Playlist link of all Booster Classes on Electrostatics : th-cam.com/users/playlist?list... Notes of these classes will be available on Physics Galaxy mobile app. To download app. Click - bit.ly/PhysicsGalaxyApp Follow the #1 Bestseller physics galaxy book of 700+ advance illustrations. For more details about this book. Click - amzn.to/3qyIK8H Access to Physics Galaxy information & all online courses join PG telegram. Click - t.me/physicsgalaxyworld
27:58 MODIFICATION:✨✨ i this case if we give the wire certain dimenion and resistivity , then after finding final charges we can find difference between them give a time interval coz a current will flow in those wires now the total heat release will be Uf-Ui + (dQ/dt)^2.r.t ...✨✨
A doubt from my side. Sir, if two spherical chares are connected with a spring, how will the maximum and minimum separation be affected if a) spring is conducting b) spring is non-conducting c) instead of spring, a rod with a coefficient of linear expansion joins the two spheres
if the spheres are not fixed , and spring is conducting, , first they will equalize their potentials ,at the same time the charges will repel each other and do some work against the spring force , which may at the end result into the simple harmonic motion of the system... if somethings wrong please correct me
@@dhrishbhansali1136 the spring when it elongates may or may not affect it's resistance too thus impeding the amount of charge that can pass thru it maybe
Sir in PG mobile app ,the notes of 2nd booster class (electric field and potential in conductor)is uploaded in the place of 3rd booster class(electric potential and field energy)
Sir I humbly request you to bring a video on pressure, anxiety, depression... Jaise Jaise Exam Pass aa Rhe hai.. Many Students Getting worried about their paper... Please Sir It's My humble request to you 🙏.. I am studying in Aakash Institute Delhi... Please Sir You Have always Always Guide the best... 🙏🙏🙏
Please clear my doubt sir: At 32:40 in modified question of erodov , the self energy of inner shell at point A will be less than that of centre point And self energy at point B will be less than that of Centre. I am correct or not
Please sir, also guide for board exams like you did in term 1 (paper prediction and important topics) and complete ncert short notes series before physics exam
21:37 sir when spheres come closer they will experience repulsive force at their respective center of charges, and for pure rolling in case external force is their, enough friction force is necessary, but why there is no loss of energy due to this friction. Please explain sir
@@shikharmoondra7999 no , the electric field inside the due to internal charge will not be uniform. You can see it by drawing electric line of forces. Electric line of forces will be dense at one side .
Sir I have done all the READING RESOURCES posted on telegram and also covered INTRODUCTION TO MECHANICS(as suggested by you in one video). Pls suggest some more books for reading as it helps a lot..
1) sir i have completed 20% block strategy for jee 2022 should i complete it fully in this remaining 45 days or should i focus on the red strips which you have given please reply sir 🙏🙏🙏🙏
sir i have two doubts: 1)how can center of charge be used to calculate the interaction potential energy?(P.S. if center of charge is defined in a similar way as center of mass, then why is it not correct to write the gravitational potential energy by taking the distance between the center of masses of the bodies). 2) in the example at 14:00 how can we say that self energy will increase as if on on side charge density if increasing (increasing the self energy), on the other side charge density would decrease (decreasing the self energy). sir please clear these doubts.
Sir as the moving sphere comes closer to the fixed one its speed will decrease it will start rolling with forward slipping and then kinetic friction will act so how can we apply energy conservation over here
@@aayushchodhary9247 but the sphere will not roll without slipping so kinetic friction will act whose work is not zero during the course of the reaction
Sir I THINK THERE WILL BE A REPULSION between THE BODIES AMD THERE WILL BE A NEW POSITION WHERE THEY COQ WILL SHIFT BUT IT CAN BE CALCULAED BY TAKING NEW DISTANCE ...
sir i had a doubt regarding the change in self energy: how can we definitely say that self energy will increase because charges are coming together, because at the surface nearer to the external charge the charges are moving far apart, so isnt it possible that the two changes compensate each other?
No i think we can say but think slight differently,see if sphere is conducting than if we put Q1 charge on it,it will distribute uniformly throughout the sphere without doing anything kind of work .But if we have to distribute it non uniformly throughout the sphere than we must have work on it. That's why it will lead to increase in self energy.
