Velocity Diagram Construction

[@Rahedib]

I am beyond grateful for this video! This has simplified 5 pages of worth of gibberish into 9 mins of simplicity! Thank you!

[@shiraazwilliams9337]

I'm doing Mechanotechnics N6, this video was recommended in a study guide, all the way from South Africa Cape Town

[@arturo0727]

lol thanks a lot man, you made 3 of my teacher's lectures reduce to a 9 min video.

[@ZopteY]

sometimes I wonder why i go to class as well! ...sigh... I've learned most of what I know from whatching youtube videos, learning at my rythme. #Outdatededucationsystem

[@DewZJ1997]

It's college, so you need to learn things by yourself. No need for spoon-feeding.

[@viper6248]

Thinking about how to do different problems yourself can only happen once you understand the methodology, I.e how to construct an acceleration diagram. Doucher. Teachers so bad they just draw the thing once and expect you to understand how they constructed it.

[@HappyguyAmazingvideos]

tomorrow I have exam and I don't understand anything on the book because my professor teaches only can diagram

[@stoffel89]

This video deserves allot more credit. I must thank you for your help. You have no idea how much you helped me by making this video. It all makes sense now. Kinematics is not easy.

[@samaysoni4015]

Steve, that was beautifully explained. I never comment on syllabus clarifying videos but this particular one deserved this praise - I understood velocity diagrams perfectly through this. Thank you!

[@Magicus1]

Fu*ckin' A, mate! You're a hell of a lifesaver!
You actually EXPLAIN this madness!
Greetings from the U.S.!
:-D

[@mpumelelomdlalose8159]

Thank you!!! You just saved me from repeating a semester.
Shout out from SA

[@tokelosellosrailwaychanel3208]

Tvet or university student?

[@MrBedooman]

don't know how to thank u ,u saved me
have exams in a couple hours

[@ThingyMcThingson]

You are amazing. Thank you for doing the job my lecturer couldn't. :)

[@nirjhorkhan2479]

thank you...finally i understand this velocity diagram... love from bangladesh

[@patriciamodise7199]

hey thnx man i really leaned a lot from just a 9 min video .yeah thnx man

[@taabhishek1996]

this the first problem i understood in velocity analysis...the textbook was too complex...thanks steve...=D

[@stevetomsett]

Hi. It is Vcb that is 6.35 and this is scaled from the diagram.
Vba is the first vector and found from the rotational velocity V = omega.r
Steve

[@champion7sharma]

Thank you so much for this video Steve !! You are a saviour

[@tariqzk6964]

loved it keep doing these kinds of videos

[@gaz_52_3]

this has helped hugely thanks for explaining.

[@SakshiSujathaShriyan]

Thank you so much for this video :) it cleared out my concepts.You're really good,you should upload more such videos.

[@charlesfajemisin2201]

This was really great! Thanks it was very simple to learn and understand it now thumbs up!

[@graywhale7032]

Hi Steve, thank you for a fantastic presentation on velocity diagrams. I am currently studying in the North Island and was wondering whether you could possibly do a segment on dynamic and static balancing. For some reason you just seem to hit the nail on the head with your explanations and they are succinct and easy to get.

[@yhlim4643]

Thank u for making this so simple

[@sibivarghese4246]

sir thanks a lot for this video it helped me a lot in my exams.

[@PaixUndPace]

Oh finally, someone I can understand!

[@serderoglukf8222]

so thanks sir!! this is extremely helpful video for me!

[@mariobrenwell]

This video really helped me....thankyou very much

[@AbhishekYadav-gs8wt]

sir its really awesome..... y dnt u upload videos of corolis component of acc.....

[@TEHWENMAN]

Fantastic video! Really helpful!

[@jaisonjoshwamusic]

Really nice video....Understood completely.... :)

[@gauthamanmt]

Very useful and simplified thank you sir...

[@GDey177]

Thanks alot.. It was really of great help..

[@ImperfectionistGaming]

hi =) i may be asking a dumb question but from where did you get the 0.3 in Vba =40x0.3=12m/s. thanks

[@asian1nvasion]

Hi Steve, could you also demonstrate how to find the Inertia force at G? Thank you for the videos, they're very useful.

