Voltage Follower - Operational Amplifier | Basic Circuits | Electronics Tutorials

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  • เผยแพร่เมื่อ 29 พ.ค. 2024
  • Operational amplifiers, or op-amps, have a variety of popular configurations but one of the most often used is as a voltage follower. In this video, Josh goes over the concept behind a voltage follower, where and why you'd need it, and does a practical example showing how it affects the output voltage of a high-impedance source.
    Parts of the video:
    0:00 Introduction
    0:36 What's the point of a voltage follower?
    0:54 High- versus low-impedance outputs
    3:47 Simulating a high-impedance output
    4:38 Setting up the op-amp voltage follower
    6:01 Trade-offs
    8:21 The toast will never pop up
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ความคิดเห็น • 45

  • @Jnglfvr
    @Jnglfvr ปีที่แล้ว +19

    At 5:28 you have it backwards. The output should provide negative feedback into the inverting terminal and the 47K ohm resistor should be fed into the non-inverting terminal. The circuit will not work the way you describe. It did work, however, because you mis-identified the inverting and non-inverting terminals and actually connected them opposite to your narrative. Take a look at the circuit diagram at 3:28.

    • @CircuitBread
      @CircuitBread  ปีที่แล้ว +19

      Dang. You are right, I misidentified those when describing the setup at 5:28. The circuit was setup correctly, it was just my description. I'll pin this comment so others can see if they're confused. Thanks for catching that!

    • @JonDeth
      @JonDeth 6 หลายเดือนก่อน +1

      I had minor confusion about the inverting terminal last night because what I was looking at vs what I heard lol. I watched it again before bed, revisited the video this afternoon, and your comment just helped me out.
      ATM, my primary area of interest is designing and building musical equipment, and there will always be a need for some devices to be a low impedance output.

    • @zainabashai7546
      @zainabashai7546 2 หลายเดือนก่อน

      @@CircuitBread Why can the 47k not be connected to non-inverting terminal of op amp? Why is it necessary to connect feedback to inverting terminal?

  • @brianm1916
    @brianm1916 2 ปีที่แล้ว +18

    The WHY explanation was exactly what I needed! Please keep telling us the why in all of your videos.

  • @ovi_4
    @ovi_4 หลายเดือนก่อน +1

    Wow....what a great resolve. I was trying to understand someone's circuit. He made a little circuit using a dual op-amp (LM358) to amplify a small signal needed for an analog movement in an old radio. By analog movement I mean the signal strength indicator (the meter. I believe it must be a baby size micro-amp-meter. Possibly 50-to-150uAmps). So he used the 2 op-amps in a series configuration but didn't know that the very first op-am was configured as a voltage follower (so the existing signal could be amplified without unbalancing the signal itself. Wow..this is what I needed to snow. I have subscribed right away!. Thank you. PS: I'm just beginning to understand the world of OP-amps. They are so versatile is unreal. I hope to master it one day (fingers crossed) :)))

  • @Mischiefcity2013
    @Mischiefcity2013 ปีที่แล้ว +1

    Best explanation I've found by far! Thanks, seriously appreciate it.

  • @flaviodanca2057
    @flaviodanca2057 ปีที่แล้ว

    Few words but a lot of meaning. Nice job.

  • @bothwellchingombe4746
    @bothwellchingombe4746 ปีที่แล้ว +3

    I’m glad I found this channel.
    Makes understanding electronics much easier.
    Please keep up the good works my good Sir.

    • @CircuitBread
      @CircuitBread  ปีที่แล้ว

      Thank you for the feedback!

  • @colyjiang412
    @colyjiang412 2 ปีที่แล้ว +3

    Thanks for these videos, they really have improved my knowledge of circuits. You also consistently answer questions in the comments, making sure your viewers understand the concepts, which is something I haven't seen other youtubers do. Keep up with the great work.

    • @CircuitBread
      @CircuitBread  2 ปีที่แล้ว

      Thanks for the feedback! We do try and answer as much as we can in the comments but I know I miss a lot. I think our Discord channel is starting to pick up more as well, with some good answers and insights there as well.

  • @maovichet1683
    @maovichet1683 2 ปีที่แล้ว +1

    Great i like electronic so much,thank for your sharing.

  • @sunrayseducation
    @sunrayseducation ปีที่แล้ว +1

    Thank You Sir, for this content.

