blud its been a year, the reason my cg is down today is because of this subject, I'll be moving into my 4th semester this January, and to this date this course has given me the worst grade, i cant comprehend I've gone through tougher courses than this, but i fail to realise how i got the lowest grade in a course where you just have to just join lines,smh!
Thankyou for taking out your time and teaching on TH-cam. I'm not an engineering student but my boyfriend is. You're great help to him. He says that you teach better than faculty itself and he can understand everything easily by seeing your videos. I'm so happy that he can easily learn without any difficulty, thanks to you. I hope other students also take advantage of your teaching. Thankyou once again sir, keep up the great work!
the top view of a 75mm long line pq measures 50 mm. the end p is 15 mm above hp and 50 infront of vp . the end q is 20 mm infront of vp and above hp . draw the projection of pq and determine its inclination with the reference plane
Top view of the line measures 50 mm. The line is inclined 300 to HP. Draw its projections when its one end is in the HP and 20 mm in front of VP when it’s other end is 55 mm in front of VP
Q3. A straight line AB is inclined 45 deg to HP and 30 deg to VP. The point A is in HP and point B is in VP. The length of the straight line is 70 mm. Draw the projections of the straight line AB. Also mark its traces.
A line AB has its end A 15mm above HP and 10mm in front of VP the end B is 60mm above HP. The distance between end projectors is 50mm. The line is inclined to HP by 25°. Draw the projection and find its inclination with VP and true length of line AB.
Sir, i have the following doubts hope you clarify them as soon as possible 1: reference line should be drawing with 2h or hb pencil? 2: is there a requirement for 4h pencil in drawing? 3: points like a a dash should be written with hb or 2h pencil? 4: scales pe exam me RF aur LOS likhna jaruri hai kya?
Tikale sir appreciate your way of explanation but you never touch concept that why we have to rotate the view in order to get TL and inclination. Pls try to explain it conceptually also which will complete discussion of this topic. Pls consider it as suggestions not comment. Rest everything is fine in explanation
A line AB 90mm along is inclined to 30 degree to HP it's end A is 12 above HP end 20mm in front of VP it front view 65 degree .draw the projection of line AB and determine its inclination with HP Please solve that question Sir please
Sir I have doubt A line PQ has its end P, 10mm above H.P. and end Q,70mm in front of V.P. The F.V. of the line is inclined at 40° to the XY line. The H.T. of the line is 30mm in front of the V.P. and it's V.T. is 20mm below the H.P. Draw the projections and find its true length n true inclination with H.P. n V.P.
all bow down to the goat of engineering graphics, underrated hero of many engineering students
🐐
😅9😅H
blud its been a year, the reason my cg is down today is because of this subject, I'll be moving into my 4th semester this January, and to this date this course has given me the worst grade, i cant comprehend I've gone through tougher courses than this, but i fail to realise how i got the lowest grade in a course where you just have to just join lines,smh!
Thankyou for taking out your time and teaching on TH-cam. I'm not an engineering student but my boyfriend is. You're great help to him. He says that you teach better than faculty itself and he can understand everything easily by seeing your videos. I'm so happy that he can easily learn without any difficulty, thanks to you. I hope other students also take advantage of your teaching. Thankyou once again sir, keep up the great work!
😊😊😊
Aapko bf ki boht fikr h..
Aap loyal lagte ho....
Is it true ? ❤🎉
Hn mere gf hai
Tere ko dikkat hai @@KushalYadav-kk9rz
Exam ke ek din pahle padhne wala hu mai 😂😂.
Mai bhi😅
Mai bhi bhai
Same here
@@mdsaifkhan7871 Kisko pakaate ho be MSBTE k saare exams ho gaye abhi koi exam baaki hi nahi hai
@@lalitha4199 do u know him.@md Saif khan
Thanks a lot sir because of your videos I could prepare my engineering drawing paper and the paper went well.... God bless you and your channel.
Good...Ma sha Allah.
Please pray for the hidaya of Professor saab.
