Like noble ,padmashree,padmabhusha etc..if there was any award for the best of bests teacher in the world .... then u would be the only one deserving it ..
Sir i think ye question aapne galat solve kia hai. Question me assumption wrong le rkha h aapne. Jo line AB hai uski other end B ki baat ki ja rhi hai. To b' & b , ke wajae b1' and b1 , given hai , i mean true length ke end die hue hai . plz check that out😀 But that aside your teaching is just awesome sir♥️🫡🫡. We students really appreciate that , from the depth of our heart.
For important questions please refer the previous 5-6 years question paper from summer 2013 to summer 2019 all the papers of summer and winter will help you to get all the important questions.
How to solve this👇 qn Draw the projection of straight line PQ 100 mm long inclined at 45° to HP and 30° to VP. The end P is in HP and the end Q is in VP. Find the shortest distance between the straight line PQ and the line of intersection of plane of projection.
The distance between the projections of two points A and B is 70mm. A is 10mm above HP and 15mm in front of VP. B is 50mm above HP and 40mm in front of VP. Find the shortest distance between A and B by rotating line method. Find true inclinations of AB with VP& HP
The line AB has its end A, 15 mm above H.P. and 10 mm in front of V.P. The end B is 60 mm above H.P. The distance between the end projectors is 50 mm. The plan of the line is inclined at 25° to X-Y line. ? the plan of the line is inclined at 25 means it is angle of tv or fv or true length ??
Isometric view of an object. Draw the following View By the first angle projection method 1front view (looking from P arrow) 2side view (looking from Q arrow) samajh Nahin a raha hai
Sir how you decided ? And how we will decide that b` and b are the end points of view or true length? Because we can also say that these points given in the question are the end points of true lenght??
A line RS has its end R 20 mm above HP and 25 mm in front of VP. The other end S is 45 mm above HP and 40 mm in front of VP. The distance between the end projectors is 60 mm. Draw its projections, also find the true length and true inclinations of the line with HP and VP and mark the traces.
I already uploaded such types of videos where distance between end projectors are not given. Please visit the PLAYLIST SECTION on my TH-cam channel. Please follow Q.NO.2,3,4,9.
Agar distance between end projector nahi diya hai to kuch aur diya hoga.....usise solve hoga. Waise koi bhi problem me 5 data diya hota hai.....Aap remaining problems study karo jo humaare channel pe milenge.....aapke douts clear hojaege.
line AB, 65 mm long has its end A 20 mm above the H.P. and 25 mm in front of the V.P. The end B is 40 mm above the H.P. and 65 mm in front of the V.P Draw the projections of AB and show its inclinations with the H.P. and the V.P
Please watch the video on Projection of Straight line Solved Problem 2 & 3. ....Un videos me aapke question ka answer mil jayenga. Aur koi dout hai to jarur puchna ??
top view of a 75 mm long PQ measures 50mm the end P is 15mm above the H.P 50 mm. inftont of the VP .Other ends Q is 20 mm infront of vp above the H.P .draw its projections and its true angle of inclination with the referance plane? Sir can you help me this question. Please
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@@TIKLESACADEMY sir i do this in free cad i have understood everything but how true length will be obtained in free cad i can't do..pls help me sir..
Sir paise hm college ko dete hai but free main aap padhate ho itna accha thankyou so much sir 😢😢😢😢😢😢
Really you are the best teacher in the world ❤️ 💕
Tommorow is the first paper of ed
Best of luck for your Exam 👍
True Length:-88mm
Theta:-27°
Phi:-34°
thank you i got same with error +-1,
Answer is Same here
@@ishinde4985 yup! same
Same but just got phi=33.5°
Right
Sir you are a angel for us.
You'r teaching way is superb, extemmelly easy way to understanding .
Thankyou so much .
Like noble ,padmashree,padmabhusha etc..if there was any award for the best of bests teacher in the world .... then u would be the only one deserving it ..
I can't explain you how much you have helped me thank you soooo much Sir .