  • @zetaconvex1987
    @zetaconvex1987 2 ปีที่แล้ว +3

    Thanks Josh. It's worth pointing out that the output draws current from the power supply rather than the input source itself. So there's no magic involved.
    Something that I struggle with - and something that is rarely mentioned - is what to do about powering the opamp. This is to do with how close the input voltage can get to the power rails. It's a subject that tutorials skimp over and taken as a given, but can leave nebies like me puzzled as to why I'm not getting the output I expect.

    • @CircuitBread
      @CircuitBread  2 ปีที่แล้ว +1

      Good feedback, thank you! You are totally right - all the power from the output comes from the power supply.
      I did finish shooting all of the op-amps videos we have planned and while mentioning the rail-to-rail output, I didn't mention the input voltage versus power rails in them either...

  • @andymouse
    @andymouse 2 ปีที่แล้ว +1

    Great video....cheers.

  • @edgeeffect
    @edgeeffect 4 หลายเดือนก่อน

    I've just this minute, finally got my head around what high/low impedance really means... Great stuff... thanks.
    Be interesting to see what it'd look like to build a voltage follower using BJTs or FETs.

    • @CircuitBread
      @CircuitBread  4 หลายเดือนก่อน +1

      I definitely remember when that clicked for me as well. A memorable moment!

  • @zackwatson755
    @zackwatson755 ปีที่แล้ว +1

    Helpful, thank you

  • @aryanpandey188
    @aryanpandey188 2 หลายเดือนก่อน +1

    best explanation

  • @wysskey1
    @wysskey1 8 หลายเดือนก่อน +1

    I use this circuit often to feed remote sensors . If you stick a blocking diode into the supply voltage of the op amp you get non destructive short circuit protection as well as reverse battery protection without damage to the op-amp. ?¿

  • @JonDeth
    @JonDeth 6 หลายเดือนก่อน +1

    I'm assuming that op amp has sentimental value considering when it was purchased. My first serious dual op amp circuit turned out to become a high gain distortion pedal with soft clipping germanium diodes, and soon I will retire it to showcase more like a trophy.
    When I "designed" it, I really had no scientific understanding and relied on tutorial basics of setting gain, RC filters and diodes on the feedback path to produce soft clipping.

  • @lad7534
    @lad7534 2 ปีที่แล้ว +1

    I am binge watching this video's, they are awesome, better than my classes

    • @CircuitBread
      @CircuitBread  2 ปีที่แล้ว

      Awesome! I'm so glad they've been helpful!

  • @Electronzap
    @Electronzap 9 หลายเดือนก่อน

    Good info.

  • @jogreeen
    @jogreeen 2 ปีที่แล้ว +1

    Thanks

  • @adrianzayas4456
    @adrianzayas4456 ปีที่แล้ว +1

    Hi, thank you for your clarifications. I have a question about the impedance of the voltage follower. If the Vi=Vo in this type of op-amp, would you say that the impedance of the op-amp is 0 or 1? If there is no Rf would you consider (Rf/Ri)= 0 or 1.

    • @CircuitBread
      @CircuitBread  ปีที่แล้ว

      Hi Adrian, for an ideal op-amp, you would consider the output impedance zero and the input impedance (to the non-inverting input) to be infinity. I'm not sure if I would look at it in the context of Rf/Ri, that may be unnecessarily complicating things, as your input isn't connected to the same leg as your output (as it is in an inverting or non-inverting amplifier configuration).

  • @jimedgar6789
    @jimedgar6789 11 หลายเดือนก่อน

    SUPER helpful. My "current" project is using a LiPo to power an ATTiny as an LED flasher in a remote area, and I need to know how often I need to swap the LiPo out. mAh math aside, cause who really knows in real life. So I am going to set up an MCU to read a pulse from the Tiny every so often, but I don't want that current to participate so I THINK with a the near infinite impedance of the opamp input, I could get a timeline of the battery life. Meaning the MCU and the opamp are their own circuit. Hmmm?

  • @DasIllu
    @DasIllu 2 ปีที่แล้ว +1

    I always had an issue with the labeling and the subsequent misdirection by calling the inputs positive and negative.
    I made it an effort to get that out of my head as soon as i started to understand OpAmps a bit better.
    Inverting- and Non-Inverting input is a better description, imho. It might seem "even more techno babble" to the uninitiated, but i think it helps in the long run.
    Once you start seeing the inputs like this and not "so this is where positive voltage goes and this is where negative voltage goes", you can start using the opamps to manipulate signals to your own liking. That is why i see the labeling as a pitfall for people just starting to learn electronics.

