Simply, for independent events we have two events derived from two different trials (two different events like tossing coin and rolling a dice, tossing two coins). Therefore, probability of occurrence of one does not affect the probability of occurrence of other. In case of mutually exclusive events, we have also two events (may be more than two) but difference is that the events derived from the same trial (in rolling a dice, facing even numbers & odd numbers are mutually exclusive).
Yes please, the tutor used combination so that is how it will be. For question A, you can solve it by saying 6/15 x 5/14 x 4/13 and you will get the same answer the tutor got using combination. Hope we have answered your question and hope you get it? Thank you. Feel free to ask more questions.
Out of 5 mathematicians and 7 physists, a committee of 2 mathematicians and 3 physists is to be formed. In how many ways can this be done if 1) any mathematicians and any physists can be included. 2) one particular physists must be on the committee. 3) two particular mathematicians cannot be on
a) 5C2 x 7C3 = 10 x 35 = 350 ways b) Since one particular Physician must be on the committee. 5C2 x 6C2 =10 x 15 = 150 ways c) 3C2 x 7C3 = 3 x 35 = 105 ways
In a question like the one used in computing the question 21, no need to do that. Also, it’s not always that you multiply P(A) and P(B) to get P(AnB). That’s only used for independent events when you are solving probability question.
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You can't imagine how much this gas helped me the first 5 minutes alone has changed my perception of probability keep it up my guy
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Please can you show us how you computed for the factorial?
Input the digit then you press the shift key, you then press the key under the mode and then equal to
please teach the factorial formulae again
I don't really get you please.
5 factorial means 5x4x3x2x1
7 factorial means 7x6x5x4x3x2x1
Hope this helps
Thanks alot
Pls for the questions with diamonds and king…hope the card would be provided in exams
No please. You have to know how the card is.
Actually Ghanaian schools don't really give questions on this card things.☺
Please whenan event is mutually exclusive is it independent too?
Simply, for independent events we have two events derived from two different trials (two
different events like tossing coin and rolling a dice, tossing two coins). Therefore,
probability of occurrence of one does not affect the probability of occurrence of other. In
case of mutually exclusive events, we have also two events (may be more than two) but
difference is that the events derived from the same trial (in rolling a dice, facing even
numbers & odd numbers are mutually exclusive).
Sir, 1:13:34 in (c) "ordering" ignored?
in this question balls are ordered so isn't that an dependent event?
Yes please, the tutor used combination so that is how it will be. For question A, you can solve it by saying 6/15 x 5/14 x 4/13 and you will get the same answer the tutor got using combination.
Hope we have answered your question and hope you get it?
Thank you.
Feel free to ask more questions.
Out of 5 mathematicians and 7 physists, a committee of 2 mathematicians and 3 physists is to be formed. In how many ways can this be done if
1) any mathematicians and any physists can be included.
2) one particular physists must be on the committee.
3) two particular mathematicians cannot be on
Kindly check our community post for the solution.
@@PhilosMasterClass can't find the solution. Kindly direct me please
a) 5C2 x 7C3
= 10 x 35
= 350 ways
b) Since one particular Physician must be on the committee.
5C2 x 6C2
=10 x 15
= 150 ways
c) 3C2 x 7C3
= 3 x 35
= 105 ways
Please help. Thanks in advance
Please the question 21… y didn’t we multiply Since it is intersection
Ok can you help explain
In a question like the one used in computing the question 21, no need to do that.
Also, it’s not always that you multiply P(A) and P(B) to get P(AnB).
That’s only used for independent events when you are solving probability question.