That's awesome that you're starting on your path to become an EE! Engineers change the world! Thanks for the feedback, we haven't done much to promote ourselves up until now, but we've been pretty steady in releasing new tutorials, interviews, etc. Also, check out our site CircuitBread.com where we have electronics tutorials, tools, an equation library, terms, article highlighting, and some fun content. We're also on Facebook, Instagram, and Twitter. We're always looking for feedback on existing content and suggestions for improvements, so don't hesitate to reach out!
Always appreciate the feedback and we're glad you liked it! We try our best to make electronics concepts easy to understand, we just hope we keep improving with our content. :-) We have quite a bit more to look at on our site CircuitBread.com and TH-cam channel.
I have a 2 color LED. Ground is common. So I have one ground pin. And I have 2 pins for the 2 colors. I know how to make this work. i.e. I can get both the colors to light up. Using ground and plus voltage. Now where I want to use this LED I have an audio circuit where I have +12V and -12v. And ground. By looking at the LED I want to confirm that both my positive rail and negative rail have power. How would I wire this. I have hooked up ground to ground. And one leg to +12 volts and the led glows. (Lets leave the resistor on the ground pin out of the equation for now). But when I connect the leg to the negative rail I get no light. Can you explain this in one of your videos.
@@CircuitBreadplease help me! 😭 Okay I've got an Olight Baldr Pro (wit a green Lazer), it's a weapon mounted light. Now it requires 2x3v batteries (cr123). The light itself has 2 settings bright (1200 lumens) and a low setting (300-500 lumens). My question is can I run 2x3.7v batteries (16340) and then keep it on the "low" setting without damaging the Led? It looks like the batteries are in series since the positive and negative differs when inserting the batteries. The cr123 batteries are really expensive and I don't mind the shorter runtime the 16340 batteries offer as I can regularly recharge them.
Nope! Polarized in electrical terms (versus optical) just means that you care which side is positive and which side is negative. Resistors don't care, most capacitors don't care, most (maybe all?) inductors don't care, but if you hook up an LED backward, it won't work. Or any diode, for that matter.
Underated channel
brilliant video, I've actually been searching for a youtube account like this, starting EE in september. cant believe you only have 184 subs.
That's awesome that you're starting on your path to become an EE! Engineers change the world! Thanks for the feedback, we haven't done much to promote ourselves up until now, but we've been pretty steady in releasing new tutorials, interviews, etc. Also, check out our site CircuitBread.com where we have electronics tutorials, tools, an equation library, terms, article highlighting, and some fun content. We're also on Facebook, Instagram, and Twitter. We're always looking for feedback on existing content and suggestions for improvements, so don't hesitate to reach out!
Nice video! Love the way you simplify things too! Remember me when you get bigger
Always appreciate the feedback and we're glad you liked it! We try our best to make electronics concepts easy to understand, we just hope we keep improving with our content. :-) We have quite a bit more to look at on our site CircuitBread.com and TH-cam channel.
Why mixing led light-bulbs size don’t work properly in a series set?
I have a 2 color LED. Ground is common. So I have one ground pin. And I have 2 pins for the 2 colors.
I know how to make this work. i.e. I can get both the colors to light up. Using ground and plus voltage.
Now where I want to use this LED
I have an audio circuit where I have +12V and -12v. And ground.
By looking at the LED I want to confirm that both my positive rail and negative rail have power.
How would I wire this.
I have hooked up ground to ground. And one leg to +12 volts and the led glows. (Lets leave the resistor on the ground pin out of the equation for now). But when I connect the leg to the negative rail I get no light.
Can you explain this in one of your videos.
I can't wait for part 2 😁
Awesome, we're glad you liked it! We actually have a few more of these coming for LEDs soon. Stay tuned!
Just a heads up, part 2 of this series has been published here (we have more coming): th-cam.com/video/N9g7aAZPbno/w-d-xo.html
@@CircuitBreadplease help me! 😭
Okay I've got an Olight Baldr Pro (wit a green Lazer), it's a weapon mounted light.
Now it requires 2x3v batteries (cr123).
The light itself has 2 settings bright (1200 lumens) and a low setting (300-500 lumens).
My question is can I run 2x3.7v batteries (16340) and then keep it on the "low" setting without damaging the Led?
It looks like the batteries are in series since the positive and negative differs when inserting the batteries.
The cr123 batteries are really expensive and I don't mind the shorter runtime the 16340 batteries offer as I can regularly recharge them.
polarized -- did they mean like a laser? If so, an LED is unpolarized!
Nope! Polarized in electrical terms (versus optical) just means that you care which side is positive and which side is negative. Resistors don't care, most capacitors don't care, most (maybe all?) inductors don't care, but if you hook up an LED backward, it won't work. Or any diode, for that matter.