TRICKIER SQL INTERVIEW question based on SYMMETRIC PAIRS

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  • เผยแพร่เมื่อ 5 ต.ค. 2024
  • **********************************************************************
    Complete SQL Query Script for the video is available at:
    houseoftechcon...
    In the Video we are going to discuss the step by step solution of SQL question asked in technical interview
    This video covers the concept of UNION, GROUP BY, WHERE, INNER JOIN, HAVING and ORDER BY clause in SQL.
    **********************************************************************
    The video is the twenty first part of series for SQL Interview and Answers.
    Entire series has step by step solution for building queries for scenarios that are asked in technical interviews.
    Previous Video Links :
    Scenario Microsoft: • Microsoft SQL Intervie...
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    **********************************************************************
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ความคิดเห็น • 11

  • @thehouseofconcepts
    @thehouseofconcepts  ปีที่แล้ว

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  • @Anashwar-p3w
    @Anashwar-p3w หลายเดือนก่อน +1

    one of the finest ans i have ever encountered yet .thanks,if someone ask you how much clear understanding of sql do you have just show them this video ,

    • @thehouseofconcepts
      @thehouseofconcepts  หลายเดือนก่อน

      Thank you so much for your kind words…please keep supporting the channel🙏🏼

  • @sandipansarkar9211
    @sandipansarkar9211 9 หลายเดือนก่อน +1

    Finished watching

  • @Datapassenger_prashant
    @Datapassenger_prashant 5 หลายเดือนก่อน

    Very difficult n tricky

  • @souvik0077
    @souvik0077 4 หลายเดือนก่อน

    with cte as(
    select *,row_number() over(order by x,y) as r from functions)
    select c.x,c.y from
    cte c inner join cte ct on
    c.x=ct.y and c.y=ct.x and c.rct.r and c.x

  • @nileshpatil4081
    @nileshpatil4081 ปีที่แล้ว +1

    select distinct a.x,a.y from
    (select row_number() over (order by f.x) rnb,f.x,f.y from FunctionDetails f) a
    inner join
    (select row_number() over (order by f1.x) rnb, f1.x,f1.y from FunctionDetails f1)b
    on concat(a.x,a.y)=concat(b.y,b.x)
    and a.rnbb.rnb and a.x

  • @playwithvihaan7601
    @playwithvihaan7601 ปีที่แล้ว +1

    Nice job. More of these please.

    • @thehouseofconcepts
      @thehouseofconcepts  ปีที่แล้ว +1

      Thank you! Please stay tuned for more content like this…