Your channel is underrated. Screw youtube for not showing the benefits of your channel. By the way, can you do research on mislavskij transformer? Or inductor-capacitor transformer. Additionally, can you do capacitor-inductor and capacitor-capacitor transformer? Check mislavskij transformer for the basics.
I wish you had more experimental evidence to support this theory. By the way your experiments are wonderfull. But to me there are still many options open. For example, what is this contact zone exactly? Why do the not create a contact zone? Because no current flows? But why does the current not flow in the fixed horizontal bars? The difference between the horizontal co-rotating bars and the contact brushes could be: 1 if there is a speed differential with the disc or not. 2 rotation speed differential. 3 difference in electrostatic potential. 4 difference in work dissipation (the voltmeter dissipates energy, the brushes have sparks and emit more stuff due to inefficiency of contact). 5 on/off sliding contact vs. continuous contact. 6 permanent influence of earth magnetic field or gravity field on the brushes vs. rotating influence on the bars. I guess current flows in the brushes because they dissipate the energy more effectively (after which you get the contact zones) and the horizontal bars are too efficient, they equalize and balance the energy too much.
I believe brushes function as ether "perturbators" gaining either +spin or -spin, where + can have 2 spins and - can have 2 spins. Wimshurst machine makes 2 different spins meet eachother - as they are both of the same "polarity" it must be the spin difference that makes the potential visible. Also, you had more views and it appears you are getting shilled by "loosers that be"
It's not the brushes which does anything, its the fact that the brushes produce a closed loop for the current to flow. So, its the fact that there are a closed conductive loop between the axle and the disk which makes the current flow?
Your assumption that a spinning Faraday disk set-up produces a current on its own is a theory that has never been proven. We did the test for that in video Exx-013 and there was no current.
@@scienceexxience What about the case of mercury (Hg) contact ? Is there movments in this liquid metal inducing current too ? A little bit of fluids mechanic will be needed. I m afraid your experiments are not exhaustive enough to build a fully demostrated theory but it's a good starting. In particular you should investigate why such micro-movments of the brush in the magnetic field generate so low voltage and so much intensity and, in case of mercury, wich fluid movment patern have similar properties ? Keep on working, best regards ;-)
@@scienceexxience why don't check if there is current flowing in the external circuit arranged parallel, coplanar and coaxial with the rotating magnet and disk ?, in this case I would expect no tension between periphery and axle since no magnetic field flux can change across the external circuit (which is positioned axially and coplanar with the axle) . If there is still tension , then we have a big anomaly
Your channel is underrated. Screw youtube for not showing the benefits of your channel. By the way, can you do research on mislavskij transformer? Or inductor-capacitor transformer. Additionally, can you do capacitor-inductor and capacitor-capacitor transformer? Check mislavskij transformer for the basics.
I wish you had more experimental evidence to support this theory. By the way your experiments are wonderfull. But to me there are still many options open. For example, what is this contact zone exactly? Why do the not create a contact zone? Because no current flows? But why does the current not flow in the fixed horizontal bars? The difference between the horizontal co-rotating bars and the contact brushes could be:
1 if there is a speed differential with the disc or not.
2 rotation speed differential.
3 difference in electrostatic potential.
4 difference in work dissipation (the voltmeter dissipates energy, the brushes have sparks and emit more stuff due to inefficiency of contact).
5 on/off sliding contact vs. continuous contact.
6 permanent influence of earth magnetic field or gravity field on the brushes vs. rotating influence on the bars.
I guess current flows in the brushes because they dissipate the energy more effectively (after which you get the contact zones) and the horizontal bars are too efficient, they equalize and balance the energy too much.
Thanks these questions. I will try to respond in the coming days, when I have more time.
I believe brushes function as ether "perturbators" gaining either +spin or -spin, where + can have 2 spins and - can have 2 spins.
Wimshurst machine makes 2 different spins meet eachother - as they are both of the same "polarity" it must be the spin difference that makes the potential visible.
Also, you had more views and it appears you are getting shilled by "loosers that be"
It's not the brushes which does anything, its the fact that the brushes produce a closed loop for the current to flow. So, its the fact that there are a closed conductive loop between the axle and the disk which makes the current flow?
Your assumption that a spinning Faraday disk set-up produces a current on its own is a theory that has never been proven. We did the test for that in video Exx-013 and there was no current.
@@scienceexxience What about the case of mercury (Hg) contact ? Is there movments in this liquid metal inducing current too ? A little bit of fluids mechanic will be needed. I m afraid your experiments are not exhaustive enough to build a fully demostrated theory but it's a good starting. In particular you should investigate why such micro-movments of the brush in the magnetic field generate so low voltage and so much intensity and, in case of mercury, wich fluid movment patern have similar properties ? Keep on working, best regards ;-)
@@scienceexxience why don't check if there is current flowing in the external circuit arranged parallel, coplanar and coaxial with the rotating magnet and disk ?, in this case I would expect no tension between periphery and axle since no magnetic field flux can change across the external circuit (which is positioned axially and coplanar with the axle) . If there is still tension , then we have a big anomaly