Composite Wall with Series/Parallel Configuration

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  • เผยแพร่เมื่อ 5 ต.ค. 2017
  • Organized by textbook: learncheme.com/ Shows how to write a thermal circuit for a composite wall with two different materials in series and parallel. Made by faculty at the University of Colorado Boulder Department of Chemical and Biological Engineering.
    Check out our Heat Transfer playlist: • Heat Transfer
    Check out our website for interactive heat transfer simulations: www.learncheme.com/simulations...

ความคิดเห็น • 22

  • @raptergamingyt5401
    @raptergamingyt5401 3 ปีที่แล้ว

    Nice presentation.
    Which is the university?

  • @currysteph1563
    @currysteph1563 ปีที่แล้ว

    What if using thermal resistivity?

  • @luisc1402
    @luisc1402 5 ปีที่แล้ว +1

    One thing that puzzles me about this method. The temperature of the A-B interface is not the same as the temperature of the A-C interface, is it? same for on the D side... How come that the circuit analysis works like this? What is the 'T' at the nodes that I am mentioning?

    • @theadel8591
      @theadel8591 3 ปีที่แล้ว

      The instructor should have mentioned the assumptions utilized in this particular example. One of them being that all surfaces normal to the x-direction are isothermal.

  • @adkm222
    @adkm222 3 ปีที่แล้ว

    thank you

  • @IillyMacdovers-cc6ob
    @IillyMacdovers-cc6ob 10 หลายเดือนก่อน

    Tendencies of alternate molecules. Greg Holme's in delta A.

  • @arkadyutichakraborty9935
    @arkadyutichakraborty9935 3 ปีที่แล้ว

    What will be the temperature profile for this case?

    • @pranavkankal5604
      @pranavkankal5604 3 ปีที่แล้ว

      Can you tell me what will be temperature profile please 🙏🏻

  • @samhithach3245
    @samhithach3245 6 ปีที่แล้ว +3

    In r (bc) the calculation is wrong pls check

  • @peterburjorjee3352
    @peterburjorjee3352 ปีที่แล้ว

    Thanks!

  • @asheshshrestha
    @asheshshrestha 6 ปีที่แล้ว +4

    @5:32 shouldn't the parallel resistance be R(b)'+R(c)' = [R(b)*R(c)]/[R(a)+R(b)]

  • @trapmaster2222
    @trapmaster2222 4 ปีที่แล้ว

    Please all note that temperatures in the problem are in ºC while in the solution are in ºK ...

    • @AbhaySingh-wi4qu
      @AbhaySingh-wi4qu 4 ปีที่แล้ว +2

      Doesn't matter we are concerned with temperature difference so the value will remain same

    • @isai1331
      @isai1331 4 ปีที่แล้ว

      @@AbhaySingh-wi4qu True, the conversion only mater if you are going to divide or multiply temperature units

    • @AbhaySingh-wi4qu
      @AbhaySingh-wi4qu 4 ปีที่แล้ว

      @@isai1331 Exactly

  • @AK-mc7gf
    @AK-mc7gf 3 ปีที่แล้ว +2

    this solution is wrong. Parallel resistance is calculated incorrect.

  • @nylepentik2696
    @nylepentik2696 3 ปีที่แล้ว +3

    Once again errors made in this video:
    When summing up the total resistances, Rt = Ra + 1/ Rb + 1/Rc + Rd
    This will give Rt= 32.79 K/W and hence, Q = 1.68W

    • @franzandrewtiangco4809
      @franzandrewtiangco4809 2 ปีที่แล้ว +1

      This is correct. The formula goes 1/Rbc = 1/Rb + 1/Rc, thus the -1 power in order to convert it back to Rbc.

  • @soyboy1944
    @soyboy1944 5 ปีที่แล้ว +1

    B area is 0,4x0,5!! not 0,4, 0,4 is the length of one of its sides

    • @remintwali2517
      @remintwali2517 5 ปีที่แล้ว +5

      The area is 0.4m2 (0.4m * 1m = 0.4m2)

    • @ashviinalbano5121
      @ashviinalbano5121 4 ปีที่แล้ว +4

      If you watch the video again, she explains that we should take the cross sectional area that the heat flux goes through.

    • @muhammadm241
      @muhammadm241 3 ปีที่แล้ว

      @soy boy
      you're such a soy boy for thinking that