Sir 1st derivation main jha aapne work done Nikala hai wha ek baat smjh nhi ayi ki q2 ke aane se field energy kaise badha, sphere pr net charge to aab bhi Q1 hai to net electric field jo sphere ka hoga wo Q1 ke he to karan hoga to field energy badha kaise? Self energy badha ye smjh aa gya kyu ki charge aab phale se orr pass aa gye hain to energy badhege, but field energy badhne ka logic smjh nhi aya?please help.
I don't think distance from centre of charge can be used to calculate interaction energy - potential energy depends inversely on the distance between charges, not linearly. (I'm assuming centre of charge is analogous to centre of mass here) This can be verified by taking 2 point charges equal in magnitude, and trying to calculate interaction energy of the system with a 3rd charge using distance from midpoint of the 2 charges - doesn't work.
@@physicsgalaxyworld Sir g plzzzzz tell me have u provided any solutions for the mock tests questions of jee(in telegram) I'm stuck in many questions and wanna know the solutions. Plz help!
Sir, I am Reported Tb (tuberculosis) what should I do now CBSE board from 7may and jee all are coming .... Plz suggest .... 🙏🙏🙏(sab kuch abhi hona tha!)...
प्रणाम सर,🙏🙏,आपसे बस दो ही प्रश्न है-1.आपके द्वारा बनाये गये physics galaxy revision checklist ke सभी नोट्स, क्या प्रिंट रूप मिल सकते हैं, जिन्हे हम डाउनलोड कर सके,साथ ही 2री बात सर,क्या आप अपने कांसेप्ट वीडियो को एक बार फिर हिन्दी मे बना सकते है ,पुरे वीडियो को कृपया इस पर जरुर विचार करे.pranam 🙏🙏🙏🌺
Advance tak thodha thodha karte raho, jo chapters top scoring hai unse shuru karo Jaise Modern Physics, Optics, Mechanics, Magnetism, ye kuch maximum question waale topics hai Phir jaha jaha dikkat aaye solution dekh lo, or phir 1-2 baad phir khud uss question ko dobara try karo
We know that shelf energy of a conducting shell with charge q is kq^2/2R. Here if a conducting shell is considered of radius a, its field lines go from a to infinity, it's energy kq^2/2a and for a shell of radius b and same centre, it will be kq^2/2b. Here energy loss is in metallic part, which corresponds to energy difference of first & second shells ie kq^2/2a - kq^2/2b
Playlist link of all Booster Classes on Electrostatics : th-cam.com/users/playlist?list...
Notes of these classes will be available on Physics Galaxy mobile app. To download app. Click - bit.ly/PhysicsGalaxyApp
Follow the #1 Bestseller physics galaxy book of 700+ advance illustrations. For more details about this book. Click - amzn.to/3qyIK8H
Access to Physics Galaxy information & all online courses join PG telegram. Click - t.me/physicsgalaxyworld
Physics galaxy sir isn't it for NEET 2022 as well?
Sir please increase the voice
Link not working
Playlist link
Can anyone please tell ki me apni July 2021 ki photo laga skati hu kya 2022 ke application form mey?
Never seen such a good content in half-hour thanks a lot sir
Yo bro in which year u are of dtu
27:58 MODIFICATION:✨✨ i this case if we give the wire certain dimenion and resistivity , then after finding final charges we can find difference between them give a time interval coz a current will flow in those wires now the total heat release will be Uf-Ui + (dQ/dt)^2.r.t ...✨✨
Modification 27:50 if we give this system resistivity then we can find initial instantaneous current through the wire
Anshul sir se pdhte hoo
thankyou sirr , these classes are really improving my thinking ability
Thankyou very muchh for this half an hour series.
We can see this lect even following our own routine.
Woah ! Sir finally 1 M ! Congratulations to the whole Physics galaxy team !
At 32:00 self energy at point A will increase due to which energy loss will increase. Please correct me if i am wrong🙏
A doubt from my side. Sir, if two spherical chares are connected with a spring, how will the maximum and minimum separation be affected if
a) spring is conducting
b) spring is non-conducting
c) instead of spring, a rod with a coefficient of linear expansion joins the two spheres
Very nice thinking
Will try to frame on it
if the spheres are not fixed , and spring is conducting, , first they will equalize their potentials ,at the same time the charges will repel each other and do some work against the spring force , which may at the end result into the simple harmonic motion of the system...
if somethings wrong please correct me
i think in the rod case ,the rod will heat up due to the initial current flow and expand but it will be very very miniscule
@@dhrishbhansali1136 the spring when it elongates may or may not affect it's resistance too thus impeding the amount of charge that can pass thru it maybe
Sir in PG mobile app ,the notes of 2nd booster class (electric field and potential in conductor)is uploaded in the place of 3rd booster class(electric potential and field energy)
ThankYou Sir
Sir I humbly request you to bring a video on pressure, anxiety, depression... Jaise Jaise Exam Pass aa Rhe hai.. Many Students Getting worried about their paper... Please Sir It's My humble request to you 🙏..
