Oh! I wish I had discovered your channel earlier.I am glad i came across your channel. You made it very easy for me. I don't have enough words to thank you. God bless you and your family and the people who love and admire you. Thank you very much.
Mam, literally u are just wow, what a tecnic to making us understand, Literally I am very happy to find ur channel, i'm gonna to complet my whole chapter with u, tnk u mam, for giving us this in easiest form 😊💞
Thank you so so so much ma'am for these amazing lectures...I was very tensed for chemistry...and u taught all the topic with great explanation. With love and Regards ❤️
@@chemistrybydr.anjalissaxena love you mam , apke ek hi lecture me clear ho gaya .and for you kind information.all my classmate also watch your lectres .and you are popular in my collage.and my seniors suggest your channel.
00:01 UV spectroscopy selection rules explained 01:21 Selection rule for electronic transitions in UV spectroscopy 02:47 Selection rules in UV spectroscopy 03:59 UV active compounds are activated by radiation 05:21 Understanding electronic transitions is key to UV activity 07:21 UV active compounds have specific electronic transition selection rules. 09:08 UV active compounds absorb UV light 10:41 UV active compounds undergo electronic transitions Crafted by Merlin AI.
Both acetic acid (CH3COOH) and nitromethane (CH3NO2) are UV-active, meaning they can absorb ultraviolet light. They are also chemically active, undergoing reactions based on their functional groups (acidic for CH3COOH, nitro group for CH3NO2). So there are UV active .
In Ch3COOH Four types of transition possible S --> s* π---> π* n---> s" n---> π* But b/c of high energy only sigma to sigma star aur n---> pi star not possible in uv /visible region hence these are uv inactive while remaining both are uv active ... Overall compound will be considered as uv active.... CH3No2 same as above
I need to see the absorbance of dichloromethane by carbon by using uv visible spectrophotometer. I had already run a pure dichloromethane to full range of uv visible spectrum I e,190 nm-1100nm to see at which wavelength its peak is seen . And,its highest and clear peak have been seen in 208nm. But in literature the range of DCM for uv visible spectrum is 233nm, and highest 274 nm. Somewhere it is written the range is between 200-300nm. And according to 'OECD guidelines for testing of samples' by uv visible spectrum, it's range is 235 nm for dichloromethane. Now I am confused what wavelength range I must fix for my samples. Please guide me.
Both are active..... Thanku mam ... U r the First teacher whoes lecture made spectroscopy easy .... I was messed up by spectroscopy earlier
Glad to hear that. Like subscribe and share plz
@@chemistrybydr.anjalissaxena ok... Mam ...but why didn't u added whole topics ... Like Woodward rules ...nd NMR is also i guess somebit missing
Both are UV active. Thank you mam for this wonderful class.
Most welcome. Kindly Like subscribe and share the videos.
Yea mam both are. Active
nice explaination
ma'am both are active but is n→π* possible in CH₃NO₂?@@chemistrybydr.anjalissaxena
You are amazing teacher in the world 🌍 bcz you did explain this topic in deeply
Thank you so much! Keep watching and sharing the videos!
Oh! I wish I had discovered your channel earlier.I am glad i came across your channel. You made it very easy for me.
I don't have enough words to thank you.
God bless you and your family and the people who love and admire you.
Thank you very much.
Welcome! And thx u
Namaskaram Guru Maa
Ur lectures are helping me in my optional Chemistry for CSE.
Thank U so much Mam.
Huge respect from NW Jammu Kashmir
It's my pleasure
Both are uv active compound.Thank you mam for such a great video.your teaching technique is literally awesome.😊
Most welcome 😊
are maa'm you are a lifesaver
studying one night before
understood every thing thanks....
Mam, literally u are just wow, what a tecnic to making us understand, Literally I am very happy to find ur channel, i'm gonna to complet my whole chapter with u, tnk u mam, for giving us this in easiest form 😊💞
Thanks! Keep watching and keep up the good work!. Like subscribe and share the videos plz
Literally mam you don't need to say like share and subscribe...your kindness and the way are teaching is enough for this.❤️❤️
So nice of you
Yes ....both are UV active .... Keep on making these lecture .... Thank you so much mam ....
Thank you, I will
Maam apne jo padhaya bhot acche se samjh me aaya.
Thank you maam🙏
Most welco
Both are uv- active mam....i
Ur video are very helpful to me during my second semester....😊😊😊
Yes. Thx u
Mam aap bahoot accha padhati ..
Ye topic mera clear ho gya thnx mam..
Thx u. Keep watching and sharing the videos
Today I am watcing Spectroscopy Module .
Tommorow is my exam. I have also subscribed to your channel.❤
Thx u. All the best
both are uv active compound . thanku so much mam for this wonderfull class
Yes, correct
very well explanation mam it is very helpful for me i was very confused in this ...