    • @CircuitBread
      @CircuitBread  2 ปีที่แล้ว +2

      Yeah, while doing these I was debating on that terminology. All of the opamp videos have been shot now and I use the terms inverting and non-inverting more and more as they progress for exactly those reasons. As you get to know them better, it makes more sense to say inverting and non-inverting. Hopefully the transition eases people into it rather than causing a confusing stumbling block.

    • @andymouse
      @andymouse 2 ปีที่แล้ว

      Good advice...cheers.

  • @andylaurie326
    @andylaurie326 2 ปีที่แล้ว +2

    a buffer also isolates that tiny input from the nasty load

  • @clusterbx
    @clusterbx 2 ปีที่แล้ว

    Thanks for the video. Helps refreshed my memory on the use of OP-AMP learnt during my schools days. May i ask, if i want to transmit 6.4Vdc across a 100m 18AWG cable, how many OP-AMP do i have to insert along the 100m length? Will every 10m suffice?

    • @CircuitBread
      @CircuitBread  2 ปีที่แล้ว

      That's both an interesting question in that I'm curious what the application is and that I can't answer it with that information. The key missing info here is the current you anticipate pushing through the wire, as that will affect your voltage drop. If there is no current, then it's theoretically possible a single op-amp will work, as you won't get any voltage drop and op-amps can output a non-negligible amount of current. My understanding (a quick Google search) is that non-PoE ethernet is only around 1-2 volts and that can go about 100 meters but it doesn't move any significant current.

    • @clusterbx
      @clusterbx ปีที่แล้ว

      @@CircuitBread Hi. I am trying to transmit 6Vdc over 200m to operate a small servo. The 200m cable is 12ohms and the servo has a rated stall current of 2A. I actually did that and the servo was not really moving. It's like there's not enough power.

    • @CircuitBread
      @CircuitBread  ปีที่แล้ว

      @@clusterbx Sorry about this extremely delayed response, TH-cam doesn't notify me about follow-up questions. I think a little Ohm's Law here will clear things up. You have 12 ohms of cable and are running upwards of 2A. With V=IR, and I=2 and R = 12, you'll need 24V to "push" that much current just through the wire, let alone to run the servo. If your op-amps are running off of that same power supply, they're going to run into the same problem. They don't magically create the current, they need a power supply as well. If they're hooked into another source of power, it should be doable, because you won't actually be running much power through that 200m wire. But I imagine that there isn't anything else (or else you wouldn't be running a 200m cable) so I don't think this will work with that large of a load.

  • @Dc_tech386
    @Dc_tech386 11 หลายเดือนก่อน

    I use the lm393comparator on my power supply I design for 1000watt the issues I have is the voltage drop still and I don’t understand way is that the voltage not holding even though the duty cycle is adjusted from the comparator am only getting current not voltage stabilized the voltage is 55 input 20amp and 14.80 volt out put when I add a low the voltage drop to 14 volt not 14 .80 and I see the tl494 only stabilized the volt in negative drive for p channel the voltage don’t drop but in positive pulse the n channel design the comparator have to use but voltage drops on the positive side can use explain why is this and should I not use n channel for

  • @zainabashai7546
    @zainabashai7546 2 หลายเดือนก่อน

    Can you provide a link to the op amp used? I want to buy it. Is it any op amp?

    • @CircuitBread
      @CircuitBread  2 หลายเดือนก่อน

      There are many differences with op-amps even though, with these examples, we're not pushing them hard enough to make a big difference in performance but there will still be changes in how they're powered and their pin-outs. We used the LM2903P from Texas Instruments for these examples if you want to ensure that everything works as it does in the examples: www.digikey.com/en/products/detail/texas-instruments/LM2903P/372786

  • @KA9DSL
    @KA9DSL ปีที่แล้ว

    Simple, a voltage to current convertor.

  • @Cm0nd00d
    @Cm0nd00d 2 ปีที่แล้ว

    woah! you changed your shirt!

    • @CircuitBread
      @CircuitBread  2 ปีที่แล้ว

      😂 Fashion is not my thing...