Same feeling bro
Best teacher, for every subjects, I really appreciate your work sir and thank you very much for helping us, #we will support you always
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Sir gazab k teacher ho aap , effortless tareka se difficult question ko bhi aasan kar dete ho 😊😊
Sir tomorrow is my exam and I have gained confidence that i will give a killer performance
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Sir you are the best
My Answer :
True Length = 88 mm
Inclination with HP (Theta) = 27 degree
Inclination with VP (Fi) = 35 degree
Ha bhai same aya , thnq 👍🏻
Can u tell me how you're finding that??
Simplified teaching👍👌thanks Sir
Sir you are amazing ❤ Love from Nepal❤
Thank you sir
Your method is brilliant.
I really THANK TO SIR AND GOT 99
Congratulations on ur success
Good way of teaching SIR THANKS🙏🙏🙏
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Best lecture👍🙏
Sir makes it look very easy, and it's starting to get easy.
Jordar all video sir me apna bdha video like krel se
Sir i think ye question aapne galat solve kia hai. Question me assumption wrong le rkha h aapne.
Jo line AB hai uski other end B ki baat ki ja rhi hai.
To b' & b , ke wajae b1' and b1 , given hai ,
i mean true length ke end die hue hai .
plz check that out😀
But that aside your teaching is just awesome sir♥️🫡🫡.
We students really appreciate that , from the depth of our heart.
Best engineering graphics lessons i have ever attended is this
Sir it's really good teaching 😊
Sir you might not get more subscribers but you won millions of hearts
Thank you so much for your informative videos 😊👍
Thank u sir ❤
❤❤❤❤❤ love you sir you are best teacher
saviour for all engineering students 😊
Sir apka koi tod nahi h bahut accha padate ho aap
You are amazing sir
Sir aap bohot achchaa padate ho...!!!!
VERY GOOD EXPLANATION
Thanks for watching
Sir hmara 13 tarik ko paper hai Ed ka mai first semester ka student hu sir aap muje most important questions bta digiye Ed ke
For important questions please refer the previous 5-6 years question paper from summer 2013 to summer 2019 all the papers of summer and winter will help you to get all the important questions.
@@TIKLESACADEMY thank sir thank you very much
Dhanyawad Guruji 🙏🙏🙏🙏
This lecture helps a lot sir
thank you sirrrrrrrrrrrrrrrrr thanks a lot
Thank you so much sir😍❣️❣️🥰👍👍👍👍👍👍👍 big fan sir😍❣️🥰
Thank You So Much Sir 🙏🙏
Sir they didn't mentioned that the given lengths is of FV and TV from the x-y line .They just said that "line AB" but u took it as FV and TV
Easiest problem till now.
❤❤❤❤❤❤❤❤❤❤. Thankyou so much sir 😌😊
You are dhoni for me sir
thank you sir for your valuable vedios
How to solve this👇 qn
Draw the projection of straight line PQ 100 mm long inclined at 45° to HP and 30° to VP. The end P is in HP and the end Q is in VP. Find the shortest distance between the straight line PQ and the line of intersection of plane of projection.
Best teacher ,It helping a lot ❤️💯💯💯🤞
Best teacher ❤
Very very nice teaching sir😇
I Appreciate your work thank you
Sir aapne FV and TV bataya lekin hum usi 50 and 65 vale lines ko true lenth bhi bol sakte the kya
wow so amazing idea
Thanks Sir
Thank you, sir
Sir you are just awesome
Thank you so much sir ❤️ u r really awesome 😎
Jai Hind sir
You are God♥️
World Febrate teacher 🙏🙏🙏
Thetha and fy har kisse student ka same hoga kya ya phir thoda difference aa sakta hai
Thank you soooooo much sir 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
THANKS you so much sir 🙏🙏🙏
Sir do we also need to write the construction of this
mera 10 baje se exam h subha 4 baje ap mil gaye agar ap na mile hote to mei fail ho jata thanks sir !!!!!!!!!!!!!!!!!!!!!!!!
