Resolution of Vectors in 2D | Introduction

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Any videos on resultant of complanar forces

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Any videos on resultant of complanar forces

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Any videos on resultant of complanar forces

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[@boatengmaxwell5403]

Indeed, you are really a genius Sir. Thank you for broadening my understanding on vector resolution

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[@InnocentAnele-x9o]

WOW.. THIS VIDEO IS TOP NOCH
LIKE.. IVE ALWAYS BEEN STUCK WITH MEMORIZING THE FORMULAS FOR RESOLUTION BUT NOW I DONT NEED TO.
THANKS SIR

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Thank you so much sir😊 I have a much better understanding of this now

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[@JulietThomas-km5ch]

U taught me how to resolve, thank you so much for the clear explanations

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This is the link to the class on Friction
th-cam.com/video/-QLtOJn3drM/w-d-xo.htmlsi=B41ktOKKyZLGeJu7

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[@spylucid]

Thank you for the video sir but i have an inquiry..at 26:58 why dont we put -120cos145 since all the other angles are anticlockwise 😢

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[@PacesetterEmmanuel]

Thank you sir but please when tita is inclined to the vertical can you substract tita from 90 degrees in other to make it inclined to the horizontal

[@jonahemmanuelofficial]

Yes, that works too

[@fareedaharogbola]

Thanks but I have a question. You said the negative sign in the direction of the resultant is showing the negativity of x (-85.3 degrees) but the lower part of the Cartesian plane also has negative x so why is direction only calculated in the north west direction and not calculated in the south west direction. I hope the question is clear.

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Please highlight the exact place in this video

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How do you know when the direction is negative

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Beams cantilevered and so on

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I don't understand,l thought the first example suppose to use tita 60, I will be so happy to receive a reply from you soon

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How to know different btw cos and tan

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Cos is adjacent/hypothenuse
tan is opposite/adjacent

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Bro wat is component of vectors

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