Very helpful content for pharma student also ☺️
Glad it was helpful! Keep watching!
Both the compounds are UV Active because they have non-bonding and pie electrons. Thank you mam for this wonderful explanation.
Yes. Welcome
Thanks a lot Mam..how nicely you teach difficult topics..😊
Thanks for liking
Both of them are UV active compounds....and thank you Ma'am for your lectures
Most welcome 😊. Like subscribe and share plz
Blessed to have this channel in 1st year😌
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Both compounds are UV active🎉
Thank you ma'am❤
👍
Thank you so much mam. Kudos to your efforts!! WATCHING JUST BEFORE MY SEMESTER. Wish I could do this before....
Thank you again mam ❤️
All the best
@@chemistrybydr.anjalissaxena ❤️🙏🏻😇
Dil se maja aa gaya ma'am
Keep watching
Very well explained 🤗....now its easy to study
Thanks a lot 😊
12:04 ya both are uv active, thanku mam your lectures are awesome and very helpful so much of love to you mam..
👍. Thx u. Like subscribe and share plz
Both are uv active. Thanks for the wonderful tutorial .
Yes.Thx u. Kindly like, subscribe and share the videos.
Easy to understand explanation Mam!!
Keep watching
Thank you so so so much ma'am for these amazing lectures...I was very tensed for chemistry...and u taught all the topic with great explanation.
With love and Regards ❤️
Welcome. Keep watching and sharing the videos.
@@chemistrybydr.anjalissaxena ma'am...iss chapter ki PDF notes hai aapke pass?
Thank you so much mam concept is crystal clear🙏
Keep watching
Both are UV active . Thank you Ma'am ❤️
Yes. Most welcome
@@chemistrybydr.anjalissaxena love you mam , apke ek hi lecture me clear ho gaya .and for you kind information.all my classmate also watch your lectres .and you are popular in my collage.and my seniors suggest your channel.
Thanku mam.... There is my exam tomorrow and i am watching it today very helpful , crystal clear concepts❤
All the best
@@chemistrybydr.anjalissaxena thanku mam😊
thanks for this golden contents mam 🥰
Glad you like them!
Both are UV Active....Thank you for your lectures 😊
Yes they are. Like subscribe and share plz
Thanku man for this video I completely understand this topic 💯👍
Happy to help
Mam you explain so well... Thankyou for helping us...
Welcome. Plz like subscribe and share the videos.
Thank you so much mam it will help me a lot in my exam the concepts are beautifully explained ❤ new subscriber here
Great to hear! Keep watching and sharing the videos!
Tnx for uploading this amazing lecture 😊
It's my pleasure
Fantastic explanation ma'am. Hats off to you. Thank u ma'am
Welcome. Kindly like subscribe and share the videos.
00:01 UV spectroscopy selection rules explained
01:21 Selection rule for electronic transitions in UV spectroscopy
02:47 Selection rules in UV spectroscopy
03:59 UV active compounds are activated by radiation
05:21 Understanding electronic transitions is key to UV activity
07:21 UV active compounds have specific electronic transition selection rules.
09:08 UV active compounds absorb UV light
10:41 UV active compounds undergo electronic transitions
Crafted by Merlin AI.
Mam 28 second pe jo music hai wo bahut mast hai ❤️❤️
Glad you like it
Both are uv active because pi to pi star and n to pi star
Thank you mam❤
Always welcome
Well explained mam❤😊
Homework question solution:
CH3COOH and CH3NO2 both will be U.V active.
Yes, correct
Both are active.. Thankyou so much maam.. 🤗
Yes. Like subscribe and share plz
both are UV active compound. Thanks a lot mam
Yes, correct
Both are uv active ... thank you mam
Yes
Both acetic acid (CH3COOH) and nitromethane (CH3NO2) are UV-active, meaning they can absorb ultraviolet light. They are also chemically active, undergoing reactions based on their functional groups (acidic for CH3COOH, nitro group for CH3NO2). So there are UV active .
Yes
Both are active nice lecture
Yes, you are right
Both are uv active maam thank for this lecture ❤❤
Most welcome 😊
Both are uv active ma'am
Thank you so much
Yes
Both are active compound....by the way thanks ma'am...😊
Yes they are. Welcome
very nicely explained ,thank u maam
Keep watching
Both are uv active
Thanks mam
Yes they are
Bahut badhiya padhaya ma'am aap nae
Thx u. Keep watching and sharing the videos
@@chemistrybydr.anjalissaxena yes ma'am
tomorrow is my exam and ur lectures are really heplful
All the best
Thanks so much Mam... Your lectures on spectroscopy are amazing..
Glad you like them!
Both are active...And thank you mam
Most welcome 😊
Understood ma'am
both are uv active. thankyou ma'am
Yes, they are both UV active.
