Carbon-13 NMR Spectroscopy
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- เผยแพร่เมื่อ 4 ก.ค. 2024
- This organic chemistry video tutorial provides a basic introduction into carbon-13 NMR spectroscopy. It covers broadband decoupled C-NMR where all signals appear as singlets as well as proton-coupled C-13 NMR spectroscopy where the signals appear as doublets, triplets, and quartets based on the N+1 rule splitting pattern of the hydrogen atoms that are directly attached to the carbon atoms. It also discusses DEPT C-13 NMR spectroscopy which is useful for identify C, CH, CH2, and CH3 carbons. This video explains how to assign the chemical shifts to different carbons given the C-13 NMR spectrum as well as proposing a structure given the molecule and using factors such as IHD and the number of signals present in the spectrum. Finally, this video discusses the different chemical shifts of functional groups such as alkyl groups like methyl, methylene, and methine groups as well as halogens, amines, alkenes, alkynes, ethers, alcohols, benzene rings, aldehydes, ketones, esters, and carboxylic acids.
Alcohol Reactions - HBr, PBr3, & SOCl2:
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Wow, this video is incredibly informative and detailed. The explanation of carbon-13 NMR spectroscopy is clear and concise, covering everything from the basics of broadband decoupled C-NMR to DEPT C-13 NMR spectroscopy. The examples provided, such as 2-butanol and 2-methylbutane, really help to illustrate how to assign chemical shifts to different carbons given the C-13 NMR spectrum. I especially appreciated the discussion on how to propose a structure given the molecule and using factors such as IHD and the number of signals present in the spectrum. The video also does a great job of explaining the different chemical shifts of functional groups, including alkyl groups, halogens, amines, alkenes, alkynes, ethers, alcohols, benzene rings, aldehydes, ketones, esters, and carboxylic acids. The score system for ranking the chemical shifts of sp3 carbon atoms is also very useful. Overall, this video is a must-watch for anyone studying organic chemistry
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Very helpful and made the concepts very clear and easy to understand. I would like to note, however, that the integration (peak height) of the C13 peaks is the result of the number of protons on the carbon not the number of equivalent carbons.
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Very helpful video! Thank you so much. I have a question. Do we get another peak If the adjacent nitrogen protonates for a certain percentage of the molecule (e.g. 10mol% of CH3-CH2-CH2-CH2-NH2 is protonated and form CH3-CH2-CH2-CH2-NH3+; do we see two separate peaks for the adjacent C of the N for these two molecules).
First of all, thank you for the perfect explanation, simple and clean. But i want to make a question: why does ketones have more cs than , for example, carboxylic acid? I mean : does not the electronegativity of Oxygen "take off" the electrons from the Carbon atom, reducing his screen for the external magnetic field, causing an increase of chemical shift ? I do not understand that. Thank you an keep it up !
Bc carboxylic acids have resonance
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For example, #6, wasn't the carbon b a tertiary carbon with a score value of 3 due to 3 primaries around?
i am wondering the same
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So how do you explain why at 10:48min why does a secondary carbon has a higher chemical shift than tertiary carbon if they both have a score of 4?
Well i'm about 5 months late but maybe this will help someone else... The carbon that has the score of 4 but is neighboring a tertiary carbon will end up having a higher "score". The other carbon with a score of 4 has a neighboring secondary carbon giving it a lower score than the other one. think of the neighboring carbon(s) as a tie breaker in these situations.
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Any help please...what's the number of carbons does cyclohezone has on 13 cnmr
Can someone explain the 13C of 2,2,4trimethyl-1,3pentandiol.cuz this system wont work for that.and there are similar ch3 groups having different peaks.
very useful : )
one confusion: when you talking about the triple bond group example, I think the carbon with triple bond should be 3° not secondary carbon. Please check~
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A carbon with a triple bond cannot be bound to three R-groups and cannot therefore be a tertiary carbon, since a carbon atom cannot form five bonds.
I was wondering the same thing! Cb should have a score of 5 and Cc a score of 7.
Why does 13C have such a wider range as compared to 1H NMR?
Can you do some problems that combine IR, H NMR, and C NMR? e.g.
formula C5H8Cl2 what is the structure?
IR (cm-1): 2950
1H NMR (δ): 1.4 (4H, triplet), 1.2 (4H, triplet)
13C NMR (ppm): 62 (singlet), 26 (triplet), 23 (triplet)
i want to cry :( :(
@TheOrganicChemistryTutor At 29:25 Isnt carbon A a tertiary carbon, making the score of carbon B 4 which would give the higher chemical shift anyways?
im confused. how come around 1:22:00 when he talks about H NMR he's not using the adjacent carbon's hydrogens to determine the split pattern?
Because the example wasn't HNMR. He was saying if it was then you would look at the adjacent hydrogen atoms.
This is a transcript from my textbook about 13C NMR:
"First, no splitting is observed between neighboring carbon atoms because of the low abundance of 13C. The likelihood of a compound having two neighboring 13C atoms is quite small, so 13C-13C splitting is not observed. In contrast, 13C-1H splitting does occur, and it creates significant problems. The signal of each 13C atom nucleus is split not only by the protons directly connected to it (separated by only one sigma bond) but also by the protons that are two or three sigma bonds removed. This leads to very complex splitting patterns, and signals overlap to produce an unreadable spectrum. To solve the problem, all 13C-1H splitting is suppressed with a technique called broadband decoupling, which uses two rf transmitters. The first transmitter provides brief pulses in the range of frequencies that cause 13C nuclei to resonate, while the second transmitter continuously irradiates the sample with the range of frequencies that cause all 1H nuclei to resonate. This second rf source effectively decouples the 1H nuclei from the 13C nuclei, causing all of the 13C signals to collapse to singlets.
The advantage of broadband decoupling comes at the expense of useful information that would otherwise be obtained from spin-spin coupling. A technique called off-resonance decoupling allows us to retrieve some of this information. With this technique, only the one-bond couplings are observed, so CH3 groups appear as quartets, CH2 groups appear as triplets, CH groups appear as doublets, and quaternary carbon atoms appear as singlets. Nonetheless, off-resonance decoupling is rarely used because it often produces overlapping peaks that are difficult to interpret. "
why alkyne have low 13C valu than alkene??
Sir can you make video on 2 d nmr spectroscopy and please explain tocsy cosy hmbc hsqc spectra ? I will really appreciate it.
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On voit tjrs un pic à 78 dans RMN c13 cela signifie quoi ? Et des fois se cache ??
Why do I even show up to class
same