TL =75 MM
Thetha=31 degree
Phie =43 degree
Right 👍😊
76mm,30°,42°
75
30
42
Tl= 75
Q=30
¢=42
Tl =75
Theetha= 31°
Phie=43°
Listening to ur lecture one night before exam is fascinating 😅
Lol true
Same
Pass hue?
Thanks sir! You are savior for students. Otherwise, some PhD holders in Mechanical engineering are just lol!
Thank you sir aap ke vedios dekh kr me😁 pass hogya love uh..sir🥳🥳🥳❣😊
i was so afraid of engineering graphics but after watching sirs lectures i am feeling more confident
TL=75.17mm,Theta=30deg.,phi=43deg.
How?
Help me
same but that TL = 75.17 bruhhh, how that 0.17 you calculated 💀💀
S
TL=73
mm and thetha is 30 and phi is lieing between 43 and 44
Yes@@bhavana.v2270
Sir mera jo problem tha sare projection of line ka tropic dekkar solve ho gaya.Thank you sir.
Thanks for watching....
the top view of a 75mm long line pq measures 50 mm. the end p is 15 mm above hp and 50 infront of vp . the end q is 20 mm infront of vp and above hp . draw the projection of pq and determine its inclination with the reference plane
True length= 75mm
Theta = 42°
Phi = 31°
@@roshandhawale why u flirting to a fake girl account
bhai woh sab jaye bhaad mai answer kya hai?@@shreyashkale9900
Thnkq you so mach so collage me kuch nahi samjte hi aap se total samaja a jata hi love you sirrr
Sir you are really the goat of indian engineering❤❤🎉🎉
Thank you for the amazing explanation ! ✨✨
Fantastic explanation sir,
It completely cleared my topics
thank you very much sir
Sir you are very best learner for the graphic
Thank you so much sir ❤❤❤❤
Great Teaching sir
❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
Thanks and welcome
Thank you sir ji 🙏
Thanks for watching
Thankyou so much sir, we are grateful to be able to learn from you.❤️❤️
Super teaching sir I understand how to solve the problem your explanation is super sir 😊😊😂😂
Allah bless u sirr..
Thanks for these useful videos..
Love from Pakistan
Aameen.
Sr . U r great..
Sb koi like karenga
Teaching very well sir thnku so much
Mast samjhate hai sir Mai aap Ka fan Ho Gaye sir
Top view of the line measures 50 mm. The line is inclined 300 to HP. Draw its projections when its one
end is in the HP and 20 mm in front of VP when it’s other end is 55 mm in front of VP
Sri 1 vdo on this question
Sir aap bahut accha samjhate hai
Q3. A straight line AB is inclined 45 deg to HP and 30 deg to VP. The point A is in HP and point B is in VP. The length of the straight line is 70 mm. Draw the projections of the straight line AB. Also mark its traces.
Thank you so so much sir sabhi topic itne aache se aapne clear ki hai thanks so much sir
3 hour bad exam hai guys 😅
To padho na
1 hour baad 🗣️
pass hogaya?? @@realgamervishu3191
pass hogaya??
@@muneebpeerzada6699 bhai pata ni shayad hojau
Thank you sir... You have helped me so much🙏🏻
kya haal h bhai
Thank you very much Sir...
Explanation is highly Good and very Helpful vdo we can watch this anytime....
This vdo means a lot for us 🙌🙌🙌🙌
thank you very much sir g..
Thanks for watching
Thanks you sir watch this video my all doubt are clear
Wow,sir.... amezing teaching.....I am from mumbai, Maharashtra.....
Exam ke ek raat phela padhne ka ghamand h
😅😅
True length=7.5mm
Theta=30 degree
Fai=40 degree
A line AB has its end A 15mm above HP and 10mm in front of VP the end B is 60mm
above HP. The distance between end projectors is 50mm. The line is inclined to HP by
25°. Draw the projection and find its inclination with VP and true length of line AB.