Thx a lot mam😍
My pleasure
These videos are really helpful. Can you please recommend book from where you are teaching?
Not a particular
Yes mam both are active compounds b/c pi pi stre and n pi bhi haii
Yes
Superb 👍
Thanks for liking
Ch3CooH- UV Active(contains π & n both π->π* n->π* causes spectrum)
Ch3No2- UV Active
Yes
Mam nice Explanation
Welcome
Thank you ma'am
Welcome
Thanks maam ,it is Really helpful
welcome. keep watching and sharing.
Thanks ❤
Keep watching and sharing the videos
Both CH3COOH, CH3NO2 will be Uv active as both contains N,pie electrons
Yes. Hope you understood well.
Donu UV active hoge maam.
And ur way of explanation is really good
Yes. Thx u so much
Both are UV active. Thank u mam
Yes they are
Thanks
Welcome
Acetic acid and nitromethane both are allowed to show transition resulting active uv spectroscopy thank you ma'am.
Yes
Kiya padate ho aap mam .❤❤ Thank you
Thx u. Like subscribe and share the videos plz
Both compounds are UV active.... Thankyou ma'am
Yes. Most welcome.
Thank u mam😊😊
welcome. kindly like, subscribe and share the video.
mam agar koi compound unsaturated h aur uske pass non bonding electron bhi h toh woh n to sigma antibonbing bhi toh show kar sakta h
Yes possible he but hoga nhi.
Thnkyou ao much mam
Most welcome 😊
Great
Thx u so much
Thankyou maam
Welcome
Ma'am can you please explain why n → σ* transition is forbidden
Mam bech ke itne sare topics kaha gye auxochrone , absorption and intesity shifts etc
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The above 2 compounds are uv active as they can undergo pie to pie as well as n to pie transition.i am grateful for your class mam have a good day
Yes. Thx u so much
mam CH3COOH will be active but why CH3NO2 will be active does pie bond between N and O count as there are no pie bond between carbon and nitrogen
Yes it will be. As pi electron are present
Yes mam, both compound UV active because of unsaturation present on both compound
Good
@@chemistrybydr.anjalissaxena mam, NMR spectroscopy and mass spectrometry left
Also fluorescence
@@harishaliahmad6667 will try
@@chemistrybydr.anjalissaxena thank you mam
Super mam
Glad you like it
Mam apne Atomic Absorption, Atomic Emission spectroscopy, Jablonski diagram nahi padhaya hai kya
No will cover soon
@@chemistrybydr.anjalissaxena Mam please thoda jaldi kardo 17 ko mid sem hai
Mam. Energy is directly proportional to wavelength?
Both are active because both molecules include 400nm to 800nm uv visible
Thanx for understanding to uv visible
Yes, you are right
In Ch3COOH
Four types of transition possible
S --> s*
π---> π*
n---> s"
n---> π*
But b/c of high energy only sigma to sigma star aur n---> pi star not possible in uv /visible region hence these are uv inactive while remaining both are uv active ...
Overall compound will be considered as uv active....
CH3No2 same as above
Yes
Both are uv active compound 1st compund are π-π* unsaturated transition And n-π* transition with unsaturated and no bonding electron
Yes
how we know they are range of 200-400 nm range ?
I need to see the absorbance of dichloromethane by carbon by using uv visible spectrophotometer. I had already run a pure dichloromethane to full range of uv visible spectrum I e,190 nm-1100nm to see at which wavelength its peak is seen .
And,its highest and clear peak have been seen in 208nm. But in literature the range of DCM for uv visible spectrum is 233nm, and highest 274 nm. Somewhere it is written the range is between 200-300nm. And according to 'OECD guidelines for testing of samples' by uv visible spectrum, it's range is 235 nm for dichloromethane. Now I am confused what wavelength range I must fix for my samples. Please guide me.
Great research. You can repeat ur experiment 2/3 time. Or you can give 200-220 nm.
1.CH3COOH
Unsaturated +non-bonding e.
n--pie*transition.....UV active.
2.CH3NO2
Same as above.
Yes
@@chemistrybydr.anjalissaxena thanku mam it helped me a lot 😊
@@mahwishiftkhar9348 most welcome
Excellent explanation of such boring and complex topic
Thx u. like subscribe and share plz
Mam😊 can you please reffer a book for this course for reading because your videos are very helpful ❤😊but i am a reader.
Not a single one. like subscribe and share plz.
@@chemistrybydr.anjalissaxenaok 👍 Mam, you may name two three major books
Mam CGSET (chemistry) ka class nhi leti hai
Substitution reaction and nucleophilic and electrophilic sn1 sn2 reaction vala video please create ..
Will try
Mam both are UV active compounds as both of them have unsaturation as well as presence of heteroatoms
👍
both the compound are active because pi electrones as well as non bonding e- present
💯
Both are UV active compound. Tq
Yes, correct