Nop bro, It depends, as an example you can put an object over the bowl and pressure will increase... But if you don't put anything over it, assume that the external pressure is the atmospheric pressure.
No, you could do an irreversible compression or expansion with any external pressure you like. I only used 1 atm to make it as simple as possible. This is a pretty common situation for real-world expansions as well, but conditions may be different.
Sir plz reply i have a question related to pv work unable to find the ans with explanation ,plz give me ur mail i will send u the question ,if u have time then plz🙏
I prefer answering content questions via video comments, where (hopefully) other students can benefit from the answers. But you can find my contact info on the channel's "About" page.
Why is the external and internal pressure equal whenever you do it slowly? Wouldn't the internal pressure be greater than 1 all the way till the end?
Oh it's pressure not from the Pext but from you holding it there and slowly allowing it to expand huh
Can we always assume that the external pressure is 1 atm for an irreversible process
Nop bro, It depends, as an example you can put an object over the bowl and pressure will increase... But if you don't put anything over it, assume that the external pressure is the atmospheric pressure.
PD. Sorry by my english... lol
No, you could do an irreversible compression or expansion with any external pressure you like. I only used 1 atm to make it as simple as possible. This is a pretty common situation for real-world expansions as well, but conditions may be different.
Studying chemistry is all just a gas anyway 👍
@@PunmasterSTP Glad you have such an expansive attitude on the subject
@@PhysicalChemistry It can be fun to be expansive, but eventually it leads to more work...
Sir plz reply i have a question related to pv work unable to find the ans with explanation ,plz give me ur mail i will send u the question ,if u have time then plz🙏
I prefer answering content questions via video comments, where (hopefully) other students can benefit from the answers. But you can find my contact info on the channel's "About" page.
@@PhysicalChemistry thanks sir i have send u through mail, plz check once
Out of curiosity, what was your question, and did you find an answer?