Calculating t1^ in e1-e2-e3 coordinate system will give (1 1 0)' while that in e1^-e2^-e3^ coordinate system will give (1.414 0 0)'. You can also verify that these two are equivalent in terms of the final vector. The sigma^ matrix gives the values in e1^-e2^-e3^ coordinate system. Basically, we could compare t2^ because a zero vector has all components as zero in every coordinate system.
What you obtained is in e1-e2-e3 system as mentioned by Siddhant. You can get the same vector in e1^-e2^-e3^ by using rotation matrix, i.e. [(R)transpose][t1 vector].
my curiosity for matrix is dead !! excellent iit professor
Sir,
for the final problem, if we calculate t1^ we get (1 1 0)' but we should have got (1.414 0 0)'
Can you kindly explain that ?
Thanks
Calculating t1^ in e1-e2-e3 coordinate system will give (1 1 0)' while that in e1^-e2^-e3^ coordinate system will give (1.414 0 0)'. You can also verify that these two are equivalent in terms of the final vector. The sigma^ matrix gives the values in e1^-e2^-e3^ coordinate system. Basically, we could compare t2^ because a zero vector has all components as zero in every coordinate system.
What you obtained is in e1-e2-e3 system as mentioned by Siddhant. You can get the same vector in e1^-e2^-e3^ by using rotation matrix, i.e. [(R)transpose][t1 vector].