Sir..kuch books ha jisme support B sink hota ha jiska value negative and iske sat support A and C (delta A&C) ka value hoga positive E.g. if support B sinks -5mm Then delta A and delta C becomes positive While in ur video u hav told us to takr delta A and C to be 0 zero Pls can u elaborate on this
Good presentation sir. Please if include the deflected shape of the beam . It will make students to understand the nature of BM. at continuous support . BM at fixedend A is positive and BMD shows negative.
Bhai ek beam h ....a to b.... Usme starting se 4m baad ek point load then after 8m there is a support(prop) then udl of 4kn/m at a distance of 6m......please give me the answer of the question........
Hello Sir, Is there possibility of any simplified method I think the time may be reduced if every step is explained with the main figure ie BM diagram itself and also the reactions may be computed by incorporating all obtained data on the loading diagram. Pl examine, Thank you.
सर आपके अनुसार यदि किसी स्थान का फर्स्ट मोमेंट नेगेटिव हो और सेकंड पॉजिटिव ,तो net BM me नेगेटिव वाले को ऊपर दिखाते हो , पॉजिटिव है तो इसे नेट बैंकिंग मोमेंट में नीचे सर लेकिन yha आपने + vale ko ऊपर क्यों दिखाया यह कैसे हुआ ? Any person reply
Sir M@A +ve hai to neutral axis ke above lii hai aur baki sub moment -ve hai to vo bhi neutral axis ke above hai...aisa kyu??????plz reply me anyone fast...
Plz Watch ending of this video, in this how to apply final moments for net bending moment diagram is explained. th-cam.com/video/RbUy86JHybA/w-d-xo.html
@@GaneshShegar Dear sir ,, i watched this video as well on which moment value at A is negetive which has been taken above Neutral axis . and here in this problem moment at A was positive value and you have drawn it above neutral axis . It has become more confusion sir , please explain in net bending moment diagram is it true that both negetive and positive values of moment are to be taken above the neutral axis ? .. Please give answer sir .
Sir..kuch books ha jisme support B sink hota ha jiska value negative and iske sat support A and C (delta A&C) ka value hoga positive
E.g. if support B sinks -5mm
Then delta A and delta C becomes positive
While in ur video u hav told us to takr delta A and C to be 0 zero
Pls can u elaborate on this
Plz follow any one method completely, either the method shown in video or in the book, because different author's solves differently
Sir we got value of Ma =17.16, and Mb and Mc negative so why have we drawn Ma above axis in BMD.
In net BMD , Negative values are also drawn above neutral axis
Good presentation sir.
Please if include the deflected shape of the beam . It will make students to understand the nature of BM. at continuous support .
BM at fixedend A is positive and BMD shows negative.
Very easy explain thanks you so much sir
Bhai ek beam h ....a to b....
Usme starting se 4m baad ek point load then after 8m there is a support(prop) then udl of 4kn/m at a distance of 6m......please give me the answer of the question........
Thank u so much sir ...for very deepest explanation 🙏🙏🙏
sir ager EI value mm^2 mai given hoto settles value ko 1000 se divid nhi krna hena?? ...... settles value in mm
Hello Sir,
Is there possibility of any simplified method I think the time may be reduced if every step is explained with the main figure ie BM diagram itself and also the reactions may be computed by incorporating all obtained data on the loading diagram.
Pl examine,
Thank you.
Sir ji question me couple ka face upar ki tarap ho tb b aise hi solve hoga kya
Sir,
How to draw FMD for moment placed at the end of overhanging beam?
Sir ..but moment about C.. -10 kyu liye....Why not +10
सर आपके अनुसार यदि किसी स्थान का फर्स्ट मोमेंट नेगेटिव हो और सेकंड पॉजिटिव ,तो net BM me नेगेटिव वाले को ऊपर दिखाते हो , पॉजिटिव है तो इसे नेट बैंकिंग मोमेंट में नीचे सर लेकिन yha आपने + vale ko ऊपर क्यों दिखाया यह कैसे हुआ ? Any person reply
Sir bahut acche question leke aate ho. Bas ek bar 10KN ki jagah UDL le lijiye na
Sir what will be the equation if support B Settele by any dimension
Bm at positive should be below the line as per rule u mentioned negative should be above neutral axis
Sir ..what if the couple is pointing upward direction ?
Sir , Plz Can You Explain The Bending Movement
Three moment method se both end fix ka problem sole ho jayega kaya is par ake lacture banaye
Thank you sir
Sir slop Deflection method M settlement ka case kra digiye aur moment distribution M sway analysis ka case
L● ki value zero hai or right hand side me L● denominator me hai to pura term undefined ho jana chahiye but nhi consider kr rhe
Why?
Thank you
Sir fixed ends par hamesha hogging moments aaenge na tho aap ko sagging kaise aayi?
Sir M@A +ve hai to neutral axis ke above lii hai aur baki sub moment -ve hai to vo bhi neutral axis ke above hai...aisa kyu??????plz reply me anyone fast...
Plz Watch ending of this video, in this how to apply final moments for net bending moment diagram is explained. th-cam.com/video/RbUy86JHybA/w-d-xo.html
@@GaneshShegar Dear sir ,, i watched this video as well on which moment value at A is negetive which has been taken above Neutral axis . and here in this problem moment at A was positive value and you have drawn it above neutral axis . It has become more confusion sir , please explain in net bending moment diagram is it true that both negetive and positive values of moment are to be taken above the neutral axis ? .. Please give answer sir .
Best sir
Sir couple loding ka face uper ki tarp hone pr kaise solve kre please new video
Left end me Hing right end me fix rahega to start solve left taraf se karenga ya right
Start left se he Kar na hai Har bar and only Take imaginary point on beside of Fixed Support
Ek right fixed Wala batau middle span me couple rakhke sir pls one example bahut sir
@@GaneshShegar ek example jisme middle me couple right me fix and left me Hing pls sir
Sir
What happen when support B settles down by 8 mm
Then TMT become A-B-C
Then deflection kyaa consider krenge??? Plzz ans
No
A B C Mai Deflection agar A or C pe hoga to he lenge
B C D Mai Deflection agar B or D pe hoga to he lenge
Simple hai first letter and Last Letter
Sir... if In a beam has both side fixed ends then also we must take imaginary points.......
@ganeshshegar
Plz reply fast
Yes at each fixed end, an imaginary point has to be taken
Nice sir
Sir why don't we calculated B C D.
There's no support at D..
NET BMD GALAT DRAW KIYEHAI SIR APNE
APAKO M@A KA BM NICCHE DRAW KARNA CHAYIE
10 Kn ki jagah udl ho tho kya karna chaiye
❤️❤️❤️❤️
💖💖💖💖💖
Sink or settled both same are not
Yes bro
Their is -20 in 1st equ.
20.1 is correct
Sir apka whatsapp no dijiye