I am studying in Aakash Institute Delhi... Please Sir
You Have always Always Guide the best... 🙏🙏🙏
Thanku sirr
Thnk u sir mai apke advance illustration ke vedio dekh muje bhut benifit hua hai
Thanku so much
Sir sare concept pe kuchh question telegram pe dal dete to bahut jyada concept build hota 🙏🙏🙏🙏🙏❤️❤️❤️❤️❤️❤️🙏🙏
Please clear my doubt sir:
At 32:40 in modified question of erodov , the self energy of inner shell at point A will be less than that of centre point
And self energy at point B will be less than that of Centre.
I am correct or not
Please sir, also guide for board exams like you did in term 1 (paper prediction and important topics) and complete ncert short notes series before physics exam
Also available
Plz sir
21:37 sir when spheres come closer they will experience repulsive force at their respective center of charges, and for pure rolling in case external force is their, enough friction force is necessary, but why there is no loss of energy due to this friction. Please explain sir
now this is interesting
Sir , in last case heat loss will be more because self energy due to inner surface of shell will increase due to non -uniform charge distribution.
true but i was concerned whether the field inside due to the internal charge will uniform anymore.... as the charge is placed a little offside.
@@shikharmoondra7999 no , the electric field inside the due to internal charge will not be uniform.
You can see it by drawing electric line of forces. Electric line of forces will be dense at one side .
Yes.
@@aaryantiwari9292 Yes.
@@aaryantiwari9292 Yeah you are right, there will be induced EF if the charges are bought close enough, inside the conductor it will remain zero
Sir plzz start live class for neet students
Sir I have done all the READING RESOURCES posted on telegram and also covered INTRODUCTION TO MECHANICS(as suggested by you in one video). Pls suggest some more books for reading as it helps a lot..
Introduction to mechanics by Arnold?
@@HarshitKumar-up1im Daniel Kleppner and Robert Kolenkow
@@FreeMe64O 2022
700+ adv illustration krlo bhout hai
Thank uuuuuuuuu very much..
18:30 sir self energy bina integtrate kre bhi nikal skte hain.
It proves that self energy is equal to field energy for a isolated sphere
Thank you sir
Sir kya maths aur chemistry ki wo series ab aayi hai 🤔
1) sir i have completed 20% block strategy for jee 2022 should i complete it fully in this remaining 45 days or should i focus on the red strips which you have given
please reply sir 🙏🙏🙏🙏
sir i have two doubts:
1)how can center of charge be used to calculate the interaction potential energy?(P.S. if center of charge is defined in a similar way as center of mass, then why is it not correct to write the gravitational potential energy by taking the distance between the center of masses of the bodies).
2) in the example at 14:00 how can we say that self energy will increase as if on on side charge density if increasing (increasing the self energy), on the other side charge density would decrease (decreasing the self energy).
sir please clear these doubts.
If charge distrubutes non uniformly then Self energy always decrease,in other words,Self energy is minimum in uniform distribution
Sir as the moving sphere comes closer to the fixed one its speed will decrease it will start rolling with forward slipping and then kinetic friction will act so how can we apply energy conservation over here
While rolling only static friction acts,and work done by static friction is zero and hence energy conservation can be applied
@@aayushchodhary9247 but the sphere will not roll without slipping so kinetic friction will act whose work is not zero during the course of the reaction
Motion**
@@chiraggarg5538 In rolling without slipping static friction acts not kinetic friction
Sir I THINK THERE WILL BE A REPULSION between THE BODIES AMD THERE WILL BE A NEW POSITION WHERE THEY COQ WILL SHIFT BUT IT CAN BE CALCULAED BY TAKING NEW DISTANCE ...
simply awestruck :)
Sir earthing of conductors?
sir i had a doubt regarding the change in self energy: how can we definitely say that self energy will increase because charges are coming together, because at the surface nearer to the external charge the charges are moving far apart, so isnt it possible that the two changes compensate each other?
No i think we can say but think slight differently,see if sphere is conducting than if we put Q1 charge on it,it will distribute uniformly throughout the sphere without doing anything kind of work .But if we have to distribute it non uniformly throughout the sphere than we must have work on it. That's why it will lead to increase in self energy.