My Answer is :
True Length = 75 mm
Inclination with VP = 30 degree
Inclination with HP = 45 degree
mera hp 42 aa raha hai
@@swaroopapte3440 are thoda plus minus chalta hai
@@hetpatel2992 matlab mera correct hai kya
@@swaroopapte3440 42° hee hai
Punnet superstar 💓💓
Your efforts are fantastic sir
Thank you so much sir
Ed ke best teacher aap ho
Mr perfect sir❤
Sir sayad hi ed.ka apse acha teacher ho🙏🙏
Sir aap itna accha padhate hai ki kuch doubt hi nhi rahta 👏
Fentastic video sir
Thanks for watching
Sir, i have the following doubts hope you clarify them as soon as possible
1: reference line should be drawing with 2h or hb pencil?
2: is there a requirement for 4h pencil in drawing?
3: points like a a dash should be written with hb or 2h pencil?
4: scales pe exam me RF aur LOS likhna jaruri hai kya?
Your all points are correct.
Nice explaination sir 👍 tnqu
Thanks for watching
Thita=150°
TL=750mm (75 cm)
Five angle= 224°
Before 2hour of exam😂😂
Thank you sir you are great
Sir your lecture is unbelievable sir
Dhanyawad Guruji 🙏🙏🙏🙏🙏
This lecture is more valuable
Thanks for watching
Exam se kaun kaun phle padh rahe ho like kro (Bihar Engineering University)
Great teaching 👏 sir 🙏
Aaj sham ko exam hai aur aaj subah me padh raha hu. Kya din hai 😍
TL = 75mm
Theta =30
Phi =42
Sir bhot help ho gyi aapki vajah se
U r amazing sir
you save my my marks
🙏nice sir .nice teaching.😅😅
Bhai main to exam ke 2 ghnte phle pdh rha hu
Tikale sir appreciate your way of explanation but you never touch concept that why we have to rotate the view in order to get TL and inclination. Pls try to explain it conceptually also which will complete discussion of this topic. Pls consider it as suggestions not comment. Rest everything is fine in explanation
love you sir sooo much
Thank you so much sir......
Legendary
Kon kon exame se ek din phle pd rha hai 😂. Like kro👍
Mera ans
TL : 69 mm
Theta : 33°
Phi : 44°
Theta = 30°
Phi= 42°
Same here 👍🏼
ekdm mast😁😃
A line AB 90mm along is inclined to 30 degree to HP it's end A is 12 above HP end 20mm in front of VP it front view 65 degree .draw the projection of line AB and determine its inclination with HP
Please solve that question Sir please
Sir u really really deserve many more subscribers 😭❤️❤️❤️
Titha 30°
Phay 44°
TL 76mm
TL is 75mm
Nice sir ❤️
I am so grateful to you sir . This videos helped me a lot
Ur teaching is awesome sir👍
Ek question Hai sir ke ap jo red line se line marte ho wo faint line hai kya
Osm videosssss
Thanks for watching
God for every pour students 🥺
It is very helpful 🥺.... thanks you so much sir 😍🙏🏼
Thak you sir
Thanks for watching
Thank u ☺️
Very nice video sir jii
🙏🙏🙏🙏 very nice explanation
Super sir
Sir one doubt in HP We get plan or top view it indicate by a in VP we get front view it indicate by a' then problems how it changed
Exam k 2 ghante pahle padne wala hu m
Kal ld me mid sem hE, And guess what I am here 😁, btw thx Sir for giving such efforts ❤️❤️❤️
Sir question may likha hai 10mm above the hp and in the vp. So, ham 10mm distance neechey bhi lena hogana sir
Point is in VP it means top view ka point aapko in XY lena hai.
TL = 75mm
Theta = 30 degrees
Phi = 43 degrees.
kaise nikale angles length ?
Splendid 👍
sir aapka actual classes kaha situated h?
do you live in mumbai
Thanks for watching
Legend is here🤷
THANKS 🙏🏻❤
Sir I have doubt A line PQ has its end P, 10mm above H.P. and end Q,70mm in front of V.P. The F.V. of the line is inclined at 40° to the XY line. The H.T. of the line is 30mm in front of the V.P. and it's V.T. is 20mm below the H.P. Draw the projections and find its true length n true inclination with H.P. n V.P.
Or mai ek rat phele 😅😅
True length 75mm
Theta= 30
Fi= 43