[@jaymali7104]

Mr. Steve thanks for sharing the vdo.

[@thestrickymoore]

thanks from Hull UK

[@anthonycollett580]

Thank you so much for this video!!!!

[@mwont]

True master! Awesome.

[@rald1691]

thanks for this vid,sir! MY textbooks sucks.

[@kishore28slash]

Sir can u upload a video on acceleration
and velocity diagram of six links bar

[@mukund631]

thanks a lot sir making easy this topic..

[@vigneshsubramanian2986]

sir ur simply awesome

[@Tee.NZ.07]

CPIT aye, nicely done.

[@shantanusaxena3431]

thanks sir !!! you cleared my direction of angular velocity doubt. ☺

[@ilanpollack703]

I was wondering if you can explain the positioning of the angels using this method
since in our course we really have no time to make sure that the ratio between the links are accurate

[@rohitlawate8482]

thank you...sir can you please upload video on corolis component of acceleration...

[@Charles-J300]

Legendary. Thank you!

[@rahulgrewal96]

you say tht we need to take the velocity perpendicular to the link. but tht velocity need to have some angle with the horizontal which u have taken approximately. if i wanna calculate that how to do it??

[@pawantofa1241]

fantastic sir

[@tsunghan_yu]

thank you this helps a lot!

[@stoffel89]

Just one question how did you calculate vca and vcb

[@muntarmadness]

How did you work out V(cb)?

[@AashiqAhmed]

can you please do vector analysis on these problems.

[@ResNRun]

0.3 is the radius of the link AB

[@Turtleboy104]

10/10 mate.

[@aniketmaraskolhe2370]

Thanks a lot sir!

[@shrivatsamelagiri4565]

sir give a lecture on cam design also

[@farhanalam6984]

thanks sir
from JNTU Hyderaba

[@danielfairuz2908]

thank you, should you come here and teach us mech students in uni of canterbury tho

[@vishu5064]

Thank you very much sir .

[@tharinduniranjan2738]

what is the angle between AB and BC?

[@junior214223]

How did you find Vca? you already had the answer, but what do you need to do exactly to find it? Pythagorean theorem..?

[@amrabdelghanyy]

you just measure the length of line ca from the velocity diagram,that will be equal to Vca and if you used a scale to draw the velocity diagram then you multiply the length of the line and the scale you used (He didn't use a scale in this example)

[@charan980]

understood well :)
thank u

[@senithmunagama5702]

Thank You very much

[@amirulariffin5566]

BIG THANKS TO U.. :D

[@creativity4095]

awesome

[@Maverickkwood]

great 💗

[@hossamqazzaz]

Thank you

[@orchidtulip1234]

why do you get 0.3 meters

[@rgt717]

thanks a lot

[@majed2488]

GOOD JOB CAN I DONATE

[@good4526]

Thanks Sir..

[@austinsimon7307]

what is Vg??

[@SakshiSujathaShriyan]

austin simon velocity at G

[@austinsimon7307]

Sakshi Shriyan, yes... I meant how is it found

[@SakshiSujathaShriyan]

austin simon The ratio between BC and BG in the configuration diagram is the same as the ratio in the velocity diagram.He found point G and joined point A to point G and found the distance if it.That's Vg

[@MohammedIbrahim-he3gz]

Thanks

[@tejasnsk]

can u help me to draw icr

[@ratneshkumar1512]

thanks sir

[@deepeshrathore]

Sir you save me :)

[@AKI-dj2yw]

thnks :)

[@prasanthksk743]

thanks sirr

[@HappyguyAmazingvideos]

tomorrow I have exam and I don't understand anything on the book because my professor teaches only can diagram

[@knack1651]

ty sir.
from g.p.mumbai

[@123dhru]

dude that was 300mm to .300m

[@varunroy2124]

You need to clear it in a different way

[@MohdKalimuddinkalim]

ok

[@legendrymukesh]

nIC eIN

[@asaiarumugam4695]

Bad communication

[@ahmedmoha1110]

Thanks a lot

[@ashishmahante6169]

Thank you..

[@youcefbacha623]

thank you