Thank you so much sir ❤️🙏
Very nice sir
Sir, please make a separate videos on autocad also
The distance between the projections of two points A and B is 70mm. A is 10mm above HP and 15mm in front of VP. B is 50mm above HP and 40mm in front of VP. Find the shortest distance between A and B by rotating line method. Find true inclinations of AB with VP& HP
The line AB has its end A, 15 mm above H.P. and 10 mm in front of V.P.
The end B is 60 mm above H.P. The distance between the end projectors
is 50 mm. The plan of the line is inclined at 25° to X-Y line. ? the plan of the line is inclined at 25 means it is angle of tv or fv or true length ??
thank you sir❤️
I’ve paid millions for my college but your free teaching is way better than my college teacher💪🏼
😍🤩🤩🤩😘😘☺😚
Isometric view of an object. Draw
the following View By the first angle projection method
1front view (looking from P arrow)
2side view (looking from Q arrow)
samajh Nahin a raha hai
Sir inki construction bhi likhni padegi exam mea
Sir how you decided ? And how we will decide that b` and b are the end points of view or true length? Because we can also say that these points given in the question are the end points of true lenght??
Tikle academy is an emotion♥️🥰
A line RS has its end R 20 mm above HP and 25 mm in front of VP. The other end S is 45 mm above HP and 40 mm in front of VP. The distance between the end projectors is 60 mm. Draw its projections, also find the true length and true inclinations of the line with HP and VP and mark the traces.
sir ek doubt hai if the distance between end projectors is not given then how we solve this question?
I already uploaded such types of videos where distance between end projectors are not given. Please visit the PLAYLIST SECTION on my TH-cam channel. Please follow Q.NO.2,3,4,9.
@@TIKLESACADEMY OK sir
Other end B ke bajaye mid point M hua to kya kre?
Sir how that theta and pi value will be evaluated?
Measure them by using Protector
sir projector mai distance na diya ho to kaise kare es question mai?
Agar distance between end projector nahi diya hai to kuch aur diya hoga.....usise solve hoga.
Waise koi bhi problem me 5 data diya hota hai.....Aap remaining problems study karo jo humaare channel pe milenge.....aapke douts clear hojaege.
line AB, 65 mm long has its end A 20 mm above the H.P. and 25 mm in front of the V.P. The end B is 40 mm above the H.P. and 65 mm in front of the V.P Draw the projections of AB
and show its inclinations with the H.P. and the V.P
If end projector do not give if TL then how solve tell me sir tommarow my exam
Please watch the video on Projection of Straight line Solved Problem 2 & 3.
....Un videos me aapke question ka answer mil jayenga.
Aur koi dout hai to jarur puchna ??
here in quesn line AB why we should not consider that it is true line instead of FV
Theta= 27mm
Alpha = 33 degree
Phai = 33 degree
Beta = 39 degree
TL = 88mm
Sir 1 example hey sovle karege plzz
Mathematics channel par kon kon semester ka math upload hoga sir
H
Sabhi semester ka maths ayega Engineering, Polytechnic & Btech
Sir kya b tech first semester me engineering drawing hota hai, sir please tell me it's urgent
Sir here we have been given b1 dash and b1 ,,not b dash and b,,am I right sir??
Sir mathematics 2 chalaoge kya
TL=84mm
theta = 28
phi=34
alpha=47
beta=39
Given 1:11
Draw
Sir what if dist between end proje is not given
Success comes into english
Theta 27
Phi 35 °
Tl 88 mm
Theta = 27 degree
Fai = 34 degree
TL = 88 mm
Sir can you provide answers so we can check it answer is write or wrong
true length is 84 mm
theta is 29 degree
pfi is 37 degree
in my problem I got
TL=87mm
Theta=29degree
Pfi=35degree
@@yashaswinilakshmana9781 I got exact 😀👍
top view of a 75 mm long PQ measures 50mm the end P is 15mm above the H.P 50 mm. inftont of the VP .Other ends Q is 20 mm infront of vp above the H.P .draw its projections and its true angle of inclination with the referance plane?
Sir can you help me this question. Please
Thnq sir
Thanks for watching
lecture 1:18