difficult but when you try yourself i am hopeful that you will get it. Try to think and try to solve it by your self after pausing every step try to do it on paper.

  • @doguhanozms4238
    @doguhanozms4238 ปีที่แล้ว +1

    Why hocam k is not a neutral axis I think torsion will be zero?

  • @harshsavla555
    @harshsavla555 5 หลายเดือนก่อน +1

    Why is Q zero at H but not K. They both lie on the edge of the circle

    • @engradnanrasheedmechanical
      @engradnanrasheedmechanical  5 หลายเดือนก่อน +1

      H lies on the outer surface and away from neutral axis and area about H is 0 so Q is zero. While K lies on neutral axis and there is area above K which is not equal to 0 . That's why its Q is not equal to zero.