Is booster checkist required for jee mains please tell
SIR LAST SECOND QUESTION ME SWITCHING KE BAAD CHARGES UNIFORMELY DISTRIBUTE HO JAYENGE (Uf will change or not)..PLS ANS ??
Sir, Now please release a new block strategy as JAB has taken the authority of JEE now
Sir 1st derivation main jha aapne work done Nikala hai wha ek baat smjh nhi ayi ki q2 ke aane se field energy kaise badha, sphere pr net charge to aab bhi Q1 hai to net electric field jo sphere ka hoga wo Q1 ke he to karan hoga to field energy badha kaise?
Self energy badha ye smjh aa gya kyu ki charge aab phale se orr pass aa gye hain to energy badhege, but field energy badhne ka logic smjh nhi aya?please help.
I don't think distance from centre of charge can be used to calculate interaction energy - potential energy depends inversely on the distance between charges, not linearly. (I'm assuming centre of charge is analogous to centre of mass here)
This can be verified by taking 2 point charges equal in magnitude, and trying to calculate interaction energy of the system with a 3rd charge using distance from midpoint of the 2 charges - doesn't work.
When centre of charge is calculated for energy then what you've written would have been already considered in its calculation so it can be used !
@@physicsgalaxyworld Sir g plzzzzz tell me have u provided any solutions for the mock tests questions of jee(in telegram) I'm stuck in many questions and wanna know the solutions. Plz help!
Sir could you give the solution of y the last class last q was wrong ???
Please make something for JEE MAINS
Sir Please Classes Fast Pace mai hi lijiye 🙏🙏
Sir, I am Reported Tb (tuberculosis) what should I do now CBSE board from 7may and jee all are coming ....
Plz suggest ....
🙏🙏🙏(sab kuch abhi hona tha!)...
Sir plz provide of this session
प्रणाम सर,🙏🙏,आपसे बस दो ही प्रश्न है-1.आपके द्वारा बनाये गये physics galaxy revision checklist ke सभी नोट्स, क्या प्रिंट रूप मिल सकते हैं, जिन्हे हम डाउनलोड कर सके,साथ ही 2री बात सर,क्या आप अपने कांसेप्ट वीडियो को एक बार फिर हिन्दी मे बना सकते है ,पुरे वीडियो को कृपया इस पर जरुर विचार करे.pranam 🙏🙏🙏🌺
Notes you can download by yourself
Sir, please provide Full Syllabus Neet Test Series 🙏
Sir what is the way to do advance illustrations book.
Sir, has already made a video. Just read the solutions and after one day without seeing try to do by yourself, if you stuck see the solution
Advance tak thodha thodha karte raho, jo chapters top scoring hai unse shuru karo
Jaise Modern Physics, Optics, Mechanics, Magnetism, ye kuch maximum question waale topics hai
Phir jaha jaha dikkat aaye solution dekh lo, or phir 1-2 baad phir khud uss question ko dobara try karo
@@viraj1304 Arre tum insp channel pe bhi ho na 🔥🔥
@@dreamyadav1598 yes🙂✌️
Tumhe bhi dekha hai
Sir please just like your physics revision checklist
Provide same revision checklist for chemistry and math too for jee mains
Please
Physics galaxy channel is mainly concern with Physics only. Thanks for your love towards PG
No , sir had announced that he is comming with chemistry and math too 🥺
next class kb hai..??
sir telegram test series ke jo questions nhi solve ho rhe unka solution kaha milega.
"Dear User,
Which class you wish to join? Video lectures are available on PG app as well as on PG site, you can follow them."
Can anyone please tell ki me apni July 2021 ki photo laga skati hu kya 2022 ke application form mey?
Please take a session on Gauss Law
coming soon
Sir help me for jee 2022
i did dont understand how sir calculated the energy loss in last question. Can someone plz help me.
We know that shelf energy of a conducting shell with charge q is kq^2/2R. Here if a conducting shell is considered of radius a, its field lines go from a to infinity, it's energy kq^2/2a and for a shell of radius b and same centre, it will be kq^2/2b. Here energy loss is in metallic part, which corresponds to energy difference of first & second shells ie kq^2/2a - kq^2/2b
@@shefalisharma1630 okay, thanku so much.
Sir mechanics ka hoga
Sir jee advance 2022 full complete
No
laal dil
Teach in English sir
Sir plz thoda hindi me samjhaya kariye aap english ka use jyada krte hai